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Losing weight A Gallup Poll found that 59% of the people in its sample said 鈥淵es鈥 when asked, 鈥淲ould you like to lose weight?鈥 Gallup announced: 鈥淔or results based on the total sample of national adults, one can say with 95% confidence that the margin of (sampling) error is \(\pm 3\) percentage points." \(^{\prime \prime 6}\) Can we use this interval to conclude that the actual proportion of U.S. adults who would say they want to lose weight differs from 0.55\(?\) Justify your answer.

Short Answer

Expert verified
Yes, the true proportion differs from 0.55.

Step by step solution

01

Understand the Problem

We need to determine if the proportion of U.S. adults who want to lose weight, based on a Gallup Poll, is statistically different from 0.55. The poll result was 0.59 with a margin of error of 卤0.03 at 95% confidence.
02

Identify the Confidence Interval

Given that the sample proportion is 0.59 and the margin of error is 卤0.03, calculate the confidence interval for the true proportion. The interval is \[ (0.59 - 0.03, 0.59 + 0.03) = (0.56, 0.62) \] This means we can be 95% confident that the true proportion is between 0.56 and 0.62.
03

Compare with 0.55

Check if the value 0.55 lies within the calculated confidence interval. The interval is (0.56, 0.62), and 0.55 is not within this range.
04

Conclusion

Since 0.55 is not within the confidence interval (0.56, 0.62), we can conclude that there is significant evidence to say that the actual proportion of U.S. adults who want to lose weight is different from 0.55, with 95% confidence.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sampling Error
When conducting surveys, like the Gallup Poll, data is collected from a sample of people rather than the entire population. This introduces something called "sampling error." Sampling error occurs because the sample might not be perfectly representative of the whole population.

Imagine surveying 1000 people to represent millions. Naturally, there will be some difference between the sample results and the true population parameter, which is the actual percentage of all people who feel a certain way. This difference is what we call sampling error.

In statistical terms, the sampling error represents the margin of error in the survey results. For Gallup Polls, this is often expressed as a plus-or-minus figure, like in the exercise we have a \(\pm 3\) percentage points margin of error. This means that if 59% of surveyed people say they want to lose weight, the true percentage could possibly be as low as 56% or as high as 62%, assuming a certain level of confidence.
Statistical Significance
Statistical significance helps us understand if the results from our sample reflect a true effect in the population or if they might have occurred by random chance.

In our exercise, the main goal is to see if there is a statistically significant difference between the proportion of U.S. adults who want to lose weight compared to a specific value, 0.55.

We calculate a confidence interval to determine this. The confidence interval gives us a range within which we expect the true proportion to lie, with a certain level of confidence, which is often 95%. If the hypothesized value (0.55 in this case) is outside of this interval, we reach a conclusion of statistical significance. It means the difference between the results and our point of reference is unlikely due to chance. In our example, since 0.55 is outside the 95% confidence interval of (0.56, 0.62), we conclude there's statistical evidence to assert the actual proportion differs from 0.55, with 95% confidence.
Gallup Poll
The Gallup Poll is a renowned tool for measuring the opinions and behaviors of populations. It's a valuable resource simply because it regularly gathers data on various public opinions through scientifically selected samples.

When you see results from a Gallup Poll, like in our weight loss example, understand that it stems from carefully designed methodologies to estimate the perspectives of larger populations. The poll adjusts for factors like sampling error and thus, provides credible insights.

Polls like Gallup鈥檚 are crucial in fields such as politics, social sciences, and marketing. They help stakeholders make informed decisions based on public sentiment. However, it's also important to keep in mind that while these polls are immensely useful, they are estimates鈥攈ence the importance of confidence intervals and understanding the range of possible error.

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Most popular questions from this chapter

Opening a restaurant You are thinking about opening a restaurant and are searching for a good location. From research you have done, you know that the mean income of those living near the restaurant must be over $85,000 to support the type of upscale restaurant you wish to open. You decide to take a simple random sample of 50 people living near one potential location. Based on the mean income of this sample, you will decide whether to open a restaurant there. (a) State appropriate null and alternative hypotheses. Be sure to define your parameter. (b) Describe a Type I and a Type II error, and explain the consequences of each. (c) If you had to choose one of the 鈥渟tandard鈥 significance levels for your significance test, would you choose A 0.01, 0.05, or 0.10? Justify your choice.

Packaging \(\operatorname{CDs}(6.2,5.3)\) A manufacturer of compact discs (CDs) wants to be sure that their CDs will fit inside the plastic cases they have bought for packaging. Both the CDs and the cases are circular. According to the supplier, the plastic cases vary Normally with mean diameter \(\mu=4.2\) inches and standard deviation \(\sigma=0.05\) inches. The CD manufacturer decides to produce CDs with mean diameter \(\mu=4\) inches. Their diameters follow a Normal distribution with \(\sigma=0.1\) inches. (a) Let X the diameter of a randomly selected CD and Y the diameter of a randomly selected case. Describe the shape, center, and spread of the distribution of the random variable X Y. What is the importance of this random variable to the CD manufacturer? (b) Compute the probability that a randomly selected CD will fit inside a randomly selected case. (c) The production process actually runs in batches of 100 CDs. If each of these CDs is paired with a randomly chosen plastic case, find the probability that all the CDs fit in their cases.

One-sided test Suppose you carry out a significance test of \(H_{0} : \mu=5\) versus \(H_{a} : \mu>5\) based on a sample of size \(n=20\) and obtain \(t=1.81\) (a) Find the P-value for this test using (i) Table B and (ii) your calculator. What conclusion would you draw at the 5% significance level? At the 1% significance level? (b) Redo part (a) using an alternative hypothesis of \(H_{a} : \mu \neq 5\)

Power A drug manufacturer claims that fewer than 10% of patients who take its new drug for treating Alzheimer鈥檚 disease will experience nausea. To test this claim, a significance test is carried out of $$ \begin{array}{l}{H_{0} : p=0.10} \\ {H_{a} : p<0.10}\end{array} $$ You learn that the power of this test at the 5\(\%\) significance level against the alternative \(p=0.08\) is 0.64 (a) Explain in simple language what "power \(=0.64^{\prime \prime}\) means in this setting. (b) You could get higher power against the same alternative with the same \(\alpha\) by changing the number of measurements you make. Should you make more measurements or fewer to increase power? Explain. (c) If you decide to use \(\alpha=0.01\) in place of \(\alpha=\) \(0.05,\) with no other changes in the test, will the power increase or decrease? Justify your answer. (d) If you shift your interest to the alternative \(p=\) 0.07 with no other changes, will the power increase or decrease? Justify your answer.

Study more! The significance test in Exercise 76 yields a P-value of 0.0622. (a) Describe a Type I and a Type II error in this setting. Which type of error could you have made in Exercise 76? Why? (b) Which of the following changes would give the test a higher power to detect \(\mu=120\) minutes: using \(\alpha=0.01\) or \(\alpha=0.10 ?\) Explain.

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