/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 215 Given a spherical triangle \(\tr... [FREE SOLUTION] | 91Ó°ÊÓ

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Given a spherical triangle \(\triangle A B C\) on the unit sphere with centre \(O,\) such that \(\angle B A C\) is a right angle, and such that \(\underline{A B}\) has length \(c\), and \(A C\) has length \(b\). (a) We have (rightly) referred to \(b\) and \(c\) as 'lengths'. But what are they really? (b) We want to know how the inputs \(b\) and \(c\) determine the value of the length \(a\) of the arc \(\underline{B C} ;\) that is, we are looking for a function with inputs \(b\) and \(c\), which will allow us to determine the value of the "output" \(a\). Think about the answer to part (a). What kind of standard functions do we already know that could have inputs \(b\) and \(c ?\) (c) Suppose \(c=0 \neq b\). What should the output \(a\) be equal to? (Similarly if \(b=0 \neq c .)\) Which standard function of \(b\) and of \(c\) does this suggest is involved? (d)(i) Suppose \(\angle B=\angle C=\frac{\pi}{2},\) what should the output \(a\) be equal to? (ii) Suppose \(\angle B=\frac{\pi}{2},\) but \(\angle C\) (and hence \(c\) ) is unconstrained. The output \(a\) is then determined \(-\) but the formula must give this fixed output for different values of \(c\). What does this suggest as the "simplest possible" formula for \(a ?\)

Short Answer

Expert verified
(a) Angular distances subtended at the sphere's center. (b) Use spherical cosine rule: \( \cos(a) = \cos(b) \cdot \cos(c) \). (c) \( a = b \) if \( c = 0 \), and \( a = c \) if \( b = 0 \). (d) Use \( \cos(a) = \cos(b) \cdot \cos(c) \).

Step by step solution

01

Determine the Spherical Lengths

In the context of a unit sphere, the lengths \( b \) and \( c \) represent angular distances rather than traditional linear distances. These are the central angles (or arc lengths) subtended by the chords \( AC \) and \( AB \), respectively, from the center of the sphere (point \( O \)).
02

Consider Known Functions Relating Inputs

Considering the right spherical triangle \( \triangle ABC \), where \( \angle BAC = \frac{\pi}{2} \), we can use spherical trigonometry. A suitable relationship involving \( b \), \( c \), and \( a \) could be the spherical Pythagorean theorem: \( \cos(a) = \cos(b) \cdot \cos(c) \).
03

Evaluate Special Case When c=0

If \( c = 0 \) and \( b eq 0 \), it implies point \( A \) and \( B \) are identical, thus \( BC \) should be exactly the arc \( AC \), which means \( a = b \). As \( c = \cos(c) = 1 \), this simplifies into the function \( \cos(a) = \cos(b) \).
04

Evaluate Special Case When b=0

Similarly, if \( b = 0 \) and \( c eq 0 \), then point \( A \) and \( C \) are identical and \( BC \) should equal \( AB \). So, \( a = c \). As in Step 3, this confirms \( \cos(a) = \cos(c) \).
05

Analyze \( \angle B = \angle C = \frac{\pi}{2} \)

In this case, triangle \( ABC \) would be a quarter of a great circle, so \( a = \frac{bound to be \frac{\pi}{2} \). This suggests the formula must account for both being fixed, likely indicating \( \cos(a) = 0 \).
06

