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The Medical College Admissions Test. Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). The total score of the four sections on the test ranges from 472 to 528 . In spring of 2019 , the mean score was \(500.9\), with a standard deviation of \(10.6\). a. What proportion of students taking the MCAT had a score over 510 ? b. What proportion had scores between 505 and 515 ?

Short Answer

Expert verified
a. 19.49% of students scored over 510. b. 25.65% scored between 505 and 515.

Step by step solution

01

Identify the Distribution

Identify the context. The problem states that the MCAT scores are normally distributed with a mean (\( \mu \)) of 500.9 and a standard deviation (\( \sigma \)) of 10.6.
02

Calculate Z-score for Over 510

To find the proportion of scores over 510, calculate the Z-score using the formula: \( Z = \frac{X - \mu}{\sigma} \). For \( X = 510 \), substitute the values: \( Z = \frac{510 - 500.9}{10.6} \approx 0.86 \).
03

Use Z-table for Over 510

Using a Z-table, find the cumulative probability for \(Z = 0.86\). The table's value is approximately 0.8051, representing the probability of scoring below 510. The probability over 510 is \(1 - 0.8051 = 0.1949\).
04

Calculate Z-score for 505

For a score of 505, calculate the Z-score: \( Z_{505} = \frac{505 - 500.9}{10.6} \approx 0.3868 \).
05

Calculate Z-score for 515

For a score of 515, calculate the Z-score: \( Z_{515} = \frac{515 - 500.9}{10.6} \approx 1.3349 \).
06

Use Z-table for Between 505 and 515

Using the Z-table, find the cumulative probabilities for the calculated Z-scores. For \(Z_{505} = 0.39\), the value is approximately 0.6517. For \(Z_{515} = 1.33\), the value is approximately 0.9082. The proportion of students scoring between 505 and 515 is \(0.9082 - 0.6517 = 0.2565\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
The concept of a normal distribution is fundamental in statistics. It describes a probability distribution that is symmetrical and bell-shaped, meaning most data points cluster around the mean, with fewer observations occurring as you move away from the center. This pattern resembles a bell curve. For MCAT scores, they are assumed to follow this distribution, making it easier to analyze and predict student performance.

Some key characteristics of a normal distribution include:
  • Symmetry around the mean, meaning the left side of the curve is a mirror image of the right side.
  • The mean, median, and mode of the distribution are all equal and located at the center.
  • About 68% of observations fall within one standard deviation of the mean, 95% fall within two standard deviations, and 99.7% fall within three standard deviations.
For the MCAT, understanding this distribution helps us determine how individual scores relate to the entire set of data, such as finding out what proportion of students scored above a specific score like 510.
Cumulative Probability
Cumulative probability is the sum of probabilities of all values that fall below a specified value in a distribution. For a given score, it tells you the probability of observing a score less than or equal to that score. With cumulative probability, we can easily find out where a particular score stands in comparison to the entire distribution.

When calculating cumulative probabilities using a Z-table, which helps find the area under the standard normal curve:
  • First, find the Z-score for the score of interest (like the score of 510).
  • Next, use the Z-table to find the cumulative probability for that Z-score. This tells you the probability of scoring below the given score.
To find the probability of scoring above the given score, subtract the cumulative probability from 1. This process is helpful for understanding what proportion of students scored above a particular score on the MCAT.
Standard Deviation
Standard deviation is a measure of how spread out the numbers in a data set are. It provides an indication of the average distance from the mean. In the context of MCAT scores, a standard deviation of 10.6 indicates how much students' scores typically vary from the average score of 500.9.

Key points about standard deviation include:
  • If the standard deviation is small, the data points are close to the mean, indicating low variability.
  • If the standard deviation is large, the data points are spread out over a wider range of values.
  • It is a crucial component in calculating Z-scores, which are used to understand the relative position of a score within the distribution.
By interpreting standard deviation, we can better understand the distribution of MCAT scores and how likely it is for scores to fall within certain ranges.
Mean Score
The mean score represents the average score obtained by all students taking the test. Calculating the mean involves summing up all individual scores and dividing by the number of students. For the MCAT, the mean score is 500.9, serving as a central tendency measure, showing that half of the students scored below this point and half scored above.

The mean score is critical as it helps in:
  • Setting a benchmark for comparison against individual scores.
  • Determining the overall performance trend of test-takers.
  • Identifying potential areas for improvement, if necessary.
The mean score offers a snapshot of the overall distribution of scores on the MCAT and is a foundational element for subsequent statistical analyses and interpretations.

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Most popular questions from this chapter

Upper Arm Lengths. Anthropomorphic data are measurements on the human body that can track growth and weight of infants and children and evaluate changes in the body that occur over the adult life span. The resulting data can be used in areas as diverse as ergonomics and clothing design. The upper arm length of males over 20 years old in the United States is approximately Normal with mean \(39.1\) centimeters \((\mathrm{cm})\) and standard deviation \(5.0 \mathrm{~cm}\). Draw a Normal curve on which this mean and standard deviation are correctly located. (Hint: Draw an unlabeled Normal curve, locate the points where the curvature changes, then add number labels on the horizontal axis.)

Where Are the Quartiles? How many standard deviations above and below the mean do the quartiles of any Normal distribution lie? (Use the standard Normal distribution to answer this question.)

Acid Rain? Emissions of sulfur dioxide by industry set off chemical changes in the atmosphere that result in "acid rain." The acidity of liquids is measured by \(\mathrm{pH}\) on a scale of 0 to 14 . Distilled water has \(\mathrm{pH}\) 7.0, and lower \(\mathrm{pH}\) values indicate acidity. Normal rain is somewhat acidic, so acid rain is sometimes defined as rainfall with a pH below \(5.0\). The \(\mathrm{pH}\) of rain at one location varies among rainy days according to a Normal distribution with mean \(5.43\) and standard deviation \(0.54\). What proportion of rainy days have rainfall with \(\mathrm{pH}\) below \(5.0\) ?

Use the Normal Table. Use Table A to find the proportion of observations from a standard Normal distribution that satisfies each of the following statements. In each case, sketch a standard Normal curve and shade the area under the curve that is the answer to the question. a. \(z<-0.42\) b. \(z>-1.58\) c. \(z<2.12\) d. \(-0.42

Standard Normal Drill. a. Find the number \(z\) such that the proportion of observations that are less than \(z\) in a standard Normal distribution is \(0.2\). b. Find the number \(z\) such that \(40 \%\) of all observations from a standard Normal distribution are greater than \(z\).

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