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91Ó°ÊÓ

Suppose that the pairwise comparison method is used to determine the winner in an election. If there are nine candidates, how many comparisons must be made?

Short Answer

Expert verified
The number of comparisons to be made is 36.

Step by step solution

01

Understanding pairwise comparison

In a pairwise comparison, each candidate is compared with every other candidate. So, if there are nine candidates, each candidate is compared with eight others.
02

Applying the formula for combinations

In a scenario where order of selection doesn't matter (like in pairwise comparison), combinations are used. The formula for combination is \( C(n, r) = \frac{n!}{r! (n-r)!}\), where \(n\) is the total number of items, and \(r\) is the items to choose. In this case \(n=9\) (candidates) and \(r=2\) (since 2 candidates are compared at a time).
03

Computing the number of combinations

Substituting the values into the formula, we get \(C(9, 2) = \frac{9!}{2!(9-2)!} = 36\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinatorics
Combinatorics is a fascinating branch of mathematics focusing on counting, arrangement, and combination of objects. It allows us to determine how various items can be grouped or ordered. In election scenarios, especially when considering pairwise comparisons among candidates, combinatorics helps calculate the number of possible match-ups. Understandably, for nine candidates, it's important to see how many unique pairs we can generate. This grouping forms the basis for analyzing elections where the order or the position of candidates is insignificant, only their presence together as a pair matters. The fundamental principle here is that the number of ways to choose two candidates from a group of nine is given by combinations, not permutations, which consider order.
Election Methods
Election methods are strategies or systems used to select candidates for a position or to allocate votes. The pairwise comparison method, a common election method, ranks candidates by comparing each pairian match separately. The winner of a pair is then judged based on who often comes out ahead in these one-on-one comparisons, similar to a round-robin tournament. It's crucial in ensuring that each candidate's strength and voter preference can be expressed in a systematic and balanced way. This method is particularly useful in multi-member elections or scenarios where there are more than two choices to evaluate.
Candidate Comparison
Candidate comparison is a process in elections to shed light on the relative standings of candidates. In the pairwise comparison method, each candidate is matched directly with every other candidate. This means for nine candidates, each will face off against the other eight candidates separately. The comparisons serve the purpose of highlighting the preference orders, helping determine which candidate has broader support or appeal. By quantifying these comparisons, decision makers or election bodies can ensure fairness and express the voters' collective voice more accurately. Importantly, the validity and equity of candidate comparison are core to maintaining trust in the election process.
Combinations Formula
The combinations formula plays a pivotal role in calculating the number of ways to select items from a group, where order does not matter. It's denoted as \(C(n, r) = \frac{n!}{r!(n-r)!}\), helping to systemize pair selections without regard for the order they are drawn. When applied to elections with nine candidates and pairwise comparisons, the formula shows how to select two candidates out of nine. Here, \(n\) is 9 and \(r\) is 2, yielding \(C(9, 2) = 36\). This calculation signifies there are 36 unique comparisons to be made, each reflecting a distinct pair showcasing competitive analysis. Utilizing this formula is essential in understanding and demolishing complex combinatorial scenarios, especially prominent in decision-making processes like elections.

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Most popular questions from this chapter

A small country is composed of five states, \(A, B, C, D\), and \(E\). The population of each state is given in the following table. Congress will have 57 seats, divided among the five states according to their respective populations. Use Jefferson's method with \(d=32,920\) to apportion the 57 congressional seats. $$ \begin{array}{|l|c|c|c|c|c|} \hline \text { State } & \text { A } & \text { B } & \text { C } & \text { D } & \text { E } \\ \hline \text { Population } & 126,316 & 196,492 & 425,264 & 526,664 & 725,264 \\\ \hline \end{array} $$

How are modified quotas rounded using Webster's method?

Members of the Student Activity Committee at a college are considering three film directors to speak at a campus arts festival: Ron Howard (H), Spike Lee (L), and Steven Spielberg (S). Committee members vote for their preferred speaker. The winner is to be selected by the pairwise comparison method. The preference table for the election is shown. $$ \begin{array}{|l|c|c|c|} \hline \text { Number of Votes } & \mathbf{1 0} & \mathbf{8} & \mathbf{5} \\ \hline \text { First Choice } & \text { H } & \text { L } & \text { S } \\ \hline \text { Second Choice } & \text { S } & \text { S } & \text { L } \\ \hline \text { Third Choice } & \text { L } & \text { H } & \text { H } \\ \hline \end{array} $$ a. Using the pairwise comparison method, who is selected as the speaker? b. Prior to the announcement of the speaker, Ron Howard informs the committee that he will not be able to participate due to other commitments. Construct a new preference table for the election with \(\mathrm{H}\) eliminated. Using the new table and the pairwise comparison method, who is selected as the speaker? c. Is the irrelevant alternatives criterion satisfied? Explain your answer.

In Exercises 11-18, the preference table for an election is given. Use the table to answer the questions that follow it. $$ \begin{array}{|l|c|c|c|c|} \hline \text { Number of Votes } & \mathbf{2 0} & \mathbf{1 6} & \mathbf{1 0} & \mathbf{4} \\ \hline \text { First Choice } & \text { D } & \text { C } & \text { C } & \text { A } \\ \hline \text { Second Choice } & \text { A } & \text { A } & \text { B } & \text { B } \\ \hline \text { Third Choice } & \text { B } & \text { B } & \text { D } & \text { D } \\ \hline \text { Fourth Choice } & \text { C } & \text { D } & \text { A } & \text { C } \\ \hline \end{array} $$ a. Using the Borda count method, who is the winner? b. Is the majority criterion satisfied? Explain your answer.

A university is composed of five schools. The enrollment in each school is given in the following table. $$ \begin{array}{|l|c|c|c|c|c|} \hline \text { School } & \begin{array}{c} \text { Human- } \\ \text { ities } \end{array} & \begin{array}{c} \text { Social } \\ \text { Science } \end{array} & \begin{array}{c} \text { Engi- } \\ \text { neering } \end{array} & \text { Business } & \begin{array}{c} \text { Educa- } \\ \text { tion } \end{array} \\ \hline \text { Enrollment } & 1050 & 1410 & 1830 & 2540 & 3580 \\ \hline \end{array} $$ There are 300 new computers to be apportioned among the five schools according to their respective enrollments. Use Hamilton's method to find each school's apportionment of computers.

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