/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 In Exercises 25-36, solve each s... [FREE SOLUTION] | 91Ó°ÊÓ

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In Exercises 25-36, solve each system by the addition method. Be sure to check all proposed solutions. \(\left\\{\begin{array}{l}x+y=1 \\ x-y=3\end{array}\right.\)

Short Answer

Expert verified
The solution to the system of equations is \(x=2, y=-1\).

Step by step solution

01

Add Equations

Add the two equations in the system, which are \(x + y = 1\) and \(x - y = 3\). Adding them yields \(2x= 4\).
02

Solve for x

Solve for x in the equation \(2x= 4\). Dividing both sides by 2 gives \(x=2\).
03

Substitute x value

Substitute \(x=2\) back into one of the original equations, for instance \(x+y=1\). Substituting yields \(2+y=1\).
04

Solve for y

Solve for y in the equation \(2+y=1\). Subtraction 2 from both sides gives \(y=-1\).
05

Check Solution

Check the solution \((x=2, y=-1)\) by substituting these values into both original equations. For \(x+y=1\), substituting yields \(2-1=1\) which is true. For \(x-y=3\), substituting gives \(2-(-1) = 3\) which is also true.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solving Systems of Equations
Understanding how to solve systems of equations is foundational in algebra. A system of equations consists of two or more equations with the same set of variables. The goal is to find a set of values that satisfy all equations in the system simultaneously. There are several methods to solve these systems, including graphing the equations, using substitution, the addition (or elimination) method, and matrix operations.

Here, we focus on the addition method, which involves adding or subtracting equations to eliminate one variable, making it easier to solve for the other. The addition method is particularly useful when the coefficients of one of the variables are opposites because adding the equations directly eliminates that variable.
Algebraic Method
The algebraic method refers to solving systems of equations using algebraic operations to manipulate the equations. Unlike graphical solutions, which involve sketching lines or curves on a plane, the algebraic approach is precise and follows a set of steps that lead to the exact solution.

For instance, in the given exercise, the addition method is an algebraic technique where equations are combined to eliminate a variable. To do this effectively, it's essential to manipulate the equations if they're not already set up for easy elimination. Beyond addition, you may need to multiply or divide terms to align the variables for elimination. This method is foundational in algebra and is applied across various fields of mathematics and science.
Verification of Solutions
After finding the values for the variables in a system of equations, it's critical to verify that the solutions are correct. Verification ensures your solution actually satisfies each original equation. To verify, plug the values back into each given equation and check if the left side equals the right side.

In the provided exercise, after determining that the proposed solution is \(x=2, y=-1\), you would replace \(x\) and \(y\) in each initial equation. If both equations balance with these values, then you can confidently claim that the solution is correct. This step, while it may seem trivial, is crucial as it validates the hard work done in the problem-solving process.
Substitution Method
While the addition method works efficiently for the given exercise, another standard method for solving systems of equations is the substitution method. This approach involves solving one of the equations for one variable in terms of the other and then substituting this expression into the other equation. It's a step-by-step process where the ultimate goal is to isolate one variable and solve for it.

Taking the example \(x+y=1\), if you solved for \(y\), you would get \(y=1-x\). You would then substitute \(1-x\) for \(y\) in the other equation \(x-y=3\), leading to \(x-(1-x)=3\). Although the substitution method wasn't necessary for the given exercise, it's essential to be versatile and familiar with different techniques to solve various systems of equations you may encounter.

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Most popular questions from this chapter

You are about to take a test that contains computation problems worth 6 points each and word problems worth 10 points each. You can do a computation problem in 2 minutes and a word problem in 4 minutes. You have 40 minutes to take the test and may answer no more than 12 problems. Assuming you answer all the problems attempted correctly, how many of each type of problem must you answer to maximize your score? What is the maximum score?

a. Create a scatter plot for the data in each table. b. Use the shape of the scatter plot to determine if the data are best modeled by a linear function, an exponential function, a logarithmic function, or a quadratic function. $$ \begin{array}{|c|r|} \hline \boldsymbol{x} & \boldsymbol{y} \\ \hline 0 & 4 \\ \hline 1 & 5 \\ \hline 2 & 7 \\ \hline 3 & 11 \\ \hline 4 & 19 \\ \hline \end{array} $$

Without graphing, Determine if each system has no solution or infinitely many solutions. \(\left\\{\begin{array}{l}6 x-y \leq 24 \\ 6 x-y>24\end{array}\right.\)

Describe the shape of a scatter plot that suggests modeling the data with an exponential function.

A theater is presenting a program on drinking and driving for students and their parents. The proceeds will be donated to a local alcohol information center. Admission is \(\$ 2\) for parents and \(\$ 1\) for students. However, the situation has two constraints: The theater can hold no more than 150 people and every two parents must bring at least one student. How many parents and students should attend to raise the maximum amount of money?

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