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If \(\phi\) is convex on \((a, b)\) and \(\psi\) is convex and nondecreasing on the range of \(\phi\), show that the function \(\psi[\phi(x)]\) is convex on \((a, b)\).

Short Answer

Expert verified
The function \( \psi[\phi(x)] \) is convex on \((a, b)\) due to the convexity of both \( \phi \) and \( \psi \).

Step by step solution

01

Understanding Convexity

A function \( f \) is convex on an interval if for any two points \( x_1, x_2 \) in the interval and any \( \lambda \in [0,1] \), the following holds: \[ f(\lambda x_1 + (1 - \lambda) x_2) \leq \lambda f(x_1) + (1 - \lambda) f(x_2). \]
02

Initial Setup

We have two functions: \( \phi \), convex on \((a, b)\), and \( \psi \), convex and nondecreasing on the range of \( \phi \). We need to show \( \psi[\phi(x)] \) is convex on \((a, b)\).
03

Using Convexity of \( \phi \) and \( \psi \)

Since \( \phi \) is convex, for any \( x_1, x_2 \in (a, b) \) and \( \lambda \in [0,1] \), we have:\[ \phi(\lambda x_1 + (1 - \lambda) x_2) \leq \lambda \phi(x_1) + (1-\lambda) \phi(x_2). \]Since \( \psi \) is convex on the range of \( \phi \) and nondecreasing, applying \( \psi \) can be done while maintaining inequality. Thus, we have:\[ \psi(\phi(\lambda x_1 + (1 - \lambda) x_2)) \leq \psi(\lambda \phi(x_1) + (1 - \lambda) \phi(x_2)). \]
04

Applying Convexity of \( \psi \)

Since \( \psi \) is convex on the range of \( \phi \), it preserves the inequality:\[ \psi(\lambda \phi(x_1) + (1-\lambda) \phi(x_2)) \leq \lambda \psi(\phi(x_1)) + (1-\lambda) \psi(\phi(x_2)). \]
05

Conclusion

Combining the inequalities from the previous steps, we conclude:\[ \psi(\phi(\lambda x_1 + (1 - \lambda) x_2)) \leq \psi(\lambda \phi(x_1) + (1-\lambda) \phi(x_2)) \leq \lambda \psi(\phi(x_1)) + (1-\lambda) \psi(\phi(x_2)). \]Thus, \( \psi[\phi(x)] \) is convex on \((a, b)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convex Functions
Convex functions play a crucial role in understanding various mathematical and optimization problems. A function is said to be convex on an interval if, intuitively, its graph forms a 'bowl-like' shape on that interval. This means that, for any two points along the curve, the line segment connecting them lies above or on the graph of the function itself.

The formal definition revolves around the idea of maintaining an inequality using a specific weighting between any two points. Specifically, a function \( f \) is convex on an interval \([a, b]\) if, for any points \( x_1, x_2 \) in the interval and any \( \lambda \in [0,1] \), the relationship holds:
  • \[ f(\lambda x_1 + (1 - \lambda) x_2) \leq \lambda f(x_1) + (1 - \lambda) f(x_2). \]
This inequality essentially states that the weighted average of the function values at \( x_1 \) and \( x_2 \) is greater than or equal to the function value at any point between \( x_1 \) and \( x_2 \). Convex functions are foundational in optimization because they ensure local minima are global minima, providing significant advantages in solving optimization problems.
Function Composition
Function composition is a powerful concept that involves applying one function to the result of another. Imagine you have two functions, \( \phi \) and \( \psi \). When you compose these two functions, denoted as \( \psi[\phi(x)] \), you apply function \( \phi \) first to \( x \), and then apply \( \psi \) to the result of \( \phi(x) \).

Understanding how composition affects properties such as convexity is important in mathematical analysis. The exercise demonstrates this by showing how combining two convex functions in a composition can result in a new convex function. If both \( \phi \) and \( \psi \) possess convexity, and \( \psi \) is nondecreasing, the composite function \( \psi[\phi(x)] \) maintains this property over a specific interval. This is achieved by systematically applying definitions and inequalities associated with both functions.

