Chapter 1: Problem 11
In Exercises 11 through 14 , find the center and radius of each circle, and draw a sketch of the graph. $$ x^{2}+y^{2}-6 x-8 y+9=0 $$
Short Answer
Expert verified
Center: (3, 4), Radius: 4
Step by step solution
01
- Write the Equation in Standard Form
The given equation is: \(x^{2} + y^{2} - 6x - 8y + 9 = 0\) To find the center and radius, we must write this in the standard form of a circle equation, which is: \((x - h)^{2} + (y - k)^{2} = r^{2}\)
02
- Group and Complete the Square
First, group the \(x\) and \(y\) terms: \(x^{2} - 6x + y^{2} - 8y = -9\) Complete the square for both groups. For the \(x\) terms: \(x^{2} - 6x\), take half of \(-6\) to get \(-3\), then square it to get \(9\). For the \(y\) terms: \(y^{2} - 8y\), take half of \(-8\) to get \(-4\), then square it to get \(16\). Add these squares to both sides of the equation.
03
- Add Completed Squares
\(x^{2} - 6x + 9 + y^{2} - 8y + 16 = -9 + 9 + 16\) Simplified, this becomes: \((x - 3)^{2} + (y - 4)^{2} = 16\)
04
- Identify the Center and Radius
Now, the equation \((x - 3)^{2} + (y - 4)^{2} = 16\) is in standard form: \((x - h)^{2} + (y - k)^{2} = r^{2}\), where \((h, k)\) is the center and \(r\) is the radius. So, the center is \((3, 4)\) and the radius is \(\sqrt{16} = 4\).
05
- Sketch the Graph
Plot the center at point \((3, 4)\) on the coordinate plane. Draw a circle with radius 4 units around this center. Ensure the circle is accurate by measuring 4 units in all directions from the center.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
standard form of a circle
To fully grasp the equation of a circle, it's important to understand its standard form. The standard form of a circle is:ewline \((x - h)^{2} + (y - k)^{2} = r^{2}\) where
- ewline The term \((x - h)\) shifts the circle horizontally by 'h' units. ewline
- The term \((y - k)\) shifts the circle vertically by 'k' units. ewline
- ewline The radius 'r' is the distance from the center \((h, k)\) to any point on the circle.
completing the square
Completing the square is a method used to convert quadratic equations into a form that reveals insights into the geometric properties of conic sections like circles.It involves creating perfect squares from the given quadratic expressions. Let's look at the steps:
- Group the x and y terms: \((x^2 - 6x) + (y^2 - 8y)\).
- Complete the square for x-terms. Take half of \(-6\) (the coefficient of x), which is -3, and then square it to get 9. Add and subtract 9 within the equation to balance it.
- Repeat the process for y-terms. Half of \(-8\), which is -4, squared is 16. Add and subtract 16.
- Add these adjusted terms to both sides of the equation: ewlineewline \(x^2 - 6x + 9 + y^2 - 8y + 16 = -9 + 9 + 16\). This simplifies to the perfect squares: \( (x - 3)^2 + (y - 4)^2 = 16\).
graphing circles
Once the equation is in standard form, graphing a circle becomes much easier and straightforward. Let's break it down:
- Identify the center: from the equation \((x - 3)^{2} + (y - 4)^{2} = 16\), the center is \((3, 4)\).By comparing it to \((x - h)^{2} + (y - k)^{2} = r^{2}\), we see that h=3 and k=4.
- Determine the radius: The radius r is \sqrt{16} = 4.\
- Plot the center at point \( (3, 4) \) on the coordinate plane.
- Use a compass or measure from the center to plot points 4 units away in all directions.
- Connect these points in a smooth, round shape to form the circle. Ensure symmetry to get an accurate circle.