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Feeling sleepy? The first four students to arrive for a first-period statistics class were asked how much sleep (to the nearest hour) they got last night. Their responses were 7, 7, 9, and 9. (a) Find the standard deviation from its definition. That is, find the deviations of each observation from the mean, square the deviations, then obtain the variance and the standard deviation. (b) Interpret the value of sx you obtained in (a). (c) Do you think it’s safe to conclude that the mean amount of sleep for all 30 students in this class is close to 8 hours? Why or why not?

Short Answer

Expert verified
The standard deviation is approximately 1.15. It's not safe to assume the class mean is close to 8 hours due to the small, unrepresentative sample size.

Step by step solution

01

Calculate the Mean

To find the mean, sum all the values and divide by the number of values. The observations are 7, 7, 9, and 9. Calculate the mean (\( \bar{x} \)) as follows: \[ \bar{x} = \frac{7 + 7 + 9 + 9}{4} = \frac{32}{4} = 8 \]
02

Find Deviations from the Mean

Subtract the mean from each observation to find the deviations. For observations 7, 7, 9, and 9 with mean 8, the deviations are: \[ 7 - 8 = -1, \quad 7 - 8 = -1, \quad 9 - 8 = 1, \quad 9 - 8 = 1 \]
03

Square the Deviations

Square each of the deviations found in Step 2. The squared deviations are: \[ (-1)^2 = 1, \quad (-1)^2 = 1, \quad 1^2 = 1, \quad 1^2 = 1 \]
04

Calculate the Variance

Find the average of the squared deviations to calculate the variance. The variance \( s^2 \) is: \[ s^2 = \frac{1 + 1 + 1 + 1}{4 - 1} = \frac{4}{3} = 1.33 \]
05

Calculate the Standard Deviation

Find the square root of the variance to get the standard deviation \( s_x \). \[ s_x = \sqrt{1.33} \approx 1.15 \]
06

Interpret the Standard Deviation

The standard deviation of approximately 1.15 indicates that each student's sleep deviation from the mean of 8 hours is on average 1.15 hours.
07

Evaluate the Mean Estimate for the Class

It is not safe to conclude the mean sleep for all 30 students is close to 8 hours based on just four students' data. The sample size is too small and not necessarily representative of the entire class's sleep patterns.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean Calculation
To start off with mean calculation, take all the numbers from your dataset and add them up. This total sum represents a collective picture, encompassing all observations or data points. For instance, in our example, the sleep hours recorded by students are 7, 7, 9, and 9.

You sum these observations like so:
  • Add: 7 + 7 + 9 + 9 = 32.

With this sum in hand, you derive the mean by dividing it by the number of observations, which gives us:
  • Mean (\( \bar{x} \)) = \( \frac{32}{4} = 8 \).

This mean of 8 suggests that, on average, the four students got about 8 hours of sleep last night. The mean is often termed the 'average' and provides a basic sense of central tendency in data interpretation.
Variance
Once the mean is calculated, variance comes into play to tell us how spread out the data points are around this mean.

To find the variance, start by calculating how each observation deviates from the mean. Here, we consider the sleep times:
  • 7 - 8 = -1
  • 7 - 8 = -1
  • 9 - 8 = 1
  • 9 - 8 = 1

These figures represent the differences or deviations from the mean.

Now, square each of these deviations to eliminate negative numbers and give more weight to larger deviations:
  • (-1)\(^2\) = 1
  • (-1)\(^2\) = 1
  • (1)\(^2\) = 1
  • (1)\(^2\) = 1

The variance is the mean of these squared deviations, calculated as:
  • Variance (\( s^2 \)) = \( \frac{1 + 1 + 1 + 1}{4 - 1} = \frac{4}{3} = 1.33 \).

The value of 1.33 represents the average of those squared deviations, showing us how much the sleep data diverges from the mean.
Data Interpretation
The standard deviation is your friend when it comes to interpreting data. It takes the square root of that variance value you've calculated.

This makes the number much more relatable, as it's measured in the same units as the original data.
  • Standard Deviation (\( s_x \)) = \( \sqrt{1.33} \approx 1.15 \).

This result, approximately 1.15, reveals how much student sleep times typically deviate from the mean of 8 hours. In simpler terms, most students' sleep falls within a range of 1.15 hours above or below 8 hours.

However, when evaluating the class mean based on these four students, caution is advised. This small sample might not reflect the entire class's sleep habits accurately. It provides a useful snapshot but may not serve as a reliable summary for all 30 students.

Hence, while understanding deviation helps per individual response, one must carefully consider sample size in data interpretation.
Sample Size
Sample size plays a crucial role in any statistical analysis. It essentially decides how much weight your data's findings can carry when applied to a larger group.

For example, the mean sleep obtained from just four students is likely not representative of an entire class of 30. It's a small snapshot and might not account for varying sleep patterns seen across the classroom.

Larger sample sizes generally produce more trustworthy estimates because they are more likely to cover the diversity of the entire group. A small sample, on the other hand, could miss certain trends or significant variations in the data.
  • Think: a bigger sample size = better representation.
  • Small samples may not encompass full variability.

In practical terms, collecting data from more students could lead to a more reliable average sleep calculation, and hence more accurate conclusions could be drawn.

Always aim to ensure your sample size is sufficiently large to speak for the group you are investigating.

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