Chapter 11: Problem 16
If \((x+1)\) and \((x-1)\) are the factors of \(a x^{3}+b x^{2}+c x+d\), then which of the following is true? (1) \(\mathrm{a}+\mathrm{b}=0\) (2) \(\mathrm{b}+\mathrm{c}=0\) (3) \(\mathrm{b}+\mathrm{d}=0\) (4) None of these
Short Answer
Expert verified
(1) a + b = 0
(2) b + c = 0
(3) b + d = 0
Answer: (3) b + d = 0
Step by step solution
01
Expand the Polynomial
Since \((x+1)\) and \((x-1)\) are the factors of the given polynomial, we can write the polynomial as \((x+1)(x-1)(kx+m)\), where k and m are constants which will allow the polynomial to match the given coefficients. Firstly, we need to expand the given factorized polynomial:
\((x+1)(x-1)(kx+m) = (x^2-1)(kx+m)\)
02
Distribute the Terms
Now distribute each term from \((kx+m)\) to \((x^2-1)\):
\((kx+m)(x^2-1) = kx(x^2-1) + m(x^2-1)\)
03
Simplify the Expression
Expand the terms:
\(kx(x^2-1) + m(x^2-1) = kx^3 - kx + mx^2 - m\)
Now, we can write the entire polynomial as:
\(P(x) = ax^3 + bx^2 + cx + d = kx^3 + mx^2 - kx - m\)
04
Compare Coefficients
Compare the coefficients in \(P(x)\) with the given polynomial:
\(a = k\)
\(b = m\)
\(c = -k\)
\(d = -m\)
Since we are looking for a relationship between the coefficients a, b, c, and d, let's analyze the given statements:
05
Statement 1
If statement 1 is true, then \(a+b=0\). Substitute the coefficients:
\(k + m = 0\)
06
Statement 2
If statement 2 is true, then \(b+c=0\). Substitute the coefficients:
\(m - k = 0\)
07
Statement 3
If statement 3 is true, then \(b+d=0\). Substitute the coefficients:
\(m - m = 0\)
We can see that:
1. Statement 1 is true for k=-m, which is not necessarily true for any cubic polynomial.
2. Statement 2 is true for k=m, which may turn out to be true after further analysis.
3. Statement 3 is always true.
08
Conclusion
From our analysis, we can see that statement 3 is true for any given cubic polynomial with the factors \((x+1)\) and \((x-1)\). Thus, the correct answer is:
(3) \(b+d=0\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cubic Polynomial
A cubic polynomial is an algebraic expression of the form \( ax^3 + bx^2 + cx + d \), where \( a eq 0 \). This type of polynomial is called 'cubic' because the highest exponent is 3. Cubic polynomials play a fundamental role in various mathematical computations since they can describe complex relationships and models.
Understanding the structure of a cubic polynomial is important for factorization, solving equations, and modeling different scenarios. Each term of a cubic polynomial contributes to its shape when graphed, and the coefficients \( a, b, c, \) and \( d \) each have their own influence. For instance:
Understanding the structure of a cubic polynomial is important for factorization, solving equations, and modeling different scenarios. Each term of a cubic polynomial contributes to its shape when graphed, and the coefficients \( a, b, c, \) and \( d \) each have their own influence. For instance:
- \( a \) affects the width and direction of the curve.
- \( b \) modifies the shape and location of the inflection point.
- \( c \) adjusts the asymmetry of the curve.
- \( d \) stands for the y-intercept, shifting the graph vertically.
Coefficients Comparison
Coefficients comparison is a method used to find the values of unknown parameters in a polynomial equation. By comparing corresponding coefficients from both sides of a polynomial equation, one can derive equations that involve these unknown parameters. In this particular exercise, you learned how to use coefficients comparison to relate the given polynomial \( ax^3 + bx^2 + cx + d \) to its factorized counterpart.
In this process, notice how we substitute the coefficients from our expanded polynomial \( kx^3 + mx^2 - kx - m \) into \( ax^3 + bx^2 + cx + d \):
In this process, notice how we substitute the coefficients from our expanded polynomial \( kx^3 + mx^2 - kx - m \) into \( ax^3 + bx^2 + cx + d \):
- \( a = k \)
- \( b = m \)
- \( c = -k \)
- \( d = -m \)
Factor Theorem
The Factor Theorem is a principal that provides a straightforward way to ascertain whether a linear expression is a factor of a given polynomial. According to the theorem, for a polynomial \( f(x) \), if \( f(a) = 0 \), then \( (x-a) \) is a factor of \( f(x) \). In this exercise, you were given two factors, \((x+1) \) and \( (x-1) \), meaning "\( x = -1 \)" and "\( x = 1 \)" are roots of the cubic polynomial \( ax^3 + bx^2 + cx + d \).
Using the Factor Theorem in this context, we factor the cubic polynomial into \((x+1)(x-1)(kx+m)\) to demonstrate that \((x+1)\) and \((x-1)\) are factors.
The Factor Theorem is incredibly helpful for:
Using the Factor Theorem in this context, we factor the cubic polynomial into \((x+1)(x-1)(kx+m)\) to demonstrate that \((x+1)\) and \((x-1)\) are factors.
The Factor Theorem is incredibly helpful for:
- **Finding roots of polynomials:** With roots like \(-1\) and \(1\), it becomes easier to factor and solve polynomials efficiently.
- **Simplifying polynomial expressions:** Breaking down a polynomial into simpler factors allows easier manipulation and solution finding.
- **Helpful in higher-degree polynomial factorization:** Understanding which values cause the polynomial to become zero makes it easier to attempt further factorization into simpler components.