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A \(\$ 20,000\) mortgage is being repaid with 20 annual installments at the end of each year. The borrower makes five payments and then is temporarily unable to make payments for the next two years. Find an expression for the revised payment to start at the end of the 8 th year if the loan is still to be repaid at the end of the original 20 years

Short Answer

Expert verified
The revised payment expression starting at the end of the 8th year to ensure that the loan is fully repaid at the end of the original 20 years is: \(R = \frac{PV\frac{1-(1+i)^{-15}}{1-(1+i)^{-n}} + A\frac{1-(1+i)^{-2}}{i}(1+i)^{-7}}{\frac{1-(1+i)^{-13}}{i}}\)

Step by step solution

01

Calculate the original annual payment

First, let's find the original annual payment (A) using the Present Value (PV) of annuity formula: \(PV = A\frac{1-(1+i)^{-n}}{i}\) where PV = 20,000 dollars, i = interest rate, and n = number of annual payments (20 years). We don't have the interest rate, but we don't need it. Instead, we will use another way to find the remaining balance after 5 payments and then skipping payments for 7 years.
02

Find the remaining balance after 5 payments

After 5 payments, there are 15 years left to repay the loan. To find the remaining balance, let's write the present value of the remaining 15 payments after the fifth payment as: \(B = A\frac{1-(1+i)^{-15}}{i}\) Re-arrange the original annuity formula to calculate A: \(A = PV\frac{i}{1-(1+i)^{-n}}\) Now, substitute A into the formula for B: \(B = PV\frac{i}{1-(1+i)^{-n}}\frac{1-(1+i)^{-15}}{i} = PV\frac{1-(1+i)^{-15}}{1-(1+i)^{-n}}\)
03

Find the present value of the 2-year skipped payments

The borrower skipped two payments after making the first five payments. To calculate the present value of these 2 skipped payments, we will discount them back at the end of the 7th year: \(S = A\frac{1-(1+i)^{-2}}{i}(1+i)^{-7}\)
04

Find the revised annual payment starting at the end of the 8th year

Now, we need to find a new payment amount (R) that will repay the remaining balance plus the present value of the 2 skipped payments over 13 years (remaining 3 years after the 7-year interval plus the original 10 years after year 5): \(R\frac{1-(1+i)^{-13}}{i} = B + S\) Substitute the expressions for B and S: \(R\frac{1-(1+i)^{-13}}{i} = PV\frac{1-(1+i)^{-15}}{1-(1+i)^{-n}} + A\frac{1-(1+i)^{-2}}{i}(1+i)^{-7}\) Finally, solve for R: \(R = \frac{PV\frac{1-(1+i)^{-15}}{1-(1+i)^{-n}} + A\frac{1-(1+i)^{-2}}{i}(1+i)^{-7}}{\frac{1-(1+i)^{-13}}{i}}\) This is the revised payment expression starting at the end of the 8th year to ensure that the loan is fully repaid at the end of the original 20 years.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mortgage Amortization
Understanding mortgage amortization is crucial when dealing with any loan repayment plan. Amortization refers to spreading out a loan into a series of fixed payments over time. Each installment covers a part of both principal and interest. The goal is to ultimately pay off the total amount borrowed, along with the accumulated interest.
In the context of mortgage calculations, think of it as gradually reducing your loan with each payment until it reaches zero by the end of the loan term. In the original exercise, the borrower is dealing with a mortgage of $20,000 to be paid over 20 years. After making initial payments, there's a pause in contributions which impacts the repayment schedule, thus requiring recalculation of how the debt is reduced over the remaining period.
The process helps ensure that the entire loan, including interest, is paid off consistently over the designated period, even if adjustments are made due to missed payments.
Adjustment of Loan Payment
Occasionally, circumstances may require adjustments to the original loan payment schedule, as seen in the exercise when the borrower misses two payments after the fifth year. Adjusting a loan payment means recalculating future installments to still meet the loan's terms.
This situation often arises when there's a significant change like a missed payment or changes in interest rates. To handle this, one calculates the payment needed to cover the remaining balance in the adjusted period.
In the exercise, after the skipped payments, new annual payments must be determined, beginning at the end of the 8th year. The revised payments have to make up for the missed contributions and ensure the loan is still cleared within the original 20 year timeline.
Recalculating involves understanding various factors like the remaining loan balance and the interest accruing during the skipped payment period.
Interest Rate Calculations
Interest rates play a significant role in how much you pay over the lifetime of a loan. They determine the amount of interest added to your balance over time. Calculating interest thoroughly helps you know your total repayment amount.
In the context of this problem, while the solution did not specify an exact interest rate, it's assumed a specific rate governs the calculations. Even if not given, the formula adjustments reveal the impact of interest on skipped payments and remaining balance.
Interest calculations would generally involve applying the rate to the outstanding balance to find out how much interest accumulates. When skipping payments, calculating how much additional interest adds to the debt during the non-payment period is crucial.
The formulas presented reflect the interest's role in adjusting the payment schedule efficiently.
Loan Payment Schedule
The loan payment schedule is essentially the roadmap of how and when your loan will be repaid. Initially set with regular installments over a specific period, changes like skipped payments will necessitate a schedule adjustment.
In our exercise, the borrower needs to adjust the payment schedule after missing payments in years 6 and 7. To get back on track, a new installment amount is calculated to ensure full repayment by year 20.
The loan payment schedule should be consistent and include both principal and interest in each payment. Any missed payment will require updating the schedule and possibly increasing future payments.
It's the schedule that keeps a borrower accounted for, ensuring every payment is systematically directed towards amortizing the loan, balancing between interest payment and principal reduction. By adhering to this plan, you maintain a clear path to debt resolution.

