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Sports Illustrated planned to ask a random sample of Division I college athletes, 鈥淒o you believe performance-enhancing drugs are a problem in college sports?鈥 Which of the following is the smallest number of athletes that must be interviewed to estimate the true proportion who believe performance-enhancing drugs are a problem within 2% with 90% confidence?

a.17b.21c.1680d.1702e.2401

Short Answer

Expert verified

The correct optionis

a.n=z/220.25ME2=1.6520.250.0221702

Step by step solution

01

Given information

We have to find the smallest number of athletes that must be interviewed to estimate the true proportion.

02

Explanation 

Formula sample size:

p^known:n=z/22p^q^ME2=z/22p^(1-p^)ME2

p^unknown:n=z/220.25ME2

the sample size is:

n=z/220.25ME2=1.6520.250.0221702

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Most popular questions from this chapter

Who talks more鈥攎en or women? Researchers equipped random samples of 56 male and 56 female students from a large university with a small device that secretly records sound for a random 30 seconds during each 12.5-minute period over 2 days. Then they counted the number of words spoken by each subject during each recording period and, from this, estimated how many words per day each subject speaks. The female estimates had a mean of 16,177 words per day with a standard deviation of 7520 words per day. For

the male estimates, the mean was 16,569 and the standard deviation was 9108. Do these data provide convincing evidence at the 伪=0.053051526=0.200=20.0%=0.05significance level of a difference in the average number of words spoken in a day by all male and all female students at this university?

An SRS of size 100is taken from Population A with proportion 0.8of successes. An independent SRS of size 400is taken from Population B with proportion 0.5of successes. The sampling distribution of the difference (A 鈭 B) in sample proportions has what mean and standard deviation?

a. mean=0.3; standard deviation =1.3

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c. mean=0.3; standard deviation =0.047

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Friday the 13thRefer to Exercise 88.

a. Construct and interpret a 90%confidence interval for the true mean difference. If you already defined parameters and checked conditions in Exercise 88, you don鈥檛 need to do them again here.

b. Explain how the confidence interval provides more information than the test in Exercise 88.

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