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Chapter 8: Q 79. (page 492)

Willows in Yellowstone Writers in some fields summarize data by giving x 虅 and its

standard error rather than x炉andSX.Biologists studying willow plants in Yellowstone National Park reported their results in a table with columns labeled x炉andSX The table entry for the heights of willow plants (in centimeters) in one region of the park was 61.55卤19.03. The researchers measured a total of 23plants.

a. Find the sample standard deviation sxfor these measurements.

b. A hasty reader believes that the interval given in the table is a 95% confidence interval for the mean height of willow plants in this region of the park. Find the actual confidence level for the given interval.

Short Answer

Expert verified

a. Standard deviation is 91.2547mm

b. Actual confidence level is 66%

Step by step solution

01

Given Information

It is given that:

SE=19.03

x炉=61.55

n=23

02

Standard Deviation

We know that SE=sxn

19.03=sx23

sx=19.03脳23

sx=91.2647

03

Actual Confidence Level

The degree of freedom is =df=n-1=23-1=22

Using excel formula, confidence level is found as =2*TDIST(1,22,2)

Confidence Level is66%

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Most popular questions from this chapter

The Gallup Poll interviews 1600 people. Of these, 18% say that they jog regularly. The news report adds: 鈥淭he poll had a margin of error of plus or minus three percentage points at a 95% confidence level.鈥� You can safely conclude that

a. 95% of all Gallup Poll samples like this one give answers within 卤3% of the true population value.

b. the percent of the population who jog is certain to be between 15% and 21%.

c. 95% of the population jog between 15% and 21% of the time.

d. we can be 95% confident that the sample proportion is captured by the confidence interval.

e. if Gallup took many samples, 95% of them would find that 18% of the people in the sample jog.

Judy is interested in the reading level of a medical journal. She records the length of a random sample of100words. The histogram displays the distribution of word length for her sample. Determine if the Normal/Large Sample condition is met in this context.

A newspaper reporter asked an SRS of 100residents in a large city for their opinion about the mayor鈥檚 job performance. Using the results from the sample, the C%confidence interval for the proportion of all residents in the city who approve of the mayor鈥檚 job performance is 0.565to0.695. What is the value of C?

a. 82

b. 86

c. 90

d. 95

e. 99

Student body totals Use your interval from Exercise 40 to construct and interpret a 99%confidence interval for the total number of students at the school that the student body president can identify by name. Then use your interval to evaluate the president鈥檚 claim.

More prayer in school Refer to Exercise 5. Interpret the confidence level.
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