Chapter 16: Problem 22
Suppose \(f\) is a function such that \(f(n)>0\) for \(n\) any positive integer. Furthermore, suppose that if \(p\) is any positive number \(\lim _{n \rightarrow+\infty} n^{p} f(n)\) exists and is positive. Prove that the series \(\sum_{n=1}^{+\infty} f(n)\) is convergent if \(p>1\) and divergent if \(0
Short Answer
Expert verified
The series \( \sum_{n=1}^{+\infty} f(n) \) converges if \( p > 1 \) and diverges if \( 0 < p \leq 1 \).
Step by step solution
01
- Understand the conditions
First, identify the conditions given in the problem. We are given that the function \( f(n) > 0 \) for any positive integer \( n \), and that the limit \( \lim _{n \rightarrow+\infty} n^{p} f(n) \) exists and is positive for any positive number \( p \).
02
- Apply the given limit condition
Use the given limit condition \( \lim_{n \to \infty} n^p f(n) = L > 0 \), which suggests that for large \( n \), \( f(n) \) behaves like \( \frac{L}{n^p} \). This gives us an idea of the general behavior of \( f(n) \).
03
- Test the convergence of the series when \( p > 1 \)
Consider the series \( \sum_{n=1}^{+\infty} f(n) \). If \( p > 1 \), then \( f(n) \approx \frac{L}{n^p} \). The series \( \sum_{n=1}^{+\infty} \frac{1}{n^p} \) is a p-series, which is known to converge when \( p > 1 \). Hence, the series \( \sum_{n=1}^{+\infty} f(n) \) converges when \( p > 1 \).
04
- Test the divergence of the series when \( 0 < p \leq 1 \)
Now, consider the series \( \sum_{n=1}^{+\infty} f(n) \) when \( 0 < p \leq 1 \). If \( 0 < p \leq 1 \), \( f(n) \approx \frac{L}{n^p} \). The series \( \sum_{n=1}^{+\infty} \frac{1}{n^p} \) is also a p-series, and it is known to diverge when \( 0 < p \leq 1 \). Therefore, the series \( \sum_{n=1}^{+\infty} f(n) \) diverges when \( 0 < p \leq 1 \).
05
- Summarize the results
We have shown that for \( p > 1 \), the series \( \sum_{n=1}^{+\infty} f(n) \) converges, and for \( 0 < p \leq 1 \), the series \( \sum_{n=1}^{+\infty} f(n) \) diverges based on the behavior of the corresponding p-series.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
p-series
A p-series is a type of infinite series that takes the form The behavior of the p-series largely depends on the value of the exponent \(p\). These series take the general form \(\sum_{n=1}^{+\infty} \frac{1}{n^p}\). p-series are very important when studying the convergence and divergence of series. The convergence or divergence of a p-series is determined by the exponent \(p\):
- If \(p > 1\), the series converges.
- If \(0 < p \leq 1\), the series diverges.
limit behavior
The concept of the limit is fundamental in understanding the behavior of functions as they approach a specific value. In this scenario, the problem statement introduces the limit condition for the behavior of the function \(f(n)\), \( \lim_{n\to \infty} n^p f(n) = L > 0 \). This limit tells us how \(f(n)\) behaves as \(n\) becomes very large. With \(L\) being a positive number, it means \(f(n)\) behaves approximately like \(\frac{L}{n^p}\) for large \(n\). This limit condition helps us compare the function \(f(n)\) directly with p-series, as previously discussed. This behavior can be generalized as:
- For large values of \(n\), \(f(n) \approx \frac{L}{n^p}\)
convergence and divergence criteria
Determining whether a series converges or diverges is fundamental in the study of calculus. In this exercise, we used the convergence and divergence criteria specific to p-series to show the behavior of \(\sum_{n=1}^\infty f(n)\). Knowing the criteria involved:
- For p-series \(\sum_{n=1}^{+\infty} \frac{1}{n^p}\):
- Convergence if \(p > 1\)
- Divergence if \(0 < p \leq 1\)
- If a series resembles a p-series closely enough, these criteria can apply.
positive functions in series
In this exercise, the function \(f(n)\) is explicitly defined as being positive for all positive integers \(n\). This is a crucial detail as it ensures that we are dealing with a series of positive terms. Dealing with positive functions in series simplifies the application of convergence tests:
- Positive terms ensure that comparison tests, p-series tests, and other convergence tests can be straightforwardly applied.
- This guarantees that if a positive series diverges, it does so because the partial sums grow indefinitely.