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Most popular questions from this chapter

A borrower has a mortgage which calls for level annual payments of 1 at the end of each year for 20 years. At the time of the seventh regular payment an additional payment is made equal to the amount of principal that according to the original amortization schedule would have been repaid by the eighth regular payment. If payments of 1 continue to be made at the end of the eighth and succeeding years until the mortgage is fully repaid, show that the amount saved in interest payments over the full term of the mortgage is 1-v^{13}$$1-v^{13}$$

A loan of \(\$ 3000\) is being amortized by 20 quarterly payments. Payments 11 and 12 are not made. At the designated time of the 12 th payment, the loan is renegotiated so that the 13 th payment is \(\$ N\) and payments \(14,16,18,\) and 20 are each \(\$ 40\) more than the preceding payment. If the rate of interest is \(8 \%\) convertible semiannually, find the value of \(N\) which would provide that the loan be completely repaid in the original time period. Answer to the nearest dollar.

A loan is being repaid by quarterly installments of \(\$ 1500\) at the end of each quarter at \(10 \%\) convertible quarterly. If the loan balance at the end of the first year is \(\$ 12,000,\) find the original loan balance. Answer to the nearest dollar.

A loan of \(\$ 1000\) is to be amortized with quarterly installments of \(\$ 100\) for as long as necessary plus a smaller final payment one quarter after the last regular payment. Interest is computed at \(12 \%\) convertible quarterly on the first \(\$ 500\) of outstanding loan balance and at \(8 \%\) convertible quarterly on any excess. a) Find the principal repaid in the fourth installment. b) Show that prior to the "crossover" point, the successive principal repayments plus a constant form a geometric progression, i.e. $$\frac{P_{t+1}+k}{P_{t}+k}=1+j \text { for } t=1,2, \ldots, a-1$$ (1) Find k. (2) Find \(j\)

It is known that the remaining undiscounted payout on an insurance claim \(t\) periods after the claim was incurred is given by \(\alpha e^{-\beta i}\) a) If the instantaneous rate of claim payment is \(P(t),\) find an expression for \(P(t)\) b) Find the undiscounted total payout on the claim at time 0 . c) Find the present value of the total payout on the claim at time 0 , if the force of interest is 8 d) Find the present value of the remaining payout on the claim at time \(t,\) if the force of interest is \(\overrightarrow{\boldsymbol{\delta}}\)

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