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91Ó°ÊÓ

Bright lights? A string of Christmas lights contains 20 lights. The lights are wired in series, so that if any light fails the whole string will go dark. Each light has probability 0.02 of failing during a 3-year period. The lights fail independently of each other. Find the probability that the string of lights will remain bright for 3 years.

Short Answer

Expert verified
The probability is approximately 0.6676.

Step by step solution

01

Understand the Problem

The problem states that we have a string of 20 Christmas lights wired in series. If any light fails, the whole string fails. We want to find the probability that none of the lights fail in a period of 3 years.
02

Identify the Failure Probability

Each individual light has a 0.02 probability of failing within the 3-year period. Since the lights fail independently of each other, this probability applies to each one of them.
03

Calculate the Probability of One Light Succeeding

The probability that a single light does not fail during the 3-year period is the complement of the failure probability. So, for one light, the probability of not failing is given by:\[ P( ext{not failing}) = 1 - 0.02 = 0.98 \]
04

Calculate the Probability for the Entire String

Since all lights must function for the entire string to remain bright, and assuming independence, we multiply the probabilities of each light not failing. For 20 lights, this is:\[ P( ext{all lights not failing}) = (0.98)^{20} \]
05

Solve the Equation

Calculate \( (0.98)^{20} \) using a calculator or logarithmic tables to get the probability that all lights remain functional.Evaluating gives:\[ P( ext{all lights not failing}) \approx 0.6676 \]
06

Interpret the Result

The probability that the entire string of lights will remain bright for 3 years is approximately 0.6676. This means there is about a 66.76% chance that none of the lights will fail in the given period.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independent Events
Understanding independent events in probability is crucial, especially in scenarios like our Christmas lights problem.
When we say events are independent, it means that the outcome or occurrence of any one event does not affect the outcome or occurrence of another.
This concept is fundamental when analyzing systems like series circuits. In the context of the Christmas lights, each light's chance of failing is independent because one bulb's failure doesn't impact the vulnerability of another to fail.
This is an assumption often made in many real-world scenarios to simplify calculations.
Without this assumption of independence, the probability calculations would become much more complex and require additional information about how the bulbs influence each other.
Failure Probability
Failure probability refers to the likelihood that a certain event will not succeed.
In our lights scenario, each bulb has a failure probability of 0.02 over a three-year period.
Considering 20 bulbs, each with this 0.02 chance of failing, on their individual paths, simplifies our evaluation of the whole system. Key points about failure probability include:
  • It is always a value between 0 and 1.
  • A failure probability of 1 means certain failure, while 0 means no chance of failure.
  • This probability applies individually to each bulb in a series circuit, assuming independent failure events.
It's important to consider the failure probability individually before assessing the whole system's performance, especially in series setups where one failure impacts the whole system.
Complementary Probability
Complementary probability is a handy concept in probability theory.
It revolves around finding the likelihood of the non-occurrence of an event.
For any event with probability \( p \), the complementary event has a probability of \( 1 - p \).In the case of the Christmas lights, if each bulb has a failure probability of 0.02, then the probability that a bulb does **not** fail is its complementary probability.
So, we calculate it as:\[P(\text{not failing}) = 1 - 0.02 = 0.98\]This helps us determine the probability that each bulb will keep lighting up.
By using complementary probability, we focus on the bulbs' success rates rather than their failures, and this is what aids us in calculating for the whole series.
Series Circuit Failure Analysis
Analyzing series circuits in terms of failure probability is vital, particularly when one failure means the entire circuit ceases to work.
In a series circuit, like our Christmas light string, if one bulb fails, the entire string becomes non-functional.The calculation of the circuit's reliability involves assessing the probability that none of the components (bulbs) fail.
As the series circuit assumes all elements must function:Key concepts in a series circuit include:
  • The overall reliability or probability of function is the product of the individual probabilities of success.
  • If any single component has a high failure probability, it drastically affects the entire circuit's reliability.
The probability equation used:\[P(\text{all lights not failing}) = (0.98)^{20}\]calculates the chance that all 20 bulbs simultaneously work over three years.
Hence, analyzing series circuits involves focusing on enhancing individual components to secure the whole system's reliability.

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Most popular questions from this chapter

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