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Significance tests \(\mathrm{A}\) test of \(H_{0} : p=0.65\) against \(H_{a} : p<0.65\) has test statistic \(z=-1.78\) (a) What conclusion would you draw at the 5\(\%\) significance level? At the 1\(\%\) level? (b) If the alternative hypothesis were \(H_{a} : p \neq 0.65\) what conclusion would you draw at the 5\(\%\) significance level? At the 1\(\%\) level?

Short Answer

Expert verified
(a) Reject at 5%, fail to reject at 1%. (b) Fail to reject at both levels.

Step by step solution

01

Understand the Hypotheses

The null hypothesis is \( H_0: p = 0.65 \), and the alternative hypothesis is \( H_a: p < 0.65 \) for part (a). This means we are testing if the proportion is less than 0.65 at given significance levels.
02

Determine Critical Value for One-sided Test

For a significance level of 5\(\%\), the critical value for a one-sided test is approximately \(-1.645\). For a 1\(\%\) level, the critical value is approximately \(-2.33\).
03

Evaluate Test Statistic for One-sided Test

The test statistic given is \(z = -1.78\). Since \(-1.78 < -1.645\) but \(-1.78 > -2.33\), the result is significant at the 5\(\%\) level but not at the 1\(\%\) level.
04

Conclusion for Part (a)

At the 5\(\%\) significance level, we reject the null hypothesis. At the 1\(\%\) significance level, we fail to reject the null hypothesis.
05

Set Up Hypotheses for Two-sided Test

Now consider the alternative hypothesis \( H_a: p eq 0.65 \), meaning we test for any deviation from 0.65.
06

Determine Critical Value for Two-sided Test

For a 5\(\%\) significance level, the critical values are \(\pm 1.96\). For a 1\(\%\) significance level, they are \(\pm 2.576\).
07

Evaluate Test Statistic for Two-sided Test

The test statistic \(z = -1.78\) is neither less than \(-1.96\) nor more than \(1.96\). Similarly, it does not exceed \(-2.576\) or \(2.576\). Hence, it is not significant for both levels.
08

Conclusion for Part (b)

At both the 5\(\%\) and 1\(\%\) significance levels, we fail to reject the null hypothesis for \(H_a: p eq 0.65\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hypothesis Testing
Hypothesis testing is a statistical method used to decide whether there is enough evidence in a sample of data to infer that a certain condition is true for the entire population. This process involves forming two hypotheses:
  • The Null Hypothesis (\( H_0 \)): a statement that indicates no effect or no difference, suggesting that any observed deviation is due solely to chance.
  • The Alternative Hypothesis (\( H_a \)): a statement indicating the presence of an effect or a difference.
The aim is to determine whether the available data reject the null hypothesis in favor of the alternative one.
The hypothesis test is conducted at a specific significance level, often set at 5% or 1%, representing the probability of making a mistake by rejecting \( H_0 \) when it is indeed true. This probability level forms a threshold against which the evidence is evaluated.
Critical Values
Critical values are fundamentally important in hypothesis testing, serving as the demarcation lines set by the significance level. They determine the "cut-off" points that dictate whether a test statistic falls within the acceptance region or the rejection region. For example:
  • In a one-sided hypothesis test at a 5% significance level, the critical value could be \(-1.645\) for left-tailed tests.
  • At the 1% significance level, it may be \(-2.33\) for left-tailed tests.
These values can vary depending on whether the test is one-sided or two-sided.
For two-sided tests, the critical values at the 5% level are \( 卤1.96 \), and at the 1% level, they are \( 卤2.576 \). Observing a test statistic beyond these critical values indicates a significant result, leading to a rejection of the null hypothesis.
Null Hypothesis
The null hypothesis, denoted as \( H_0 \), is the bedrock assumption of our statistical test. It posits that there is no effect or difference in the population parameter that we are trying to validate. In the provided example, the null hypothesis \( H_0: p = 0.65 \) suggests that the proportion is statistically equal to 0.65.
This hypothesis serves as a starting point for statistical testing. The reason for beginning with \( H_0 \) is to assume as a default stance that the observed effect is simply due to random chance.
The decision in hypothesis testing usually revolves around rejecting or not rejecting \( H_0 \). If the test statistic falls in the rejection region, as determined by the critical values, the alternative hypothesis is supported instead.
Alternative Hypothesis
The alternative hypothesis, denoted as \( H_a \), is the statement that researchers are usually most interested in proving. It postulates that there is a specific effect or difference worth investigating.
Depending on the test, \( H_a \) can take different forms:
  • For a one-sided test: \( H_a: p < 0.65 \) (as in the original problem), meaning we suspect the proportion is less than 0.65.
  • For a two-sided test: \( H_a: p eq 0.65 \), meaning any deviation from 0.65鈥攚hether positive or negative鈥攊s of concern.
The confirmation of the alternative hypothesis indicates that the null hypothesis is not likely to be true, implying that the observed effect may indeed exist in the population. A rejection of \( H_0 \) provides support to \( H_a \), thereby highlighting its role as the main focus of interest in most significance tests.

