Chapter 3: Problem 9
Find the derivative of the given function. $$ g(x)=(2 x-5)^{-1}(4 x+3)^{-2} $$
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Chapter 3: Problem 9
Find the derivative of the given function. $$ g(x)=(2 x-5)^{-1}(4 x+3)^{-2} $$
These are the key concepts you need to understand to accurately answer the question.
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Differentiate the given function by applying the theorems of this section. $$ f(x)=\frac{x^{2}-a^{2}}{x^{2}+a^{2}} $$
A particle is moving along a straight line according to the given equation of motion, where \(s\) \(\mathrm{ft}\) is the directed distance of the particle from the origin at \(t \mathrm{sec}\). Find the time when the instantaneous acceleration is zero, and then find the directed distance of the particle from the origin and the instantaneous velocity at this instant. $$ s=\frac{125}{16 t+32}-\frac{2}{5} t^{5}, t \geq 0 $$
Find an equation of the tangent line to the curve \(y=\sqrt{4 x-3}-1\) that is perpendicular to the line \(x+2 y-11=0\).
A particle is moving along a horizontal line according to the given equation of motion, where \(s \mathrm{ft}\) is the directed distance of the particle from a point \(O\) at \(t \mathrm{sec}\). Find the instantaneous velocity \(v\left(t_{1}\right) \mathrm{ft} / \mathrm{sec}\) at \(t_{1} \mathrm{sec}\); and then find \(v\left(t_{1}\right)\) for the particular value of \(t_{1}\) given. $$ s=\frac{2}{\sqrt{5 t+6}} ; t_{1}=2 $$
If a ball is given a push so that it has an initial velocity of \(24 \mathrm{ft} / \mathrm{sec}\) down a certain inclined plane, then \(s=24 t+10 t^{2}\), where \(s \mathrm{ft}\) is the distance of the ball from the starting point at \(t \mathrm{sec}\) and the positive direction is down the inclined plane. (a) What is the instantaneous velocity of the ball at \(t_{1}\) sec? (b) How long does it take for the velocity to increase, to \(48 \mathrm{ft} / \mathrm{sec} ?\)
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