/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 A luxury sports car dealership o... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A luxury sports car dealership offers its clients a complimentary shuttle service to and from the dealership when their cars are serviced. Currently, the dealership's driver shuttles clients to and from locations. However, the dealership has only one driver, and clients sometimes have to wait for an extended period. In hopes of improving service and pleasing clients, the dealership decides to change from an in-house shuttle service to using a ride- sharing service. The dealership wants to monitor the impact of this change to see if the percentage of clients who take advantage of the transportation service changes. First, the dealership gathers historical data to determine the percentage of clients who have been using the shuttle service. It looks at records for the past six months. The average number of clients who visit the dealership each month is 190 , with relatively little month-to-month variation. During the past six months, a total of 354 clients have requested rides. a. What is the estimated total number of clients requesting rides during these six months? What is \(p\) ? b. Give the center line and control limits for a \(p\) chart on which to plot the future monthly proportions of clients requesting rides.

Short Answer

Expert verified
Estimated rides requested: 1140 clients; \( p = 0.3105 \). Center line: 0.3105; UCL: 0.4107, LCL: 0.2103.

Step by step solution

01

Calculate Total Number of Clients in Six Months

To find the total number of clients who visited the dealership over the six-month period, multiply the average number of monthly clients by six: \[ \text{Total clients in 6 months} = 190 \times 6 = 1140 \] clients.
02

Estimate the Proportion of Clients Requesting Rides ( p ext{)

The proportion \( p \) of clients requesting rides is calculated by dividing the total number of clients who requested rides by the total number of clients. We have 354 clients requesting rides.\[ p = \frac{354}{1140} \approx 0.3105 \]
03

Center Line of the p ext{ Chart}

The center line for a \( p \) chart is the proportion \( p \) of clients requesting rides. Thus, the center line is \( p = 0.3105 \).
04

Calculate Standard Deviation of p ext{ ( p ext{)}

The standard deviation for proportions is given by \( \sigma = \sqrt{\frac{p(1-p)}{n}} \), where \( n \) is the average number of clients per month.\[ \sigma = \sqrt{\frac{0.3105 \times (1 - 0.3105)}{190}} \approx 0.0334 \]
05

Determine Control Limits for the p ext{ Chart}

The control limits are calculated as: \[ \text{Upper Control Limit (UCL)} = p + 3\sigma = 0.3105 + 3 \times 0.0334 \approx 0.4107 \]\[ \text{Lower Control Limit (LCL)} = p - 3\sigma = 0.3105 - 3 \times 0.0334 \approx 0.2103 \] (Ensure that the LCL is not negative).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

p-chart
P-charts are a type of control chart used in statistical process control to monitor the proportion of defective items or events in a process over time. In our example, the dealership wants to assess whether the switch to a ride-sharing service will affect the usage rate of their transportation service. A p-chart provides a visible way to track changes in these proportions, helping the dealership quickly identify any significant variations in client behavior.
By plotting the proportion of clients using the service each month on a p-chart, the dealership can assess whether there are any trends or outliers that may indicate an improvement or decline in service usage.
Proportion Calculation
Calculating the proportion is an essential first step in creating a p-chart. It involves determining the percentage of a particular outcome over the total number of opportunities. In this case, we need to find out the proportion of clients who requested rides.
Here's how we do it:
  • First, calculate the total number of clients over the six-month period, which was found to be 1,140.
  • Then, divide the number of clients who requested rides (354) by the total number of clients (1,140).
  • The calculated proportion, \( p = \frac{354}{1140} \approx 0.3105 \), represents the percentage of clients who opted for the shuttle service.
This proportion can now be used as a foundation for creating the p-chart.
Standard Deviation
In the context of p-charts, the standard deviation measures the expected variation in the proportion of successes or features of interest (e.g., clients requesting rides). Here's how we calculate it:
  • The formula for standard deviation for a proportion \( \sigma \) is given by \( \sigma = \sqrt{\frac{p(1-p)}{n}} \).
  • Using our previous proportion \( p = 0.3105 \) and an average number of clients \( n = 190 \), we calculate \( \sigma = \sqrt{\frac{0.3105 \times (1 - 0.3105)}{190}} \approx 0.0334 \).
Standard deviation is crucial as it provides a sense of how much the monthly proportions might naturally fluctuate around the average. This information is vital when determining the control limits on a p-chart.
Control Limits
Control limits define the boundaries within which we expect the process proportion to fluctuate under normal conditions. They are calculated using the average proportion and its standard deviation:
  • The Upper Control Limit (UCL) is calculated as \( p + 3\sigma \).
  • The Lower Control Limit (LCL) is \( p - 3\sigma \), ensuring it does not fall below zero as proportions can't be negative.
In the dealership's case, with \( p = 0.3105 \) and \( \sigma = 0.0334 \):
  • UCL = \( 0.3105 + 3 \times 0.0334 \approx 0.4107 \).
  • LCL = \( 0.3105 - 3 \times 0.0334 \approx 0.2103 \).
These limits help determine whether the proportion of clients using the service is stable or needs further investigation if it breaches these control boundaries.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A large chain of coffee shops records a number of performance measures. Among them is the time required to complete an order for a cappuccino, measured from the time the order is placed. Suggest some plausible examples of each of the following. a. Reasons for common cause variation in response time b. s-type special causes c. \(x\)-type special causes

John recently changed to a more healthy diet, and after switching his eating habits he began to chart the number of servings of fruits and vegetables consumed each day. The number of servings of fruits and vegetable he consumed varied each day but was generally stable. There were some days when the number of servings was unusual. Sometimes the number of servings was much higher than expected, and sometimes it was much lower than expected. Give several examples of special causes that might significantly increase or decrease the number of servings of fruits and vegetables John consumes on a given day.

What type of control chart or charts would you use as part of efforts to improve each of the following performance measures in a college admissions office? Explain your choices. a. Time to acknowledge receipt of an application b. Percentage of admission offers accepted c. Student participation in a healthy meal plan

The net weight (in ounces) of bags of almond flour is monitored by taking samples of four bags during each hour of production. The process mean should be \(\mu=16 \mathrm{oz}\). When the process is properly adjusted, it varies with \(\sigma=0.4 \mathrm{oz}\). The mean weight \(x\) for each hour's sample is plotted on an \(x\) control chart. Calculate the center line and control limits for this chart.

A manufacturer of ultrasonic parking sensors samples four sensors during each production shift. The expectation is that a sensor will initially alarm when an object comes within 60 inches of the sensor. The sensors are put on a rack, and an object is moved toward each sensor, one at a time, at a 90 -degree angle until the sensor alarms. The distance from the object to the sensor at that point is recorded. This results in four measurements, one for each sensor on the rack, and the mean of these four measurements is recorded. The process mean should be \(\mu=60\) inches. Past experience indicates that the response varies with \(\sigma=1.0\) inches. The mean response distance is plotted on an \(x\) control chart. The center line for this chart is a. \(1.0\) inches. b. 4 inches. c. 60 inches.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.