/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 Perceived Exertion while Exercis... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Perceived Exertion while Exercising. Can the introduction of pleasant sensory stimuli lead to a more pleasant exercise environment and decrease perceived exertion during a four-minute stepping task? Forty-three students from a southeastern university were assigned at random to three conditions: "taste," in which participants inserted a lemon-flavored mouth guard during the task; "placebo," in which participants inserted a non-flavored mouth guard; and "control," in which no mouth guard was used. Twelve students were assigned to the taste group, 15 to the placebo group, and 16 to the control group. Ratings of perceived exertion (RPE) scores were measured on a standard 15-point scale ranging from 6 (very, very light) to 20 (exhausted). 14

Short Answer

Expert verified
Perform an ANOVA to test if flavored mouthguards affect perceived exertion.

Step by step solution

01

Understand the Problem

We are tasked with determining whether the introduction of pleasant sensory stimuli, like a lemon-flavored mouthguard, can reduce perceived exertion during exercise. This involves comparing RPE scores across three groups: 'taste', 'placebo,' and 'control.'
02

Identify the Data

The data involves 43 students divided into three groups: 12 in the 'taste' group, 15 in the 'placebo' group, and 16 in the 'control' group. Each group provides RPE scores on a scale from 6 to 20.
03

Determine the Appropriate Analysis

Since we need to compare the mean RPE scores across three independent groups, an ANOVA (Analysis of Variance) test is appropriate. It will tell us whether there is a statistically significant difference among the groups.
04

State the Hypotheses

The null hypothesis (H0) is that there is no difference in mean RPE scores between the groups. The alternative hypothesis (H1) is that at least one group has a different mean RPE score.
05

Perform the ANOVA Test

Using the ANOVA formula, calculate the F-statistic by comparing the variance between groups to the variance within groups. This requires calculating group means, the overall mean, and variances.
06

Check Results and Make a Decision

After calculating the F-statistic and comparing it to a critical value from the F-distribution table (or using a p-value), determine if the null hypothesis can be rejected. A p-value less than the significance level (commonly 0.05) indicates a significant difference.
07

Interpret the Results

If the null hypothesis is rejected, it suggests that the introduction of the lemon-flavored mouthguard may reduce perceived exertion. If not, sensory stimuli did not make a significant impact.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Analysis of Variance (ANOVA)
When we have multiple groups and want to see if they differ from each other, ANOVA is the tool to use. In this exercise about perceived exertion during a short stepping task, ANOVA helps us determine whether the average ratings between the 'taste', 'placebo', and 'control' groups differ significantly.

The basic idea of ANOVA is to analyze variance. It divides the observed variance in data into different parts. Here, it splits the total variation in RPE scores into two:
  • Between-group variance: This variance comes from differences between the group means (e.g., 'taste' vs. 'placebo').
  • Within-group variance: This variance is the natural variation within each group (e.g., different individuals in the 'taste' group).
By comparing these two, ANOVA calculates an F-statistic. A significant F-statistic suggests the group means are not all the same, indicating a potential effect from the lemon-flavored mouthguard.
Experimental Design
Experimental design is crucial when we want to examine cause-and-effect relationships. Our problem looked at whether a sensory stimulus affects perceived exertion during exercise.

In this study, 43 students were randomly assigned to one of three experimental conditions:
  • Taste group: Used a lemon-flavored mouthguard.
  • Placebo group: Used a non-flavored mouthguard.
  • Control group: Did not use any mouthguard.
This random assignment ensures that each group is similar at the start of the experiment, minimizing bias. The only difference between the groups should be the type of mouthguard used, allowing us to isolate its effect on perceived exertion.
Hypothesis Testing
Hypothesis testing is like a tool that decides if a pattern observed in data is real or just due to random chance. It's fundamental for scientific conclusions.

In this study, the key hypotheses are:
  • Null hypothesis (H0): There is no difference in RPE scores between the three groups.
  • Alternative hypothesis (H1): At least one group has a different mean RPE score from the others.
We use statistical tests, like ANOVA, to analyze data and check these hypotheses. By calculating a p-value (probability value), we determine the likelihood that the observed data occurred under the null hypothesis. If the p-value is below a chosen significance level (usually 0.05), we reject the null hypothesis, suggesting a real difference in group means due to the sensory stimuli.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Political Views and Education. The University of Chicago's General Social Survey (GSS) is the nation's most important social science sample survey. The GSS asked a random sample of adults in 2018 their highest degree earned and where they placed themselves on the political spectrum using a 7-point scale from \(1=\) extremely liberal to \(7=\) extremely conservative. The analysis reports \(F=9.317\) with \(P\)-value \(<0.0001\) and, for each highest degree earned, provides the mean political spectrum score, which can be used to draw a graph like Ejgure 27.3. \({ }^{-}\) a. What are the null and alternative hypotheses for the ANOVA \(F\) test? Be sure to explain what means the test compares. b. Based on the graph and the F test, what do you conclude?

In an ANOVA that compares three treatments, how many pairwise comparisons between two of these treatments are there? a. two b. three c. six

The purpose of analysis of variance is to compare a. the variances of several populations. b. the standard deviations several populations. c. the means of several populations.

What Music Will You Play? People often match their behavior to their social environment. One study of this idea first established that the type of music most preferred by Black college students is R\&B and that Whites' most preferred music is rock. Will students hosting a small group of other students choose music that matches the racial composition of the people attending? Assign 90 Black business students at random to three equal-sized groups. Do the same for 96 White students. Each student sees a picture of the people he or she will host. Group 1 sees six Blacks, Group 2 sees three Whites and three Blacks, and Group 3 sees six Whites. Ask how likely the host is to play the type of music preferred by the other race. Use ANOVA to compare the three groups to see whether the racial mix of the gathering affects the choice of music. \(\frac{8}{1}\) a. For the White subjects, \(F=16.48\). What are the degrees of freedom? b. For the Black subjects, \(F=2.47\). What are the degrees of freedom?

As part of an ANOVA that compares three treatments, you carry out Tukey pairwise tests at the overall \(5 \%\) significance level. The Tukey tests find that \(\mu_{1}\) is significantly different from \(\mu_{3}\) but that the other two comparisons show no significant difference. You can be \(95 \%\) confident that a. \(\mu_{1} \neq \mu_{3}\) and \(\mu_{1}=\mu_{2}\) and \(\mu_{2}=\mu_{3}\). b. just \(\mu_{1} \neq \mu_{3}\); there is not enough evidence to draw conclusions about the other pairs of means. c. \(\mu_{1}=\mu_{2}\) and \(\mu_{2}=\mu_{3}\) and this implies that it must also be true that \(\mu_{1}=\mu_{3}\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.