/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 Forward stepwise regression. Sup... [FREE SOLUTION] | 91影视

91影视

Forward stepwise regression. Suppose we have the QR decomposition for the \(N \times q\) matrix \(\mathbf{X}_{1}\) in a multiple regression problem with response \(\mathbf{y}\), and we have an additional \(p-q\) predictors in the matrix \(\mathbf{X}_{2}\). Denote the current residual by \(\mathbf{r}\). We wish to establish which one of these additional variables will reduce the residual- sum-of squares the most when included with those in \(\mathbf{X}_{1}\). Describe an efficient procedure for doing this.

Short Answer

Expert verified
Answer: To determine the predictor in 饾憢2 that will reduce the residual-sum-of squares the most when included with those in 饾憢1, follow these steps: 1. Compute the residual vector 饾憻 using the QR decomposition of 饾憢1 and the given response vector 饾懄. 2. Perform forward stepwise regression starting with a model containing the predictors in 饾憢1. 3. Evaluate the reduction in RSS for each variable in 饾憢2 by adding it to the model (with predictors in 饾憢1) and calculating the new RSS. 4. Find the variable in 饾憢2 that results in the highest reduction in RSS when added to the model with predictors in 饾憢1. This predictor will reduce the residual-sum-of squares the most when included with those in 饾憢1.

Step by step solution

01

Understand QR decomposition and residuals

QR decomposition is a method to decompose a matrix 饾憢 into the product of an orthogonal matrix 饾憚 and an upper triangular matrix 饾憛. It has applications in solving linear least squares problems such as multiple regression. An orthogonal matrix is a matrix whose columns are orthonormal vectors, meaning their dot product is 0 and their norms (lengths) are 1. In our case, we have the QR decomposition of 饾憢1. The residual in a multiple regression problem is the difference between the observed values of the dependent variable (饾懄) and the predicted values of the dependent variable. The residual-sum-of squares (RSS) measures the overall difference between the observed and predicted values.
02

Compute the residual 饾憻

Compute the residual vector 饾憻 as follows: 1. Multiply 饾憢1 by its QR decomposition: 饾憢1 = 饾憚饾憛 2. Calculate the predicted values of 饾懄: 饾懄虃 = 饾憢1饾浗饾憥 3. Compute the residual vector 饾憻: 饾憻 = 饾懄 - 饾懄虃
03

Forward stepwise regression

Forward stepwise regression is a feature selection technique whereby multiple linear regression models are fit by iteratively including a new predictor variable that reduces the RSS the most. Start with a model containing the predictors in 饾憢1 to perform forward stepwise regression. 1. Fit the multiple regression model with predictors in 饾憢1. 2. Evaluate the residuals and RSS obtained at each step. Denote the current residual by 饾憻.
04

Evaluate the contribution of each additional predictor

For each variable in 饾憢2, perform the following: 1. Add the predictor to the model (with predictors in 饾憢1) and calculate the RSS for the new model. 2. Compute the reduction in RSS compared to the model with only predictors in 饾憢1.
05

Determine the best predictor

Find the variable in 饾憢2 that results in the highest reduction in RSS when added to the model with predictors in 饾憢1. This predictor is the one that will reduce the residual-sum-of squares the most when included with those in 饾憢1.
06

Update the model

Include the best predictor found in Step 5 to the model containing predictors in 饾憢1, and compute the new RSS. This updated model will now have the additional predictor from 饾憢2 which contributes to the greatest reduction in the residual-sum-of squares.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

QR decomposition
QR decomposition is a powerful technique in linear algebra used to break down a matrix into two specific matrices: an orthogonal matrix, known as \( Q \), and an upper triangular matrix, referred to as \( R \). This decomposition helps simplify the process of solving linear equations, especially in the context of least squares problems like multiple regression.
For any given matrix \( X \), QR decomposition allows us to express \( X \) as the product of \( Q \) and \( R \): \( X = QR \). Here, the orthogonal matrix \( Q \) consists of orthonormal columns, meaning each column vector has a length of one and all are perpendicular to each other. Meanwhile, the upper triangular matrix \( R \) contains non-zero elements solely on the diagonal and above. This decomposition is not only useful for simplifying matrices but also enhances numerical stability.
In multiple regression, QR decomposition enables efficient computation of regression coefficients by simplifying the systems of equations. This makes it particularly handy when dealing with large datasets or when precision is important.
  • Decomposes matrix into \( Q \) (orthogonal) and \( R \) (upper triangular)
  • Useful for solving least squares problems
  • Provides numerical stability
  • Residual-sum-of-squares
    The Residual-Sum-of-Squares (RSS) is a crucial metric in regression analysis. It gauges the deviation between observed values and those predicted by a regression model. More simply, it tells us how well the model fits the available data.
    Whenever a regression model is constructed, the difference between each observed value of the dependent variable and its corresponding predicted value is called a residual. By squaring these residuals and summing them up, we get the RSS. This squared aspect ensures negative differences don't offset positive ones, giving a clear measure of total deviation.
    Minimizing RSS is a primary goal in regression models since it indicates a better fit. The smaller the RSS, the closer the predicted values are to the observed ones, implying the model is more accurate. In the context of forward stepwise regression, adding predictors that effectively lower the RSS can significantly enhance the model's performance.
    • Measures model accuracy by assessing fit
    • Smaller RSS indicates a better fit
    • Used in feature selection to improve models
    Multiple regression
    Multiple regression is a statistical method that explores the relationship between a single dependent variable and multiple independent variables. It's an extension of simple linear regression, which only involves one independent variable. Using multiple regression, we aim to predict an outcome based on several predictors, making it highly applicable in many fields like economics, engineering, and social sciences.
    The multiple regression equation takes the form: \( Y = \beta_0 + \beta_1 X_1 + \beta_2 X_2 + \ldots + \beta_p X_p + \epsilon \), where \( Y \) is the dependent variable, \( X_1, X_2, ... X_p \) denote independent variables, \( \beta_0 \) is the intercept, \( \beta_1, \beta_2, ... \beta_p \) are the coefficients, and \( \epsilon \) represents the error term.
    Multiple regression's ability to control for various factors simultaneously makes it invaluable for examining complex datasets. It lets researchers understand which variables significantly influence the dependent variable and helps in predicting future trends or behaviors.
    In stepwise regression, multiple regression is repeatedly refined by adding variables that most improve the model's predictive power, often judged by reducing the RSS.
    • Models relationships involving multiple predictors
    • Form: \( Y = \beta_0 + \beta_1 X_1 + \ldots + \beta_p X_p + \epsilon \)
    • Useful for examining complex datasets

