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Stop doing homework! (4.3)Researchers in Spain interviewed 772513-year-olds about their homework habits鈥攈ow much time they spent per night on homework and whether they got help from their parents or not鈥攁nd then had them take a test with 24math questions and 24science questions. They found that students who spent between 90and 100minutes on homework did only a little better on the test than those who spent 60to 70minutes on homework. Beyond 100minutes, students who spent more time did worse than those who spent less time. The researchers concluded that 60to 70minutes per night is the optimum time for students to spend on homework.32 Is it appropriate to conclude that students who reduce their homework time from 120minutes to 70minutes will likely improve their performance on tests such as those used in this study? Why or why not? independent random samples from two populations of interest or from two groups in a randomized experiment, use two-sample t procedures for 渭1鈭捨23051526=0.200=20.0%1-2

Short Answer

Expert verified

The required answer is No

Step by step solution

01

Explanation

In the previous exercise, we concluded that there was a link between homework time and test performance, such as those used in the study, because homework times longer than 100minutes tend to correspond with poor test results.

However, association does not imply causation, which means that reducing homework time does not always result in better test results.

02

For example

It is possible that people with long homework times have learning difficulties, and that reducing their homework time will worsen their test results.

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Most popular questions from this chapter

Ban junk food! A CBS News poll asked 606 randomly selected women and 442

randomly selected men, 鈥淒o you think putting a special tax on junk food would encourage more people to lose weight?鈥 170 of the women and 102 of the men said 鈥淵es.鈥 A 99% confidence interval for the difference (Women 鈥 Men) in the true proportion of people in each population who would say 鈥淵es鈥 is 鈭0.020to0.120. Does the confidence interval provide convincing evidence that the two population proportions are equal? Explain your answer.

Does drying barley seeds in a kiln increase the yield of barley? A famous

experiment by William S. Gosset (who discovered the t distributions) investigated this

question. Eleven pairs of adjacent plots were marked out in a large field. For each pair,

regular barley seeds were planted in one plot and kiln-dried seeds were planted in the

other. A coin flip was used to determine which plot in each pair got the regular barley seed

and which got the kiln-dried seed. The following table displays the data on barley yield

(pound per acre) for each plot.

Do these data provide convincing evidence at the 伪=0.05 level

that drying barley seeds in a kiln increases the yield of barley, on average?

According to sleep researchers, if you are between the ages of 12and 18years old, you need 9hours of sleep to function well. A simple random sample of 28students was chosen from a large high school, and these students were asked how much sleep they got the previous night. The mean of the responses was 7.9hours with a standard deviation of 2.1hours. If we are interested in whether students at this high school are getting too little sleep, which of the following represents the appropriate null and alternative hypotheses ?

  1. H0:=7.9and Ha:<7.9
  2. H0:=7.9and Ha:7.9
  3. H0:=9and Ha:9
  4. H0:=9and width="69" height="24" role="math">Ha:<9
  5. H0:9andHa:9

Researchers suspect that Variety A tomato plants have a different average yield than Variety B tomato plants. To find out, researchers randomly select10Variety A and10Variety B tomato plants. Then the researchers divide in half each of10small plots of land in different locations. For each plot, a coin toss determines which half of the plot gets a Variety A plant; a Variety B plant goes in the other half. After harvest, they compare the yield in pounds for the plants at each location. The10differences (Variety A 鈭 Variety B) in yield are recorded. A graph of the differences looks roughly symmetric and single-peaked with no outliers. The mean difference is x-A-B=0.343051526=0.200=20%x-A-B=0.34and the standard deviation of the differences is s A-B=0.833051526=0.200=20%=sA-B=0.83.Let A-B=3051526=0.200=20%渭A鈭払 = the true mean difference (Variety A 鈭 Variety B) in yield for tomato plants of these two varieties.

A 95% confidence interval forA-B3051526=0.200=20%A-Bis given by

a. 0.341.96(0.83)3051526=0.200=20%0.341.96(0.83)

b.0.341.96(0.8310)3051526=0.200=20%0.341.96(0.8310)

c. 0.341.812(0.8310)3051526=0.200=20%0.341.812(0.8310)

d. 0.342.262(0.83)3051526=0.200=20%0.342.262(0.83)

e.0.342.262(0.8310)3051526=0.200=20%0.342.262(0.8310)

A random sample of 200New York State voters included 88Republicans, while a random sample of 300California voters produced141Republicans. Which of the following represents the 95%confidence interval for the true difference in the proportion of Republicans in New York State and California?

a. (0.440.47)1.96((0.44)(0.56)+(0.47)(0.53)200+300)

b. (0.440.47)1.96((0.44)(0.56)200+(0.47)(0.53)300)

c. (0.440.47)1.96(0.44)(0.56)200+(0.47)(0.53)300

d. (0.440.47)1.96(0.44)(0.56)+(0.47)(0.53)200+300

e. (0.440.47)1.96(0.45)(0.55)200+(0.45)(0.55)300

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