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Here are the row and column totals for a two-way table with two rows and two columns: $$ \begin{array}{ll|r} a & b & 50 \\ c & d & 50 \\ \hline 60 & 40 & 100 \end{array} $$ Find two different sets of counts \(a, b, c,\) and \(d\) for the body of the table that give these same totals. This shows that the relationship between two variables cannot be obtained from the two individual distributions of the variables.

Short Answer

Expert verified
Two sets of counts are (30, 20, 30, 20) and (40, 10, 20, 30).

Step by step solution

01

Analyze the Given Totals

Examine the row and column totals provided in the problem. The first row must sum to 50 and the second row to 50, giving a total of 100 for both rows together. The first column should sum to 60 and the second column to 40, giving a total of 100 for both columns together.
02

Understand Constraints for Calculation

Identify the equations resulting from the totals. From the table, we have these equations: \(a + b = 50\), \(c + d = 50\), \(a + c = 60\), and \(b + d = 40\). These are the constraints for choosing values of \(a\), \(b\), \(c\), and \(d\).
03

Find a Set of Counts

Using the equations, choose a value for \(a\). Suppose \(a=30\). Then \(b = 50 - 30 = 20\). For \(c\), we have \(c = 60 - a = 60 - 30 = 30\). Therefore \(d = 50 - 30 = 20\). The first set of counts is \(a=30, b=20, c=30, d=20\).
04

Verify First Set of Counts

Make sure the first set of counts satisfies all the constraints: \(a + b = 30 + 20 = 50\), \(c + d = 30 + 20 = 50\), \(a + c = 30 + 30 = 60\), and \(b + d = 20 + 20 = 40\). All constraints are satisfied.
05

Find Another Set of Counts

Choose a different value for \(a\). Suppose \(a=40\). Then \(b = 50 - 40 = 10\). For \(c\), we have \(c = 60 - a = 60 - 40 = 20\). Therefore \(d = 50 - 20 = 30\). The second set of counts is \(a=40, b=10, c=20, d=30\).
06

Verify Second Set of Counts

Ensure the second set of counts also meets all constraints: \(a + b = 40 + 10 = 50\), \(c + d = 20 + 30 = 50\), \(a + c = 40 + 20 = 60\), and \(b + d = 10 + 30 = 40\). All constraints are satisfied.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Row and Column Totals
Row and column totals are essential when working with two-way tables. These totals help in organizing and analyzing data that involves two different categorical variables. When dealing with a two-way table, each intersection in the table, or cell, represents a count of observations for the corresponding row and column categories.
For example, if you have a two-way table with two rows and columns, the sum of each row gives you row totals, and the sum of each column gives you column totals. These totals are very useful because they sum the counts in each category, offering a quick overview of the distribution of data across the table.

Let's consider the given exercise: the row and column totals are
  • Row 1: a + b = 50
  • Row 2: c + d = 50
  • Column 1: a + c = 60
  • Column 2: b + d = 40
Each of these equations must hold true for the counts in the table body. That is why analyzing these totals allows you to verify that any proposed counts match the original distribution constraints.
Simultaneous Equations
Simultaneous equations come into play when you solve for unknown values that must satisfy multiple conditions at the same time. In two-way tables, the row and column totals give rise to these equations, which must all be satisfied by the table values.
In our exercise, we derived the following equations:
  • (1) \(a + b = 50\)
  • (2) \(c + d = 50\)
  • (3) \(a + c = 60\)
  • (4) \(b + d = 40\)
To find a suitable set of numbers for \(a\), \(b\), \(c\), and \(d\), these equations must be solved together. This means you select a starting value for one variable, plug it into the equations, and solve for the others in a way that all equations maintain their integrity.
Typically, by starting with one equation, you can find a variable's value and substitute it back into other equations. This process is iterative and involves calculation and verification at each step to ensure satisfaction of all constraints.
Discrete Variables
Discrete variables, such as the ones used in our two-way table, are countable numbers. They take fixed values with no intermediates, common in categorical data involving non-overlapping groups.
Within a two-way table, each cell reflects the count of observations hitting a particular pair of categories across both dimensions. Unlike continuous variables, which can be any value within a range, discrete variables are numbers like whole integers.

In the exercise context, consider how we assign separate counts to elements like \(a, b, c,\) and \(d\). Each one represents a specific, countable number of observations, and when these counts add up, they form the row and column totals.
This distinction is crucial because it impacts how we approach designing and interpreting a two-way table. Each value is independently chosen, constrained by the simultaneous equation conditions, yet is essential for representing the relationships between different types of categorized data.

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Most popular questions from this chapter

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