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whether of the following scenarios explain a geometric setting yes or not, If yes than define an appropriate geometric random variable.

The geometric distribution of a random variable When a variable has two possible outcomes, each draw is independent of the previous ones. The variable computes the number of draws needed until the first success. Every draw has the same chance of winning.

There is no geometric distribution since each draw is not independent of the previous ones, even though there is no replacement.

whether of the following scenarios explain a geometric setting yes or not, If yes than define an appropriate geometric random variable.

A geometric setup has four conditions: independent trials, binary (success/failure), the chance of success is the same for each trial, and the variable of interest is the number of trials required to get the first success.

Binary: it is satisfied since Success=place bag in hole and Failure=do not place bag in hole. Independent trials: it is satisfied since each toss has an identical chance of landing a bag in the hole (as the probability is $20\%$)

Probability of success: it is satisfied, because there is a $20\%$possibility of getting a bag into the hold and therefore the probability of success is 20%.

It is satisfied since he is interested in the number of trials until he obtains a bag in the hole, which is the first success.

Despite the fact that all four prerequisites are met, the offered scenario explains a geometric situation.