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Take \(p_{9}\) and \(p_{12}\) to be the proportions of all ninth- and 12 thgraders who ate breakfast daily. The hypotheses to be tested are a. \(H_{0}: p_{9}=p_{12}\) versus \(H_{a}: p_{9} \neq p_{12}\). b. \(H_{0}: p_{9}=p_{12}\) versus \(H_{a}: p_{9}>p_{12}\). c. \(H_{0}: p_{9}=p_{12}\) versus \(H_{a}: p_{9}

Short Answer

Expert verified
Each part involves setting different directions for the alternative hypothesis and comparing the computed z to critical values based on test tails and significance. Collect data to proceed with calculations.

Step by step solution

01

Understand the Hypotheses

Let's define the null hypothesis, denoted as \(H_0\), and the alternative hypothesis, denoted as \(H_a\). The null hypothesis \(H_0: p_9 = p_{12}\) suggests there is no difference in the proportions. The alternative hypothesis \(H_a\) will vary based on the test and evaluate if there is a difference or direction of difference in the proportions of ninth and twelfth graders who eat breakfast daily.
02

Analyze Each Hypothesis Scenario

For each part of the problem, the way we test these hypotheses differ:- Part a involves a two-tailed test where \(H_a: p_9 eq p_{12}\), testing for any difference.- Part b involves a right-tailed test where \(H_a: p_9 > p_{12}\), testing if ninth graders have a higher proportion than twelfth graders.- Part c involves a left-tailed test where \(H_a: p_9 < p_{12}\), testing if ninth graders have a lower proportion than twelfth graders.
03

Choose the Test Statistic and Decision Rule

For hypothesis testing of proportions, use the standard normal (z) test statistic: \[z = \frac{\hat{p}_9 - \hat{p}_{12}}{\sqrt{\hat{p}(1-\hat{p})(\frac{1}{n_9} + \frac{1}{n_{12}})}}\]where \(\hat{p}\) is the combined sample proportion, \(n_9\) and \(n_{12}\) are the sample sizes for 9th and 12th graders, respectively. The decision rule is based on the chosen significance level (typically 0.05) to determine critical z-values for rejecting \(H_0\).
04

Conduct the Test and Interpret Results

Collect data values for \(\hat{p}_9, \hat{p}_{12}, n_9, n_{12}\) and calculate the test statistic \(z\). Compare \(z\) to critical values:- For part a, reject \(H_0\) if \(|z|\) > critical z.- For part b, reject \(H_0\) if \(z\) > critical z.- For part c, reject \(H_0\) if \(z\) < -critical z.If the test statistic leads to not rejecting \(H_0\), conclude no sufficient evidence against \(H_0\). Otherwise, support \(H_a\) as significant.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proportion Comparison
In statistics, when we talk about comparing proportions, we are generally looking at two different groups to determine if the proportions present in each group are equivalent or not. In this exercise, we compare the proportion of ninth graders and twelfth graders who eat breakfast daily. The proportion is a statistical term that describes how some part of a total is distributed among items in a group. For example, if among 100 ninth graders, 50 eat breakfast daily, the proportion, denoted as \( p_9 \), is 0.5. Similarly, if among 100 twelfth graders, 40 eat breakfast daily, the proportion \( p_{12} \) is 0.4. The task is to make a statistical determination if these two proportions differ by more than what could be expected by random chance. This is the essence of proportion comparison.
Null Hypothesis
The null hypothesis, symbolized as \( H_0 \), is a fundamental concept in hypothesis testing. It represents a statement of no effect or no difference and serves as the default or starting assumption in statistical testing. In our exercise, the null hypothesis is \( H_0: p_9 = p_{12} \), which states that there is no difference in the breakfast-eating proportions of the ninth and twelfth graders.The null hypothesis is always tested for the possibility that it can be rejected. It is akin to a position of status quo, assuming no change or effect unless significant evidence in our sample data indicates otherwise. This forms the basis on which tests like the z-test are constructed to evaluate the truth of this statement.
Alternative Hypothesis
The alternative hypothesis, denoted as \( H_a \), contrasts the null hypothesis. It presents what the researcher aims to prove, reflecting a new effect or change. In the context of the exercise, we have three possible alternative hypotheses:
  • \( H_a: p_9 eq p_{12} \) (two-tailed test) checks for any difference in proportions.
  • \( H_a: p_9 > p_{12} \) (right-tailed test) investigates if ninth graders are more likely to eat breakfast than twelfth graders.
  • \( H_a: p_9 < p_{12} \) (left-tailed test) examines whether ninth graders are less likely to eat breakfast.
Each hypothesis is based on a specific direction or nature of the expected outcome. This is essential, as the choice of alternative hypothesis determines the tail of the test and ultimately influences the critical values against which our test statistics are measured.
Z-Test
The z-test is a statistical test used to determine if there are differences between means or proportions when the sample size is large. In our exercise, we utilize the z-test for comparing proportions. Given two groups of students — ninth graders and twelfth graders — and their proportions of breakfast eaters, we calculate the z-score with the formula:\[z = \frac{\hat{p}_9 - \hat{p}_{12}}{\sqrt{\hat{p}(1-\hat{p})(\frac{1}{n_9} + \frac{1}{n_{12}})}}\]where \( \hat{p} \) is the pooled sample proportion, and \( n_9, n_{12} \) are the sample sizes.The z-test helps us make decisions about the null hypothesis. By computing our z-score and comparing it to critical z-values from the standard normal distribution, we decide whether the observed difference in sample proportions is statistically significant. A significant result suggests the alternative hypothesis holds true, whereas a non-significant result implies there isn't enough evidence to reject the null hypothesis. This objective approach provides a clear framework for research and hypothesis testing.

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Most popular questions from this chapter

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