/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q 36. George鈥檚 average bowling score... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 2: Q 36. (page 108)

George鈥檚 average bowling score is180; he bowls in a league where the average for all bowlers is 150 and the standard deviation is 20Bill鈥檚 average bowling score is 190; he bowls in a league where the average is 160and the standard deviation is 15. Who ranks higher in his own league, George or Bill?

a. Bill, because his 190is higher than George鈥檚 180

b. Bill, because his standardized score is higher than George鈥檚.

c. Bill and George have the same rank in their leagues because both are 30pins above the mean.

d. George, because his standardized score is higher than Bill鈥檚.

e. George, because the standard deviation of bowling scores is higher in his league.

Short Answer

Expert verified

The correct option is (b) Bill, because his standardized score is higher than George鈥檚.

Step by step solution

01

Given information

For 1st bowler

x=180,渭=150,蟽=20

For 2nd bowler

x=190,渭=160,蟽=15

02

Concept

The formula used: Z=x鈭�渭蟽

03

Calculation

Formula for z-score

Z=x鈭�渭蟽ZGeorge=180鈭�15020=1.5ZBill=190-16015=2ZBill>ZGeorge

So the correct choice is (b).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The following Normal probability plot shows the distribution of points scored for the 551 players in a single NBA season.

If the distribution of points was displayed in a histogram, what would be the best

description of the histogram鈥檚 shape?

a. Approximately Normal

b. Symmetric but not approximately Normal

c. Skewed left

d. Skewed right

e. Cannot be determined

Standard Normal areas Find the proportion of observations in a standard Normal distribution that satisfies each of the following statements.

a. z<鈭�2.46

b. 0.89<z<2.46

A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measuring the weights of many of these cockroaches, a lab assistant reports that 14% of the cockroaches weigh more than 55 grams. Based on this report, what is the approximate standard deviation of weight for this species of cockroaches?

a.4.6b.5.0c.6.2d.14.0

e. Cannot determine without more information.

The number of absences during the fall semester was recorded for each student in a large elementary school. The distribution of absences is displayed in the following cumulative relative frequency graph.

What is the interquartile range (IQR) for the distribution of absences?

a. 1

b. 2

c. 3

d. 5

e. 14

Taxi! In 2016, taxicabs in Los Angeles charged an initial fee of \(2.85 plus \)2.70 per mile. In equation form, Fare=2.85+2.7(miles). At the end of a

month, a businessman collects all his taxicab receipts and calculates some numerical

summaries. The mean fare he paid was \(15.45with a standard deviation of \)10.20What are the mean and standard deviation of the lengths of his cab rides in miles?
See all solutions

Recommended explanations on Math Textbooks

Logic and Functions

Read Explanation

Discrete Mathematics

Read Explanation

Probability and Statistics

Read Explanation

Applied Mathematics

Read Explanation

Decision Maths

Read Explanation

Theoretical and Mathematical Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.