Chapter 3: Problem 13
Find the derivative of the given function. $$ f(x)=\frac{2}{7 x^{2}+3 x-1} $$
Short Answer
Expert verified
The derivative is \(\frac{-28x - 6}{(7x^{2}+3x-1)^2}\).
Step by step solution
01
Identify the Function and the Rule to Use
Notice that the given function is in the form of a fraction. Therefore, the best way to differentiate this function is by using the quotient rule. The quotient rule states that if you have a function in the form \(\frac{u}{v}\), then the derivative is given by \(\frac{u'v - uv'}{v^2}\). Here, \(u=2\) and \(v=7x^{2}+3x-1\).
02
Compute the Derivative of the Numerator
The numerator \(u\) is a constant, 2. The derivative of a constant is zero. Therefore, \(u'=0\).
03
Compute the Derivative of the Denominator
The denominator \(v\) is \(7x^{2}+3x-1\). Its derivative \(v'\) can be found by applying the power rule to each term: \[v' = \frac{d}{dx}(7x^2) + \frac{d}{dx}(3x) - \frac{d}{dx}(1) = 14x + 3\]
04
Apply the Quotient Rule
Substitute \(u, u', v,\) and \(v'\) into the quotient rule formula: \(\frac{u'v - uv'}{v^2}\). Therefore, \[f'(x) = \frac{(0)(7x^{2}+3x-1) - (2)(14x+3)}{(7x^{2}+3x-1)^2} = \frac{-28x - 6}{(7x^{2}+3x-1)^2}\]
05
Simplify the Result
Finally, write the simplified form of the derivative: \[\boxed{f'(x) = \frac{-28x - 6}{(7x^{2}+3x-1)^2}}\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quotient Rule
When dealing with functions in the form of a fraction, it's essential to use the quotient rule for differentiation. The quotient rule provides a way to find the derivative of a quotient of two functions. If you have a function in the form \(\frac{u}{v}\), the quotient rule states: \[\frac{d}{dx} \bigg( \frac{u}{v} \bigg) = \frac{u'v - uv'}{v^2}\] Here, \(u\) and \(v\) are functions of \(x\), and \(u'\) and \(v'\) are their respective derivatives. To apply the quotient rule, follow these steps:
- Differentiate \(u\) and denote it as \(u'\).
- Differentiate \(v\) and denote it as \(v'\).
- Substitute the values of \(u, u', v\), and \(v'\) into the quotient rule formula.
- Simplify the resulting expression.
Power Rule
The power rule is a fundamental tool in differentiation. It provides a straightforward way to differentiate terms of the form \(ax^n\). The rule states: \[\frac{d}{dx}(ax^n) = anx^{n-1}\] where \(a\) is a constant and \(n\) is the exponent. To apply the power rule, follow these steps:
- Identify the exponent \(n\) and the constant \(a\).
- Multiply \(a\) by \(n\).
- Reduce the exponent by 1.
Differentiation
Differentiation is a process in calculus used to find the rate of change of a function. It is one of the core concepts and techniques you will use in calculus. Here's a quick breakdown:
Finally, we simplified our result to the final derivative:
\[ f'(x) = \frac{-28x - 6}{(7x^{2}+3x-1)^2}\] Remember, practice is key to mastering differentiation. By breaking problems into smaller steps, applying the correct rules, and simplifying, you will become more confident in solving these types of problems.
- It measures how a function changes as its input changes.
- The derivative is the function that describes this rate of change.
- Different rules apply based on the function's form (e.g., product rule, chain rule, power rule, and quotient rule).
- Used the power rule to differentiate the polynomial in the denominator.
- Applied the quotient rule to find the derivative of the entire fraction.
Finally, we simplified our result to the final derivative:
\[ f'(x) = \frac{-28x - 6}{(7x^{2}+3x-1)^2}\] Remember, practice is key to mastering differentiation. By breaking problems into smaller steps, applying the correct rules, and simplifying, you will become more confident in solving these types of problems.