/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 50 The Addition Rule. The addition ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The Addition Rule. The addition rule for probabilities, \(P(A\) or \(B)=P(A)+P(B)\), is not always true. Give (in words) an example of real-world events \(A\) and \(B\) for which this rule is not true.

Short Answer

Expert verified
Example: Raining (A) and seeing a rainbow (B) are events where the simple addition rule fails due to overlap.

Step by step solution

01

Identify Real-world Events

Choose two real-world events, one being 'raining tomorrow' (event A) and the other 'seeing a rainbow tomorrow' (event B). These events can happen independently, but sometimes one affects the occurrence of the other.
02

Define Event Relationship

Recognize that these events are not mutually exclusive. If it's raining tomorrow, the probability of seeing a rainbow increases because a rainbow often appears after rain when the sun comes out.
03

Analyze Intersection of Events

Since both events can happen simultaneously, calculate their combined probability using the adjusted addition rule: \[P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B)\]This accounts for the intersection of events, which the naive addition rule does not.
04

Discuss Why Rule Fails

The initial rule \(P(A) + P(B)\) overcounts scenarios where both events happen together. For the case of rainbows and rain, \(P(A \text{ and } B)\) is greater than zero, demonstrating why the simple addition rule does not apply.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability
Probability is a measure that quantifies the likelihood of a specific event occurring. In simpler terms, it's a way to describe how likely something is to happen. It's expressed numerically, typically as a fraction, a decimal, or a percentage. Understanding probability allows us to predict future events based on possible outcomes.
  • Probability ranges from 0 to 1.
  • A probability of 0 means the event will not occur.
  • A probability of 1 means the event is certain to occur.
For example, flipping a fair coin gives us two possible outcomes: heads or tails. Each has a probability of 0.5 (or 50%). In the context of the addition rule, we explore probabilities of multiple events occurring together or separately.
Mutually Exclusive Events
Mutually exclusive events are those that cannot happen at the same time. If one event occurs, the other cannot occur. This concept is essential in understanding when the simple addition rule of probability is applicable.

An easy example of mutually exclusive events is tossing a coin. You cannot get both a 'head' and a 'tail' in one toss. They are mutually exclusive.
  • For mutually exclusive events \(A\) and \(B\), the probability of either \(A\) or \(B\) occurring is the sum of their individual probabilities: \(P(A \text{ or } B) = P(A) + P(B)\).
  • This is straightforwardly applicable because there is no overlap between the events.
However, in many real-world scenarios, events may occur simultaneously, making them non-mutually exclusive.
Intersection of Events
The intersection of events refers to situations where two or more events can occur at the same time. This is often represented in probability with the symbol \(\cap\) and is read as 'and'.

When events are not mutually exclusive, the probability of both events happening at the same time, \(P(A \cap B)\), must be considered. This is because these overlapping probabilities can lead to an overestimation if not subtracted.For instance, consider event A as 'rain tomorrow' and event B as 'seeing a rainbow tomorrow'. These are not mutually exclusive because the occurrence of rain often increases the chances of seeing a rainbow. Thus, the intersection \(P(A \cap B)\) is greater than zero and must be subtracted when applying the addition rule:\[P(A \text{ or } B) = P(A) + P(B) - P(A \cap B)\]By accounting for the intersection, we achieve a more accurate measure of the overall probability of either event happening.
Real-world Example
Let's illustrate these concepts with a real-world example: considering the likelihood of the events 'raining tomorrow' (Event A) and 'seeing a rainbow tomorrow' (Event B).In this scenario, the simple addition rule does not apply because the events are not mutually exclusive. Rain increases the conditions favorable for rainbows, so these events overlap.
  • If we only added their individual probabilities without adjustment, we'd be overcounting the likelihood of one or both events occurring together.
  • The corrected addition rule: \(P(A \text{ or } B) = P(A) + P(B) - P(A \cap B)\), ensures we subtract the double-counted intersection \(P(A \cap B)\).
This example shows how real-world situations often require an understanding of non-mutually exclusive events to make accurate probability predictions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(Optional Topic) Alysha makes \(40 \%\) of her free throws. She takes five free throws in a game. If the shots are independent of each other, the probability that she misses the first two shots but makes the other three is about a. \(0.230\). b. \(0.115\). c. \(0.023\). d. \(0.600\).

