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91Ó°ÊÓ

The proportion of observations from a standard Normal distribution that take values greater than \(1.78\) is about a. \(0.9554 .\) b. \(0.0446 .\) c. \(0.0375 .\)

Short Answer

Expert verified
Option c. 0.0375.

Step by step solution

01

Understanding the standard normal distribution

The standard normal distribution is a normal distribution with a mean of 0 and a standard deviation of 1. The area under the curve of a normal distribution represents probabilities.
02

Identify the Z-score

We want to find the proportion of observations with a Z-score greater than 1.78. In other words, we are looking for the probability that a standard normal random variable is greater than 1.78.
03

Look up the Z-score in a Z-table

A Z-table provides the cumulative probability for a given Z-score in a standard normal distribution. The value from a Z-table for a Z-score of 1.78 gives the probability of observing a value less than 1.78 in a standard normal distribution.
04

Calculate the probability of observations greater than 1.78

The area to the left of 1.78 (from the Z-table or using a calculator) is approximately 0.9625. We want the area to the right, which is 1 minus this value: \[ P(Z > 1.78) = 1 - P(Z < 1.78) = 1 - 0.9625 = 0.0375 \]
05

Choose the correct option

Compare the calculated probability, 0.0375, with the options given in the question. The closest match is option c. 0.0375.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-score
A Z-score is a statistical measurement that describes how many standard deviations a data point is away from the mean of a data set. In the context of the standard normal distribution, which has a mean of 0 and a standard deviation of 1, a Z-score tells us precisely where a particular point falls within the distribution.

Calculating a Z-score is straightforward:
  • Z = (X - μ) / σ
Where X is the data point, μ is the mean, and σ is the standard deviation. In a standard normal distribution, since μ is 0 and σ is 1, the formula simplifies.

  • A positive Z-score indicates the data point is above the mean.
  • A negative Z-score shows it is below the mean.
When we look for values greater than a certain Z-score, as in our problem, we determine the probability of observations that lie beyond that point in the distribution.
Probability
In statistics, probability measures the likelihood of a specific event occurring out of all possible outcomes.

For a standard normal distribution, probabilities are represented by the area under the curve. This model assumes that outcomes follow a bell pattern where most observations cluster around the mean, creating a symmetric curve.

Understanding probabilities in this distribution helps in:
  • Estimating how likely a value will fall within a specific range.
  • Making informed predictions and decisions based on data.
For example, if you seek the probability of observations greater than a Z-score of 1.78, you are looking at the proportion of the area to the right of this score in the standard normal distribution.
Z-table
The Z-table, also known as the standard normal table, is a tool used to quickly find the cumulative probability associated with a particular Z-score. It lists the percentage of values to the left of a given Z-score in a standard normal distribution.

By looking at the Z-table:
  • You can determine the likelihood of a score being less than a given value.
  • The further you move away from 0, either positively or negatively, the lower the cumulative probability becomes.
When using the Z-table, locate the Z-score you are interested in. For 1.78, look up this value to see how much of the data lies below it. In our exercise, for a Z-score of 1.78, the cumulative probability is found to be about 0.9625.
Cumulative Probability
Cumulative probability is the total probability that a random variable is less than or equal to a given value. In a standard normal distribution, it indicates what portion of the data falls under the curve to the left of a specified Z-score.

To find the area to the right (as the problem requires for Z > 1.78), subtract the cumulative probability from 1:
  • P(Z > z) = 1 - P(Z < z)
This calculation gives the probability that a data point is above a certain threshold. For instance, if the cumulative probability for Z = 1.78 is 0.9625, the probability for Z > 1.78 is:
  • P(Z > 1.78) = 1 - 0.9625 = 0.0375
This shows only a small fraction of values lie beyond 1.78 in the distribution, corresponding to the tail end of the curve.

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Most popular questions from this chapter

Heights of Men and Women. The heights of women aged 20-29 follow approximately the \(N(64.1,3.7)\) distribution. Men the same age have heights distributed as \(N(69.4,3.1)\). What percentage of men aged 20-29 are taller than the mean height of women aged 20-29?

The Medical College Admissions Test. Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). The total score of the four sections on the test ranges from 472 to 528 . In spring of 2019 , the mean score was \(500.9\), with a standard deviation of \(10.6\). a. What are the median and the first and third quartiles of the MCAT scores? What is the interquartile range? b. Give the interval that contains the central \(80 \%\) of the MCAT scores.

The distribution of hours of sleep per weeknight among college students is found to be Normally distributed, with a mean of \(6.5\) hours and a standard deviation of 1 hour. The percentage of college students that sleep at least eight hours per weeknight is about a. \(95 \%\) b. \(6.7 \%\) c. \(2.5 \%\)

The distribution of hours of sleep per weeknight among college students is found to be Normally distributed, with a mean of \(6.5\) hours and a standard deviation of 1 hour. What range contains the middle \(95 \%\) of hours slept per weeknight by college students? a. \(5.5\) and \(7.5\) hours per weeknight b. \(4.5\) and \(7.5\) hours per weeknight c. \(4.5\) and \(8.5\) hours per weeknight

Weights Aren't Normal. The heights of people of the same sex and similar ages follow a Normal distribution reasonably closely. Weights, on the other hand, are not Normally distributed. The weights of men aged 20-29 in the United States have mean 186.8 pounds and median \(177.8\) pounds. The first and third quartiles are \(152.9\) pounds and \(208.5\) pounds, respectively. In addition, the bottom \(10 \%\) have weights less than or equal to \(137.6\) pounds while the top \(10 \%\) have weights greater than or equal to 247.2. What can you say about the shape of the weight distribution? Why?

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