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Lie detectors A federal report finds that lie detector tests given to truthful persons have probability about 0.2 of suggesting that the person is deceptive. company asks 12 job applicants about thefts from previous employers, using a lie detector to assess their truthfulness. Suppose that all 12 answer truthfully. Let \(X=\) the number of people who the lie detector says are being deceptive. (a) Find and interpret \(\mu_{X}\). (b) Find and interpret \(\sigma_{X}\).

Short Answer

Expert verified
(a) \(\mu_X = 2.4\); on average, 2.4 people out of 12 are judged deceptive. (b) \(\sigma_X \approx 1.39\); the variation around this average is about 1.39 people.

Step by step solution

01

Understanding the Binomial Distribution

In this scenario, we assume that the lie detector test outcome follows a binomial distribution because the result for each individual is a Bernoulli trial (either they are judged deceptive or not). Given:- Number of trials, \( n = 12 \)- Probability of a lie detector suggesting deception when the person is truthful, \( p = 0.2 \).Thus, \(X\), the number of people judged deceptive, follows \(B(n, p)\), specifically \(B(12, 0.2)\).
02

Calculating the Mean, \(\mu_X\)

The mean of a binomial distribution is calculated using the formula:\[ \mu_X = n \, p \]Plugging in the values, we find:\[ \mu_X = 12 \, \times \, 0.2 = 2.4 \]Thus, on average, the lie detector will suggest that 2.4 out of the 12 truthful people are being deceptive.
03

Calculating the Standard Deviation, \(\sigma_X\)

The standard deviation of a binomial distribution is calculated using the formula:\[ \sigma_X = \sqrt{n \, p \, (1 - p)} \]Substituting the given values:\[ \sigma_X = \sqrt{12 \, \times \, 0.2 \, \times \, (1 - 0.2)} = \sqrt{12 \, \times \, 0.2 \, \times \, 0.8} = \sqrt{1.92} \approx 1.3856 \]This means there is a standard deviation of approximately 1.39 in the number of people judged deceptive by the lie detector.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistics Problem Solving
Understanding statistics involves learning to analyze and interpret data through mathematical methods. In the case of the exercise with the lie detector test, the objective is to use statistical problem-solving techniques to predict outcomes based on probability. This requires recognizing the nature of the data, which in this scenario is a binomial distribution.
Here are some steps to effectively solve such problems:
  • Identify the type of distribution: Is it normal, binomial, or another kind?
  • Recognize if the trials are independent events: Each lie detector test is a separate event with the same probability of an outcome.
  • Determine the variables and their meanings: In this scenario, 'n' is the number of trials (job applicants) and 'p' is the probability of a truthful person being wrongly identified as deceptive.
  • Apply relevant formulas: For binomial distributions, key formulas include those for calculating mean and standard deviation, which help summarize and interpret the data.
Statistics problem-solving skills allow us to handle real-world scenarios where randomness is involved, like predicting the outcomes of tests and evaluations.
Standard Deviation
Standard deviation is a key concept in statistics. It measures the amount of variation or dispersion in a set of values. In simpler terms, it tells us how much the results can differ from the average result.
In this lie detector scenario, the standard deviation helps quantify the variability in the number of truthful people falsely identified as deceptive. For a binomial distribution, you can calculate the standard deviation using:\[ \sigma_X = \sqrt{n \, p \, (1 - p)} \]Where:\
  • \( n \) is the total number of trials, in this case, 12 job applicants.
  • \( p \) is the probability of any single trial resulting in a deceptive result (0.2 in this scenario).
Calculation steps:
  • Multiply the number of trials by the probability of a deceptive result: \(12 \times 0.2 = 2.4\).
  • Multiply this number by the probability of not getting a deceptive result, \(0.8\), giving \( 2.4 \times 0.8 = 1.92\).
  • Take the square root of the result above: \(\sqrt{1.92} \approx 1.39\).
This outcome shows that within the set of 12 trials, there is a significant amount of variation in how many false deceptive results might occur, reflecting natural randomness in the results.
Mean Calculation
The mean, or average, is a fundamental concept in statistics that represents a central value of a set. In binomial distribution problems like the lie detector test, calculating the mean helps us understand the expected outcome over several trials.
In this situation, the mean is calculated with the formula for a binomial distribution:\[ \mu_X = n \, p \]Where:
  • \( n \) is the number of trials, which in this case is 12.
  • \( p \) is the probability of a false positive (the lie detector indicating deception), which is 0.2.
By multiplying these two values, \( n \times p = 12 \times 0.2 \), we find:\[ \mu_X = 2.4 \]This tells us that, on average, the lie detector will incorrectly identify 2.4 out of the 12 applicants as being deceptive. Mean calculations are crucial because they offer a simplified yet powerful summary of the data, providing a clear expectation for practitioners to understand and make decisions based on average predicted outcomes.

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