Chapter 2: Problem 41
If the HCF of the polynomials \(x^{3}+p x+q\) and \(x^{3}+r x^{2}+1 x+x\) is \(x^{2}+a x+b\), then their LCM is \((r \neq 0)\) (1) \(\left(x^{2}+a x+b\right)(x+a)(x+a-r)\) (2) \(\left(x^{2}+a x+b\right)(x-a)(x-a+r)\) (3) \(\left(x^{2}+a x+b\right)(x-a)(x-a-r)\) (4) \(\left(x^{2}-a x+b\right)(x-a)(x-a+r)\)
Short Answer
Step by step solution
Divide the polynomials by their HCF
Find the LCM
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Highest Common Factor (HCF)
In the given exercise, the HCF of the polynomials \(x^{3}+p x+q\) and \(x^{3}+r x^{2}+1 x+x\) is specified as \(x^{2}+a x+b\). This means that \(x^{2}+a x+b\) is the largest polynomial that fits into both of the given polynomials with no remainder left behind.
- To determine the validity of this HCF, polynomial division is typically employed to check how it divides each polynomial.
- Understanding and determining the HCF is crucial as it simplifies polynomial expressions and is a foundational step towards finding the Least Common Multiple (LCM).
Least Common Multiple (LCM)
For the exercise, knowing the HCF allows us to find the LCM. The relationship is straightforward: the product of two polynomials equals the product of their HCF and LCM.
This relationship is expressed as:
\[(x^3 + px + q) \times (x^3 + rx^2 + x + x) = (x^2 + ax + b) \times LCM\]
By dividing each polynomial by the HCF, the remaining factors can be multiplied with the HCF to give the LCM. This ensures that both original polynomials can divide evenly.
- Finding the LCM helps in operations like adding, subtracting, or finding the common solutions of polynomial equations.
- LCM calculation relies heavily on accurate HCF determination and polynomial division.
Polynomial Division
In the exercise, we divide the given polynomials \(x^{3}+p x+q\) and \(x^{3}+r x^{2}+1 x+x\) by their HCF, \(x^{2}+a x+b\), to find the leftover factors and help in finding the LCM.
- Divide the highest degree terms first, adjust and subtract, and repeat the process for the resulting polynomials.
- The division continues until a remainder that's lower than the divisor, in degree, is obtained, or ideally zero in the case of the HCF correctly dividing them.
Factorization in Algebra
For instance:
- The result of dividing the polynomials by an HCF can lead to factors \(A(x)\) and \(B(x)\), which when multiplied by their HCF, reconstructs the polynomials.
- Factorization makes it easier to solve polynomial equations or to find LCMs by providing a clear multiplication path through its linear factors.