91影视

Data re paired if a data value in one sample corresponds with a unique data value in the other sample.

In this case, we note that the Male literacy data values belongs to the same countries as the Female literacy rates which implies that we have two data values per day and thus each of these data values per day forms a pair.

The dots in the dot plot represents the difference between males literacy rates and females literacy rates.

We note that all dots in the dot plot lie to the right of the zero which means that most of the differences are positive and thus the male literacy rates appears to be higher than the female literacy rates in general.

It is given that the table of the difference which is the male literacy rates less by the female literacy rates.

The mean is:

$$\begin{gathered} \stackrel{炉}{x}=\frac{{\displaystyle \underset{i-1}{\overset{n}{鈭�}}}{x}_i}{n} \\ =\frac{30.5+0+0.2+8.6+16.8+7.4+15.4+8.7+6.4+0.5+7.4+7.9+4.7+18.5+25+9.1+12.4+0.2+14.8+4+1+0.6+34.4+1.2}{24} \\ =\frac{235.7}{24} \\ =9.8208 \end{gathered}$$

The sample variance is then as:

$$\begin{gathered} s^2=\frac{\underset{}{鈭�}{(x-\stackrel{炉}{x})}^2}{n-1} \\ =\frac{{(30.5-9.8208)}^2+(0-9.8208)2+(0.2-9.8208{)}^2+(8.6-9.8208{)}^2+(16.8-9.8208{)}^2+(7.4-9.8208{)}^2+(15.4-9.8208{)}^2+(8.7-9.8208{)}^2+(6.4-9.8208{)}^2+(0.5-9.8208{)}^2+(7.4-9.8208{)}^2+(7.9-9.8208{)}^2+(4.7-9.8208{)}^2+(18.5-9.8208{)}^2+(25-9.8208{)}^2+(9.1-9.8208{)}^2+(12.4-9.8208{)}^2+(0.2-9.8208{)}^2+(14.8-9.8208{)}^2+(4-9.8208{)}^2+(1-9.8208{)}^2+(0.6-9.8208{)}^2+(34.4-9.8208{)}^2+(1.2-9.8208{)}^2+(}{24-1} \\ =93.2548 \end{gathered}$$

The sample standard deviation is then,

$$\begin{gathered} s=\sqrt{s^2} \\ =\sqrt{93.2548} \\ =9.6569 \end{gathered}$$

The difference are on average$9.8208$ which tends to vary on average by$9.6569$ from the average of$9.8208$.