91Ó°ÊÓ

Given,

$$\begin{gathered} \mathrm{μ}=3668 \\ \mathrm{σ}=511 \end{gathered}$$

With one standard deviation from the distribution's mean, the centre 68 percent of a normal distribution lies.

The middle 95 percentile of a normal distribution is two standard deviations off the mean.

With three standard deviations from the distribution's mean, the middle 99.7% of a normal distribution is found.

Identifying values that are 1,2, and 3 standard deviations apart from the mean

$$\begin{gathered} \mathrm{μ}-3\mathrm{σ}=3668-3\left(511\right)=2135 \\ \mathrm{μ}-2\mathrm{σ}=3668-2\left(511\right)=2646 \\ \mathrm{μ}-\mathrm{σ}=3668-511=3157 \\ \mathrm{μ}+\mathrm{σ}=3668+511=4179 \\ \mathrm{μ}+2\mathrm{σ}=3668+2\left(511\right)=4690 \\ \mathrm{μ}+3\mathrm{σ}=3668+3\left(511\right)=5201 \end{gathered}$$

Normal distribution

$$\begin{gathered} \mathrm{μ}=3668 \\ \mathrm{σ}=511 \end{gathered}$$

A basic random sample of size 5 has 5 data values that are broadly centred around a, with all data values falling between and. $\mathrm{μ}-3\mathrm{σ}=3668-3\left(511\right)=2135$and $\mathrm{μ}+3\mathrm{σ}=3668+3\left(511\right)=5201$.

The size of a probable sample of size 5 is then calculated.$2400,3000,3600,3700,4500$.

The Range $=\max -\min =4500-2400=2100$

Place a dot above the associating number on the number line for each given data value.

Given , The graph is

The dots on the dot plot show the sample range of simple random samples with a size of $n=5$. A single simple random sample size $n=5$with a sample range of 2800 grammes is represented by the dot at 2800.

Given,

$$\begin{gathered} \mathrm{μ}=3668 \\ \mathrm{σ}=511 \end{gathered}$$

A normal distribution's middle 68 percent are one standard deviation from the distribution's mean. The middle 95 percentile of a normal distribution is two standard deviations off the mean. With three standard deviations from the distribution's mean, the middle 99.7% of a normal distribution is found.

$$\begin{gathered} \mathrm{μ}-3\mathrm{σ}=3668-3\left(511\right)=2135 \\ \mathrm{μ}+3\mathrm{σ}=3668+3\left(511\right)=5201 \end{gathered}$$

As a result, almost all data values fall between 5201 and 2135.

The difference between the maximum and minimum called the range.

$\text{Range}=\max -\min =5201-2135=3066$

This means that the population range is approximately 3066 grammes.

If the centre of the estimator's sample distribution equals the corresponding population parameter, the estimator is said to be unbiased.

All sample ranges are smaller than the population range of 3066 grammes, as seen in the dot plot. This suggests that the sample range's centre of sampling distribution is not the population range, and hence the sample range is not an unbiased estimator of the population range.