/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 Cool pool? Coach Ferguson uses a... [FREE SOLUTION] | 91Ó°ÊÓ

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Cool pool? Coach Ferguson uses a thermometer to measure the temperature (in degrees Celsius) at 20 different locations in the school swimming pool. An analysis of the data yields a mean of \(25^{\circ} \mathrm{C}\) and a standard deviation of \(2^{\circ} \mathrm{C}\). Find the mean and standard deviation of the temperature readings in degrees Fahrenheit (recall that \({ }^{\circ} \mathrm{F}=(9 / 5)^{\circ} \mathrm{C}+32\) ).

Short Answer

Expert verified
Mean: \(77^{\circ}F\); Standard Deviation: \(3.6^{\circ}F\).

Step by step solution

01

Convert the Mean to Fahrenheit

First, we need to convert the mean temperature from Celsius to Fahrenheit using the conversion formula. The given mean is \(25^{\circ}\,C\). The formula for converting Celsius to Fahrenheit is: \(^{\circ}F = \frac{9}{5}\times^{\circ}C+32\). Thus, \(^{\circ}F = \frac{9}{5}\times 25 + 32\). Calculating this gives: \(^{\circ}F = 45 + 32 = 77^{\circ}F\). So, the mean temperature in Fahrenheit is \(77^{\circ}F\).
02

Convert the Standard Deviation to Fahrenheit

The spread or scale of the data is affected only by the multiplication part of the linear transformation (conversion equation) because adding a constant (32) does not impact the spread. Given that the standard deviation in Celsius is \(2^{\circ}\,C\), we use the formula only with the multiplication term: \( SD_{F} = \frac{9}{5} \times SD_{C}\).Thus, \( SD_{F} = \frac{9}{5} \times 2 = 3.6\).So, the standard deviation of the temperatures in Fahrenheit is \(3.6^{\circ}F\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean Temperature Conversion
Understanding how to convert the mean temperature from Celsius to Fahrenheit requires us to use a standard conversion formula. This formula is:
  • \(^\circ F = \left(\frac{9}{5}\right) \times ^\circ C + 32\)
The conversion process has two steps. First, multiply the Celsius mean by \(\frac{9}{5}\). This scales the temperature to match the Fahrenheit system. Then, add 32 to account for zero offset between these temperature scales.
In our exercise, the mean temperature is \(25^{\circ}C\). Applying this conversion, we get:
  • \(^\circ F = \left(\frac{9}{5}\right) \times 25 + 32\)
Upon calculating, it becomes:
  • \(45 + 32 = 77^{\circ}F\)
This result shows the average swimming pool temperature in Fahrenheit, underscoring that converting a mean temperature involves both scaling and shifting the original value.
Standard Deviation Conversion
Converting the standard deviation from Celsius to Fahrenheit involves a slightly different process than converting the mean. Standard deviation measures the spread of your data, so the constant you add when converting to Fahrenheit does not affect its calculation.
Instead, we only consider the multiplication factor, which pertains to scaling the original Celsius values. Specifically, we apply the factor \(\frac{9}{5}\) to the original standard deviation.
  • Given the standard deviation in Celsius is \(2^{\circ}C\), we utilize the equation \( SD_{F} = \left(\frac{9}{5}\right) \times SD_{C} \)
  • For our exercise, this becomes \( SD_{F} = \left(\frac{9}{5}\right) \times 2 = 3.6\).
Thus, the standard deviation in Fahrenheit is \(3.6^{\circ}F\), reflecting how spreading values scale under a linear transformation without being shifted by adding constants.
Celsius to Fahrenheit Conversion
Converting temperatures from Celsius to Fahrenheit is a common task in statistical analysis, particularly when working with data across different regions or reports using different scales. The formula
  • \(^\circ F = \left(\frac{9}{5}\right) \times ^\circ C + 32\)
is derived from the linear relationship between the two scales. For an individual value, it's essential to remember:
  • The multiplication by \(\frac{9}{5}\) adjusts the unit size. Celsius has 100 units between freezing and boiling, while Fahrenheit has 180.
  • With the addition of 32, the two scales align, fixing the zero-points' discrepancy, since freezing in Celsius is 0, whereas in Fahrenheit it is 32.
Performing such conversions is fundamental, whether it's for weather reports or global scientific research, ensuring consistent and comparable data presentation.

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