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Most popular questions from this chapter

A researcher plans to conduct a significance test at the \(\alpha=0.01\) significance level. She designs her study to have a power of 0.90 at a particular alternative value of the parameter of interest. The probability that the researcher will commit a Type II error for the particular alternative value of the parameter at which she computed the power is (a) 0.01. (b) 0.10. (c) 0.89. (d) 0.90. (e) 0.99.

Statistical significance Asked to explain the meaning of 鈥渟tatistically significant at the A 0.05 level,鈥 a student says, 鈥淭his means that the probability that the null hypothesis is true is less than 0.05.鈥 Is this explanation correct? Why or why not?

Growing tomatoes An agricultural field trial compares the yield of two varieties of tomatoes for commercial use. Researchers randomly select 10 Variety A and 10 Variety B tomato plants. Then the researchers divide in half each of 10 small plots of land in different locations. For each plot, a coin toss determines which half of the plot gets a Variety A plant; a Variety B plant goes in the other half. After harvest, they compare the yield in pounds for the plants at each location. The 10 differences (Variety \(A-\) Variety \(B )\) give \(\overline{x}=0.34\) and \(s_{x}=0.83\) A graph of the differences looks roughly symmetric and single- peaked with no outliers. Is there convincing evidence that Variety A has the higher mean yield? Perform a significance test using \(\alpha=0.05\) to answer the question.

Bullies in middle school A University of Illinois study on aggressive behavior surveyed a random sample of 558 middle school students. When asked to describe their behavior in the last 30 days, 445 students said their behavior included physical aggression, social ridicule, teasing, name-calling, and issuing threats. This behavior was not defined as bullying in the questionnaire. Is this evidence that more than three-quarters of the students at that middle school engage in bullying behavior? To find out, Maurice decides to perform a significance test. Unfortunately, he made a few errors along the way. Your job is to spot the mistakes and correct them. $$ \begin{array}{l}{H_{0} : p=0.75} \\ {H_{a} : \hat{p}>0.797}\end{array} $$ where \(p=\) the true mean proportion of middle school students who engaged in bullying. A random sample of 558 middle school students was surveyed. \(558(0.797)=444.73\) is at least 10 $$ z=\frac{0.75-0.797}{\sqrt{\frac{0.797(0.203)}{445}}}=-2.46 ; P \text { -value }=2(0.0069)=0.0138 $$ The probability that the null hypothesis is true is only \(0.0138,\) so we reject \(H_{0} .\) This proves that more than three-quarters of the school engaged in bullying behavior.

Which of the following 95\(\%\) confidence intervals would lead us to reiect \(H_{0} : p=0.30\) in favor of \(H_{a} : p \neq 0.30\) at the 5\(\%\) significance level? $$ \begin{array}{l}{\text { (a) }(0.29,0.38) \quad \text { (c) }(0.27,0.31) \quad \text { (e) None of these }} \\ {\text { (b) }(0.19,0.27) \quad \text { (d) }(0.24,0.30)}\end{array} $$

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