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In debt? According to financial records, 24% of U.S. adults have more debt on their credit cards than they have money in their savings accounts. Suppose that we take a random sample of 100 U.S. adults. Let D= the number of adults in the sample with more debt than savings.

a. Explain why D can be modeled by a binomial distribution even though the sample was selected without replacement.

b. Use a binomial distribution to estimate the probability that 30 or more adults in the sample have more debt than savings.

Short Answer

Expert verified
  1. A binomial distribution can be used to model D.
  2. More than or equal to 30 persons in the sample have more debts than savings, with a probability of 0.11087.

Step by step solution

01

Part (a) Step 1: Given information

The number of adults in the sample who have more debt than savings is denoted by the letter D.

Sample size =100

Percentage of adults in the United States who have more debt than savings=24%

The following is the concept applied:

10%condition.

n<0.10N

02

Part (a) Step 2:  Calculation

According to the rule, if the sample represents less than 10% of the population, it is safe to assume that the trials are independent and may be modelled using the binomial distribution, regardless of the without replacement sample.

The sample size (=100) is much less than 10% of all people in the United States.

Furthermore, each adult's study is conducted independently. The financial situation of one adult has no bearing on the financial situation of another adult.

So,D~Bin(100,0.24)

Hence, A binomial distribution can be used to model D.

03

Part (b) Step 1: Given information

The number of adults in the sample who have more debt than savings is denoted by the letter D.

Sample size =100

Percentage of adults in the United States who have more debt than savings =24%

Concept applied:

10%condition

n<0.10N

04

Part (b) Step 2:  Calculation

Consider,

P(D≥30)=1-P(D<30)P(D≥30)=1-P(D≤29)

Using TI- 83 plus

a) First we have to Click on 2nd and then click on Dist.

b) Next Go to binomcdf with ↓ key.

c) Then Hit Enter

d) Type100,0.24,29

e) Then Hit Enter

The probability comes to be 0.88913.

P(D≥30)=1-0.88913P(D≥30)=0.11087

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