According to the National Survey of Student Engagement (NSSE), the average amount of time that first-year college st udents spent preparing for class (studying, reading, writing, doing homework or lab work, analyzing data, rehearsing, and other academic activities) in 2019 was 14.44 hours per week. Your college wonders if the average \(\mu\) for its first-year st udents in 2019 differed from the national average. A random sample of 500 students who were first-year students in 2019 claims to have spent an average of \(x=13.4\) hours per week on homework in their first year. What are the null and alternative hypotheses for a comparison of first-year students at your college with national first-year students in \(2019 ?\) a. \(H_{0}: x=14.44, H_{a}: x \neq 14.44\) b. \(H_{0}: x=13.4, H_{\mathrm{a}}: x>13.4\) c. \(H_{0}: \mu=14.44, H_{a}: \mu \neq 14.44\) d. \(H_{0}: \mu=13.4, H_{a}: \mu>13.4\) Testing Blood Cholesterol. The distribution of blood cholesterol level in the population of all adult patients tested in a large hospital over a 10-year period is close to Normal with mean 130 milligrams per deciliter (mg/dL) and standard deviation \(40 \mathrm{mg} /\) dL. You measure the blood cholesterol of 16 adult patients 20 34 years of age. The mean level is \(x=125 \mathrm{mg} / d \mathrm{~L} . A \mathrm{ssume}\) that \(\sigma\) is the same as in the general hospital populationt. Use this information to artswer Quentions \(19.32\) through \(19.34\)

(Optional Topic) Alysha makes \(40 \%\) of her free throws. She takes five free throws in a game. If the shots are independent of each other, the probability that she makes exactly one of five shots is about a. \(0.259\) b. \(0.115\). c. \(0.052\). d. \(0.200\). (Optional Topic) Tracking Your Health. Sample surveys show that more people are tracking changes in their health or paper, spreadsheet, mobile device, or just "in their heads." A survey asked a nationwide random sample of 3014 adults, "Now thinking about your health overall, do you currently keep track of your own weight, diet, or exercise routine, or is this not something you currently do? 10 The population that the poll wants to draw conclusions about is all U.S. residents aged 18 and over. Suppose that, in fact, \(61 \%\) of all adult U.S. residents would say Yes if asked this question. Use this information to answer Questions 19. 48 and 19.49.

(Optional Topic) Retention Rates in a Weight-loss Program. Americans spend more than \(\$ 30\) billion annually on a variety of weightloss products and services. In a study of retention rates of those using the Rewards Program at Jenny Craig in 2005, it was found that about \(18 \%\) of those who began the program dropped out in the first four weeks. 15 Assume that we have a random sample of 300 people beginning the program. a. Assuming that the results of the 2005 study still characterize the general population, what is the mean number of people who would drop out of the Rewards Program within four weeks in a sample of this size? What is the standard deviation? b. What is the probability that at least 235 people in the sample will still be in the Rewards Program after the first four weeks? Check that the Normal approximation is permissible and use it to find this probability. If your software allows, find the exact binomial probability and compare the two results.

When our brains store information, complicated chemical changes take place. In trying to understand these changes, researchers blocked some processes in brain cells taken from rats and compared these cells with a control group of normal cells. They say that "no differences were seen" between the two groups at significance level \(0.05\) in four response variables. They give \(P\)-values \(0.45,0.83,0.26\), and \(0.84\) for these four comparisons. 2 Which of the following statements is correct? a. It is literally true that "no differences were seen." That is, the mean responses were exactly alike in the two groups. b. The mean responses were exactly alike in the two groups for at least one of the four response variables measured but not for all of them. c. The statement "no differences were seen" means that the observed differences were not statistically significant at the significance level used by the researchers. d. The statement "no differences were seen" means that the observed differences were all less than 1 (and were actually \(0.45\), \(0.83,0.26\), and \(0.84\) for these four comparisons).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.