    One App. One Place for Learning.

    All the tools & learning materials you need for study success - in one app.

    Get started for free

    Most popular questions from this chapter

    Gauss-Markov theorem: (a) Prove the Gauss-Markov theorem: the least squares estimate of a parameter \(a^{T} \beta\) has variance no bigger than that of any other linear unbiased estimate of \(a^{T} \beta\) (Section 3.2.2). (b) The matrix inequality \(\mathbf{B} \preceq \mathbf{A}\) holds if \(\mathbf{A}-\mathbf{B}\) is positive semidefinite. Show that if \(\hat{\mathbf{V}}\) is the variance-covariance matrix of the least squares estimate of \(\beta\) and \(\tilde{\mathbf{V}}\) is the variance-covariance matrix of any other linear unbiased estimate, then \(\hat{\mathbf{V}} \preceq \tilde{\mathbf{V}}\).

    Consider the canonical-correlation problem (3.67). Show that the leading pair of canonical variates \(u_{1}\) and \(v_{1}\) solve the problem $$ \max _{u^{T}\left(\mathbf{Y}^{T} \mathbf{Y}\right) u=1 \atop{ }^{v}\left(\mathbf{X}^{T} \mathbf{X}\right) v=1} u^{T}\left(\mathbf{Y}^{T} \mathbf{X}\right) v, $$ a generalized SVD problem. Show that the solution is given by \(u_{1}=\) \(\left(\mathbf{Y}^{T} \mathbf{Y}\right)^{-\frac{1}{2}} u_{1}^{*}\), and \(v_{1}=\left(\mathbf{X}^{T} \mathbf{X}\right)^{-\frac{1}{2}} v_{1}^{*}\), where \(u_{1}^{*}\) and \(v_{1}^{*}\) are the leading left and right singular vectors in $$ \left(\mathbf{Y}^{T} \mathbf{Y}\right)^{-\frac{1}{2}}\left(\mathbf{Y}^{T} \mathbf{X}\right)\left(\mathbf{X}^{T} \mathbf{X}\right)^{-\frac{1}{2}}=\mathbf{U}^{*} \mathbf{D}^{*} \mathbf{V}^{* T} . $$ Show that the entire sequence \(u_{m}, v_{m}, m=1, \ldots, \min (K, p)\) is also given by (3.87).

    Consider the elastic-net optimization problem: $$ \min _{\beta}\|\mathbf{y}-\mathbf{X} \beta\|^{2}+\lambda\left[\alpha\|\beta\|_{2}^{2}+(1-\alpha)\|\beta\|_{1}\right] $$ Show how one can turn this into a lasso problem, using an augmented version of \(\mathbf{X}\) and \(\mathbf{y}\).

    Show that the \(F\) statistic (3.13) for dropping a single coefficient from a model is equal to the square of the corresponding \(z\)-score \((3.12)\)

    Consider a regression problem with all variables and response having mean zero and standard deviation one. Suppose also that each variable has identical absolute correlation with the response: $$ \frac{1}{N}\left|\left\langle\mathbf{x}_{j}, \mathbf{y}\right\rangle\right|=\lambda, j=1, \ldots, p $$ Let \(\hat{\beta}\) be the least-squares coefficient of \(\mathbf{y}\) on \(\mathbf{X}\), and let \(\mathbf{u}(\alpha)=\alpha \mathbf{X} \hat{\beta}\) for \(\alpha \in[0,1]\) be the vector that moves a fraction \(\alpha\) toward the least squares fit u. Let \(R S S\) be the residual sum-of-squares from the full least squares fit. (a) Show that $$ \frac{1}{N}\left|\left\langle\mathbf{x}_{j}, \mathbf{y}-\mathbf{u}(\alpha)\right\rangle\right|=(1-\alpha) \lambda, j=1, \ldots, p $$ and hence the correlations of each \(\mathbf{x}_{j}\) with the residuals remain equal in magnitude as we progress toward \(\mathbf{u}\). (b) Show that these correlations are all equal to $$ \lambda(\alpha)=\frac{(1-\alpha)}{\sqrt{(1-\alpha)^{2}+\frac{\alpha(2-\alpha)}{N} \cdot R S S}} \cdot \lambda $$ and hence they decrease monotonically to zero. (c) Use these results to show that the LAR algorithm in Section 3.4.4 keeps the correlations tied and monotonically decreasing, as claimed in (3.55).

    See all solutions

    Recommended explanations on Math Textbooks

    View all explanations

    What do you think about this solution?

    We value your feedback to improve our textbook solutions.

    Study anywhere. Anytime. Across all devices.