Generalize the Formula

Suppose \( \angle B = \frac{\pi}{2} \) with \( c \) unconstrained. Consider the simplest formula that always resolves to a consistent output for known constraints: the spherical Pythagorean theorem \( \cos(a) = \cos(b) \cdot \cos(c) \) meets all conditions from varying lengths of arcs.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Spherical Trigonometry
Spherical trigonometry is a branch of geometry that deals with the relationships between spherical triangles situated on the surface of a sphere. Unlike planar trigonometry, which works with flat surfaces, spherical trigonometry addresses the complexities that come with curved surfaces.
Spherical triangles are formed by the intersection of three great circle arcs, the shortest path between two points on a sphere, and they behave differently than their flat counterparts:
  • Angles in a spherical triangle can sum to more than 180 degrees.
  • The sides of a spherical triangle are measured as angles subtended at the sphere's center, also known as angular distances.
Understanding spherical trigonometry is essential for navigating this curved space, and it uses special laws and theorems, like the spherical Pythagorean theorem, to relate the sides and angles of spherical triangles.
Spherical Triangle
A spherical triangle is a figure formed on the surface of a sphere by three intersecting great circle arcs. These triangles differ notably from their planar counterparts:
  • They have three vertices and sides measured in angular distances, rather than in length.
  • Each side of a spherical triangle is part of a great circle, effectively a circle that divides the sphere into two equal hemispheres.
The characteristics of spherical triangles make them unique in geometry:
  • The sum of the internal angles is greater than 180 degrees.
  • They are an integral part of calculations in navigation, astronomy, and geophysics, where the curvature of the Earth (or other celestial bodies) needs to be considered.
Thus, spherical triangles are a crucial concept in understanding how geometry operates on curved surfaces.
Angular Distance
In spherical geometry, the concept of distance takes a different form; here, the distance between two points on a sphere is measured by the angle subtended by the shortest path, or arc, between them. This arc is part of a great circle.
  • Angular distance is measured in radians or degrees and represents the angle at the center of the sphere subtended by an arc between two points on the sphere's surface.
  • This measurement of distance reflects the curved nature of the sphere, offering a more accurate depiction of distance over a spherical surface than linear measurement.
Angular distance is vital in fields such as astronomy and aviation, where knowing the accurate separation between two points on a spherical body, like stars or planets, is crucial.
Spherical Pythagorean Theorem
The spherical Pythagorean theorem offers a way to relate the sides of a right spherical triangle. It is similar to the traditional Pythagorean theorem from flat geometry, but adapted to address the curvature of spheres.
  • In the right spherical triangle, where one angle is 90 degrees, the theorem states: \( \cos(a) = \cos(b) \cdot \cos(c) \).
  • Here, \( a \), \( b \), and \( c \) are angular distances (arc lengths) opposite corresponding vertices.
  • This relationship helps to calculate the unknown side of a spherical triangle when the lengths of the other sides are known.
The spherical Pythagorean theorem is crucial when solving problems involving spherical triangles, making it invaluable in understanding complex geometrical relationships on spherical surfaces.

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Most popular questions from this chapter

Consider the cube with edges of length 2 running parallel to the coordinate axes, with its centre at the origin \((0,0,0),\) and with opposite corners at (1,1,1) and (-1,-1,-1) . The \(x-, y-,\) and \(z\) -axes, and the \(x y\) -, \(y z-,\) and \(z x\) -planes cut this cube into eight unit cubes \(-\) one sitting in each octant. (i) Let \(A=(0,0,1), B=(1,0,0), C=(0,1,0), W=(1,1,1) .\) Describe the solid \(A B C W\) (ii) Let \(D=(-1,0,0), X=(-1,1,1) .\) Describe the solid \(A C D X\). (iii) Let \(E=(0,-1,0), Y=(-1,-1,1) .\) Describe the solid \(A D E Y\). (iv) Let \(Z=(1,-1,1) .\) Describe the solid \(A E B Z\). (v) Let \(F=(0,0,-1)\) and repeat steps (i)-(iv) to obtain the four mirror image solids which lie beneath the \(x y\) -plane. (vi) Describe the solid \(A B C D E F\) which is surrounded by the eight identical solids in (i)-(v).

The twelve hour marks for a clock are marked on the circumference of a unit circle to form the vertices of a regular dodecagon ABCDEFGHIJKL. Calculate exactly (i.e. using Pythagoras' Theorem rather than trigonometry) the lengths of all the possible line segments joining two vertices of the dodecagon.

(a) Find a formula for the surface area of a right circular cone with base of radius \(r\) and slant height \(l\). (b) Find a similar formula for the surface area of a right pyramid with apex \(A\) whose base \(B C D E \cdots\) is a regular \(n\) -gon with inradius \(r\).

Let \(A B C D\) be a trapezium with \(A B \| D C,\) in which \(A B\) has length \(a\) and \(D C\) has length \(b\). (a) Let \(M\) be the midpoint of \(\underline{A D}\) and let \(N\) be the midpoint of \(\underline{B C}\). Prove that \(M N \| A B\) and find the length of \(\underline{M N}\). (b) If the perpendicular distance between \(A B\) and \(D C\) is \(d,\) find the area of the trapezium \(A B C D\).

The point \(P\) lies inside a circle. Two secants from \(P\) meet the circle at \(A, B\) and at \(C, D\) respectively. Prove that $$\underline{P A} \times \underline{P B}=\underline{P C} \times \underline{P D}$$ We end our summary of the foundations of Euclidean geometry by deriving the familiar formula for the area of a trapezium and its 3-dimensional analogue, and a formulation of the similarity criteria which is often attributed to Thales (Greek \(6^{\text {th }}\) century BC).

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