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Music and mazes A researcher wishes to determine if people are able to complete a certain pencil and paper maze more quickly while listening to classical music. Suppose previous research has established that the mean time needed for people to complete a certain maze (without music) is 40 seconds. The researcher decides to test the hypotheses $H_0:\mathrm{μ}=40$ versus $H_a:\mathrm{μ}<40$ where $\mathrm{μ}=$ the time in seconds to complete the maze while listening to classical music. To do so, the researcher has $10,000$ people complete the maze with classical music playing. The mean time for these people is $\overline{x}=39.92$ seconds, and the P-value of his significance test is $0.0002$ Explain why this result is statistically significant, but not practically important.

Step by step solution

01

Given information

$$\begin{gathered} H_0:\mathrm{μ}=40 \\ {H}_1:\mathrm{μ}<40 \\ \overline{x}=39.92 \\ P−value=0.0002 \end{gathered}$$

02

Calculation

Assume that the level of significance $\mathrm{Î\pm }$is $0.05$

$\mathrm{Î\pm }=0.05$

Reject the null hypothesis $H_0$if the$P-$value is less than the significance level, and the result is statistically significant.

$0.0002<0.05⇒Statisticallysignificant$

However, the finding is not practically significant because the improvement was just $40-39.92=0.08$ seconds, and $0.08$ seconds is not a significant improvement in the maze completion time.

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