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If two corridors at right angles to each other are \(10 \mathrm{ft}\) and \(15 \mathrm{ft}\) wide, respectively, what is the length of the longest steel girder that can be moved horizontally around the corner? Neglect the horizontal width of the girder.

Short Answer

Expert verified
The length of the longest steel girder that can be moved is approximately 18.03 feet.

Step by step solution

01

- Visualize the Problem

Visualize the two corridors forming a right angle. One corridor is 10 feet wide and the other is 15 feet wide. The goal is to find the longest steel girder that can be moved around the corner.
02

- Understand the Geometric Constraint

Assume the girder moves tangentially to the corner where the two corridors meet. When in the position that makes the girder its longest, it will form a right triangle with the corridor widths as legs.
03

- Apply Geometry

Use the Pythagorean Theorem to calculate the length of the longest girder. Here, the girder forms the hypotenuse of a right triangle whose legs are the widths of the two corridors. The Pythagorean Theorem is: \[c = \sqrt{a^2 + b^2}\]where \(a = 10 \mathrm{ft} \) and \(b = 15 \mathrm{ft}\).
04

- Calculate the Maximum Length

Substitute the values into the Pythagorean Theorem: \[c = \sqrt{10^2 + 15^2}\]Simplify inside the square root: \[c = \sqrt{100 + 225}\]Add the results inside the square root: \[c = \sqrt{325}\]Finally, compute the square root: \[c \approx 18.03 \mathrm{ft}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Right triangle geometry
In right triangle geometry, one of the angles is always 90 degrees. This forms a right-angle, splitting the triangle into two legs and one hypotenuse, which is the longest side. Understanding right triangle geometry is essential because it allows the use of the Pythagorean Theorem to solve problems involving distances and lengths.
For example, in the given exercise, the two corridors intersect at a right angle forming a right triangle. The widths of the corridors represent the two legs of this triangle. By visualizing the problem in terms of right triangle geometry, we can use mathematical principles to solve it.
The legs, denoted as 'a' and 'b', are perpendicular to each other. The hypotenuse, 'c', can be found by solving the equation: \[ c^2 = a^2 + b^2 \]This relationship is critical for calculating distances and understanding geometric constraints in similar real-world problems.
Hypotenuse calculation
The hypotenuse is the longest side in a right triangle, opposite the right angle. To calculate the hypotenuse accurately, the Pythagorean Theorem is used. This theorem states that in a right triangle, the square of the hypotenuse equals the sum of the squares of the other two sides.
For our exercise, the corridor widths of 10 feet and 15 feet form the legs 'a' and 'b'. We apply the Pythagorean Theorem as follows: \[ c = \sqrt{a^2 + b^2} \]Substitute the given values: \[ c = \sqrt{10^2 + 15^2} = \sqrt{100 + 225} = \sqrt{325} \]
Finally, compute the square root of 325 to find: \[ c \approx 18.03 \text{ feet} \]This calculation shows that the longest steel girder that can be moved horizontally around the corner is approximately 18.03 feet long. This practical application of the Pythagorean Theorem helps solve the problem of navigating tight spaces with long objects.
Corridor intersection
The intersection of corridors at right angles creates a classic problem in geometry where one needs to calculate distances or object lengths that can move around corners. When two corridors meet at right angles, it forms a 90-degree intersection, resulting in a right-angled triangle when considering the diagonal path.
Visualizing this helps in understanding how to accommodate large objects. Each corridor width represents a leg of the triangle. The challenge, then, is determining the maximum length of an object, like a steel girder, that can be maneuvered in this space.
In practice, the corners of the corridors are points where precision matters. Any object like the steel girder must navigate this space by forming a right triangle with the corridor sides. Thus, the object’s length when positioned horizontally and tangentially forms the hypotenuse. This efficient spatial understanding ensures accurate and practical solutions for real-life scenarios involving tight turns and large objects.

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Most popular questions from this chapter

In Exercises 6 through 25 , evaluate the indefinite integral. \(\int \frac{d x}{(1+x) \sqrt{x}}\)

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