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The distribution of hours of sleep per weeknight among college students is found to be Normally distributed, with a mean of \(6.5\) hours and a standard deviation of 1 hour. What range contains the middle \(95 \%\) of hours slept per weeknight by college students? a. \(5.5\) and \(7.5\) hours per weeknight b. \(4.5\) and \(7.5\) hours per weeknight c. \(4.5\) and \(8.5\) hours per weeknight

Short Answer

Expert verified
Choice c: 4.5 to 8.5 hours.

Step by step solution

01

Understanding the Problem

We are given a normally distributed variable, which is the number of hours college students sleep per weeknight. The mean (\(\mu\)) is given as \(6.5\) hours, and the standard deviation (\(\sigma\)) is 1 hour. We need to find the range that contains the middle \(95\%\) of the distribution.
02

Recall the Empirical Rule

The empirical rule states that for a normal distribution, approximately \(68\%\) of the data falls within one standard deviation (\(\mu \pm \sigma\)), \(95\%\) of the data falls within two standard deviations (\(\mu \pm 2\sigma\)), and \(99.7\%\) of the data falls within three standard deviations (\(\mu \pm 3\sigma\)). We are interested in the range that encompasses \(95\%\) of the data.
03

Calculate the Bounds Using the Empirical Rule

The middle \(95\%\) of a normal distribution corresponds to the range from two standard deviations below the mean to two standard deviations above the mean. Thus, we calculate:- Lower bound: \(\mu - 2\sigma = 6.5 - 2(1) = 4.5\)- Upper bound: \(\mu + 2\sigma = 6.5 + 2(1) = 8.5\)Therefore, the range is \(4.5\) to \(8.5\) hours.
04

Identify the Correct Answer Choice

Comparing our calculated range of \(4.5\) to \(8.5\) hours with the given choices, we see that option (c) matches:- c. \(4.5\) and \(8.5\) hours per weeknightHence, the correct answer is choice c.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Empirical Rule
The Empirical Rule is a handy guideline used in statistics that applies to normal distributions. It helps in understanding how data is spread out around the mean or average. This rule states that in a normal distribution:
  • About 68% of the data lies within one standard deviation (\( \mu \pm \sigma \)) from the mean.
  • Approximately 95% of the data falls within two standard deviations (\( \mu \pm 2\sigma \)) from the mean.
  • Nearly 99.7% of the data is within three standard deviations (\( \mu \pm 3\sigma \)) from the mean.
These percentages help provide a quick insight into how much data resides close to the average and how much rests further away. This is particularly useful for normally distributed data, aiding in predictions and assessments of variability around the mean. When solving problems regarding normal distributions, like finding the range for the middle 95%, the Empirical Rule can quickly guide us to the answer without complex calculations.
Standard Deviation
Standard Deviation is a key concept in statistics that quantifies the amount of variation or dispersion in a set of data values. It tells us how spread out the numbers in your data set are. In a normal distribution, a smaller standard deviation means that the data points tend to be closer to the mean, while a larger standard deviation means they are more spread out.
In mathematical terms, the standard deviation is calculated as the square root of the variance. Variance is the average of the squared differences from the mean, and this helps in understanding overall data variability. For the problem given:
  • The mean (\( \mu \)) is 6.5 hours.
  • The standard deviation (\( \sigma \)) is 1 hour.
This means that most of the student sleeping hours are close to 6.5 hours, with an acceptable deviation of 1 hour. Understanding standard deviation is essential since it plays a fundamental role in determining how data behaves under the normal distribution, especially when applying the Empirical Rule.
Mean
The mean, often referred to as the "average," is one of the most basic statistical measures. It provides the central tendency of a data set. To find the mean, you sum up all the observed data points and then divide by the total number of points. It represents the "middle" of the data.
In the context of a normal distribution, like the hours slept per weeknight in our example, the mean shows the center of the data's bell-shaped curve. In this situation:
  • \( \mu = 6.5 \) hours.
This tells us that, on average, college students sleep for 6.5 hours per weeknight. The mean is essential for determining the location of the peak of the normal distribution and is a pivotal point around which the standard deviation and the Empirical Rule operate. Thus, understanding the concept of mean helps solidify our grasp of data behavior in statistics, serving as a foundation for more complex analyses.

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Most popular questions from this chapter

Heights of Men and Women. The heights of women aged 20-29 follow approximately the \(N(64.1,3.7)\) distribution. Men the same age have heights distributed as \(N(69.4,3.1)\). What percentage of men aged 20-29 are taller than the mean height of women aged 20-29?

Osteoporosis. Osteoporosis is a condition in which the bones become brittle due to loss of minerals. To diagnose osteoporosis, an elaborate apparatus measures bone mineral density (BMD). BMD is usually reported in standardized form. The standardization is based on a population of healthy young adults. The World Health Organization (WHO) criterion for osteoporosis is a BMD lower than \(2.5\) standard deviations below the mean for healthy young adults. BMD measurements in a population of people similar in age and sex roughly follow a Normal distribution. a. What percentage of healthy young adults have osteoporosis by the WHO criterion? b. Women aged \(70-79\) are, of course, not young adults. The mean BMD in this age is about \(-2\) on the standard scale for young adults. Suppose the standard deviation is the same as for young adults. What percentage of this older population have osteoporosis?

To completely specify the shape of a Normal distribution, you must give a. the mean and the standard deviation. b. the five-number summary. c. the median and the quartiles.

.A Sur prising Calculation. Changing the mean and standard deviation of a Normal distribution by a moderate amount can greatly change the percentage of observations in the tails. Suppose a college is looking for applicants with either SAT Math or Evidence-Based Reading and Writing (ERW) scores 780 and above. a. In 2018, the scores on the math SAT followed the \(N(528,117)\) distribution. What percentage scored 780 or better? b. The ERW scores that year had the \(N(531,104)\) distribution. What percentage scored 780 or better? You see that the percentage of students with math SAT scores above 780 is almost two times the percentage of students with such high ERW scores.

Nor mal Is Only Approximate: ACT Scores. Composite scores on the ACT for the 2019 high school graduating class had mean \(20.8\) and standard deviation \(5.8\). In all, \(1,914,817\) students in this class took the test. Of these, 227,221 had scores higher than 28 , and another 54,848 had scores exactly 28. ACT scores are always whole numbers. The exactly Normal \(N(20.8,5.8)\) distribution can include any value, not just whole numbers. What is more, there is no area exactly above 28 under the smooth Normal curve. So ACT scores can be only approximately Normal. To illustrate this fact, find a. the percentage of 2019 ACT scores greater than 28 , using the actual counts reported. b. the percentage of 2019 ACT scores greater than or equal to 28 , using the actual counts reported. c. the percentage of observations that are greater than 28 using the \(N(20.8,5.8)\) distribution. (The percentage greater than or equal to 28 is the same because there is no area exactly over 28.)

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