91Ó°ÊÓ

The given data is:

32000, 32000, 32000, 32000, 32000, 60000, 60000, 280000

$n=8$

Mean is:

$$\begin{gathered} \stackrel{¯}{x}=\frac{\underset{i=1}{\overset{n}{∑}}{x}_i}{n} \\ =\frac{32000+32000+32000+32000+32000+60000+60000+280000}{8} \\ =\frac{560000}{8} \\ =70000 \end{gathered}$$

All employees of the firm earn less than the mean salary of $70,000 except the owner.

32000, 32000, 32000, 32000, 32000, 60000, 60000, 280000

As we know that median is the middle value of a data set. As the given set is even, the median will be the average of two middle values (4th and 5th) of this sorted data:

$$\begin{gathered} M=\frac{32000+32000}{2} \\ =32000 \end{gathered}$$

The median salary is $32,000.

As we have observed that all employees in the organization make less than the mean, an unethical recruiter might use the mean to deceive prospective recruits, and so the prospective employees will have no possibility of making that much money with this company.