Thus, function composition not only helps in constructing complex functions from simpler ones but also in preserving certain desired traits like convexity, given certain preconditions.
Inequality Properties
Inequality properties are fundamental in proving various characteristics of functions. In the context of convex functions, inequalities are used extensively to establish and verify convexity. The hallmark of a convex function, as explored in previous sections, relies on maintaining a specific inequality between points on its graph.

When handling composite functions like \( \psi[\phi(x)] \), inequalities help in understanding how the convexity of each function contributes to the overall convexity of the composition. If \( \phi \) is convex and \( \psi \) is both convex and nondecreasing on the range of \( \phi \), inequality properties ensure that:
  • \[ \psi(\phi(\lambda x_1 + (1 - \lambda) x_2)) \leq \psi(\lambda \phi(x_1) + (1 - \lambda) \phi(x_2)) \]
By further leveraging the convexity of \( \psi \), the final step involves ensuring:
  • \[ \psi(\lambda \phi(x_1) + (1-\lambda) \phi(x_2)) \leq \lambda \psi(\phi(x_1)) + (1-\lambda) \psi(\phi(x_2)). \]
Thus, the entire inequality chain concludes the convexity of the entire composite function, underscoring the strength and utility of inequality properties in mathematical proofs.

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Most popular questions from this chapter

Variance stabilizing transformations are transformations for which the resulting statistic has an asymptotic variance that is independent of the parameters of interest. For each of the following cases, find the asymptotic distribution of the transformed statistic and show that it is variance stabilizing. (a) \(T_{n}=\frac{1}{n} \sum_{i=1}^{n} X_{i}, X_{i} \sim \operatorname{Poisson}(\lambda), h\left(T_{n}\right)=\sqrt{T}_{n}\) (b) \(T_{n}=\frac{1}{n} \sum_{i=1}^{n} X_{i}, X_{i} \sim \operatorname{Bernoulli}(p), h\left(T_{n}\right)=\arcsin \sqrt{T}_{n}\).

Let \(X_{1}, \ldots, X_{m}\) and \(Y_{1}, \ldots, Y_{n}\) be independently distributed according to \(N\left(\xi, \sigma^{2}\right)\) and \(N\left(\eta, \tau^{2}\right)\), respectively. Find the minimal sufficient statistics for these cases: (a) \(\xi, \eta, \sigma, \tau\) are arbitrary: \(-\infty<\xi, \eta<\infty, 0<\sigma, \tau\). (b) \(\sigma=\tau\) and \(\xi, \eta, \sigma\) are arbitrary. (c) \(\xi=\eta\) and \(\xi, \sigma, \tau\) are arbitrary.

Suppose that \(X_{1}, \ldots, X_{n}\) are an iid sample from a location-scale family with distribution function \(F((x-a) / b)\). (a) If \(b\) is known, show that the differences \(\left(X_{1}-X_{i}\right) / b, i=2, \ldots, n\), are ancillary. (b) If \(a\) is known, show that the ratios \(\left(X_{1}-a\right) /\left(X_{i}-a\right), i=2, \ldots, n\), are ancillary. (c) If neither \(a\) or \(b\) are known, show that the quantities \(\left(X_{1}-X_{i}\right) /\left(X_{2}-X_{i}\right), i=\) \(3, \ldots, n\), are ancillary.

Show that \(x^{p}\) is concave over \((0, \infty)\) if \(0

Morris \((1982,1983 \mathrm{~b})\) investigated the properties of natural exponential families with quadratic variance functions. There are only six such families: normal, binomial, gamma, Poisson, negative binomial, and the lesser-known generalized hyperbolic secant distribution, which is the density of \(X=\frac{1}{\pi} \log \left(\frac{Y}{1-Y}\right)\) when \(Y \sim \operatorname{Beta}\left(\frac{1}{2}+\frac{\theta}{\pi}, \frac{1}{2}-\frac{\theta}{\pi}\right),|\theta|<\frac{\pi}{2}\). (a) Find the density of \(X\), and show that it constitutes an exponential family. (b) Find the mean and variance of \(X\), and show that the variance equals \(1+\mu^{2}\), where \(\mu\) is the mean. Subsequent work on quadratic and other power variance families has been done by BarLev and Enis (1986, 1988), Bar-Lev and Bshouty (1989), and Letac and Mora (1990).

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