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91Ó°ÊÓ

A manufacturer of consumer electronic equipment makes full use not only of statistical process control, but also of automated testing equipment that efficiently tests all completed products. Data from the testing equipment show that finished products have only \(3.0\) defects per million opportunities. (a) What is \(\mathrm{p}^{-\bar{p}}\) for the manufacturing process? If the process turns out 4000 pieces per day, how many defects do you expect to see per day? In a typical month of 24 working days, how many defects do you expect to see? (b) What are the center line and control limits for a \(p\) chart for plotting daily defect proportions? (c) Explain why a \(p\) chart is of no use at such high levels of quality.

Short Answer

Expert verified
(a) \( p^{\bar{p}} \approx 0.000003 \), expected daily defects \( 0.012 \); monthly \( 0.288 \). (b) Center line \( 0.000003 \); control limits are close to \( \bar{p} \). (c) p-chart is ineffective at high quality due to minimal variability.

Step by step solution

01

Calculate defect probability

The given defect rate is 3.0 defects per million opportunities, which translates to a defect probability \( \bar{p} = \frac{3}{10^6} = 0.000003 \).
02

Calculate expected daily defects

With \( 4000 \) pieces produced per day, the expected number of defects per day is \( 4000 \times \bar{p} = 4000 \times 0.000003 = 0.012 \).
03

Calculate expected defects in a month

In a typical month of 24 working days, the expected number of defects is \( 24 \times 0.012 = 0.288 \).
04

Calculate center line for the p-chart

The center line \( \bar{p} \) for the \( p \) chart is the average daily defect probability, calculated in Step 1 as \( 0.000003 \).
05

Calculate control limits for the p-chart

Control limits for a \( p \) chart are calculated using the formula: \[ UCL = \bar{p} + 3\sqrt{\frac{\bar{p}(1-\bar{p})}{n}} \] \[ LCL = \bar{p} - 3\sqrt{\frac{\bar{p}(1-\bar{p})}{n}} \] where \( n = 4000 \) is the number of units per day. For \( \bar{p} = 0.000003 \), both limits are very close to \( \bar{p} \) due to the low defect rate.
06

Explain the reason for p-chart limitations

At such high levels of quality, the defect rate is so low that any variability will be minimal, making the control chart ineffective for detecting changes or trends, as almost all points will fall inside the control limits.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the P-Chart
A *p-chart*, or proportion chart, is a type of control chart used in statistical process control. It helps monitor the proportion of defective items in a process over time.

The main idea is to check whether a process is "in control" or if something unusual is occurring that might need attention.

This is particularly useful when the quality of items is measured by defective or non-defective categories, rather than a continuous measurement.
  • **P-chart Use:** It's mainly used when you want to track the extent of defects in a manufacturing process across different samples.
  • **Proportion:** It specifically monitors the proportion of defective items out of the total produced.
In the exercise above, since only 3 defects are expected per million opportunities, the p-chart would have values very close to zero. This makes it hard to detect any variations accurately.
Diving into Control Limits
Control limits are key elements of p-charts that define the expected variation in the process. These are statistical boundaries set on either side of the process mean.

Here's how they work:
  • **Upper Control Limit (UCL):** This is the highest value a process measure can reach before it is deemed "out of control." The UCL is calculated using the mean proportion defect rate, \( \bar{p} \), and sample size, \( n \).
  • **Lower Control Limit (LCL):** Similarly, the LCL is the lowest value before a process is flagged for being out of control.
The control limits in our exercise's context were extremely close to the mean defect rate due to the high quality (low defect rate) in the process. This makes utilizing the control limits tricky because any changes would likely be within these narrow limits, suggesting little variation or issues to address.
Understanding Defect Probability
Defect probability is a fundamental measure in quality control that quantifies how likely it is for a given product to have defects.

In mathematical terms, it refers to the proportion of defective items compared to the total number of items checked.
  • **Basic Calculations:** Given as defects per opportunities, it's calculated as \( \bar{p} = \frac{\text{defects}}{\text{opportunities}} \). In our scenario, with a rate of 3 defects per million opportunities, \( \bar{p} = 0.000003 \).
  • **Implications:** With such a low probability, the expected number of daily defects is very minimal, less than one per day, emphasizing the high-quality manufacturing process.
Understanding defect probability helps in setting process control limits and assessing the overall quality consistency over time.
The Role of Quality Control
Quality control is a critical aspect of manufacturing processes focused on maintaining product specification and industry standards.

It helps to ensure that products meet quality requirements and remain consistent, thereby reducing wastage and defects.
  • **Importance:** Frequent monitoring and testing, like what was depicted in the exercise, are essential for identifying potential process issues before they become significant problems.
  • **Statistical Techniques:** Using statistical techniques like p-charts and understanding defect probabilities enable better decision-making and process improvements.
In the context of our exercise, effective quality control shows how low defect rates are the result of stringent controls, making additional monitoring tools like p-charts less effective due to minimal defects occurrence.

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Most popular questions from this chapter

When parts are machined, it is important that they are created with enough precision so that they can be assembled with other parts. No machine can hold dimensions exactly, so it is important that there is an agreed upon level of variation. A company that creates nuts and bolts makes their parts with specific tolerances that follow rules established by an international standard. The nut (or hole) has a slightly larger tolerance than the bolt (or shaft) so that the nuts and bolts will work together. This company uses process control, with samples taken five times during each hour, to ensure the processes are stable and running on target. For the nuts, the process is running with \(\mathrm{x}^{-}=10.004 \mathrm{~mm} \overline{\bar{x}}=10.004 \mathrm{~mm}\) and a sigma estimate of all measurements \(s=0.002 \mathrm{~mm}\). For the bolts, \(\mathrm{x}^{-}=10.000 \mathrm{~mm} \overline{\bar{x}}=10.000 \mathrm{~mm}\) with a sigma estimate of all measurements \(s=0.001 \mathrm{~mm}\). Compute the natural tolerances for both the nuts and bolts. What issue do you see with where the process is currently running?

A manufacturer of ultrasonic parking sensors samples four sensors during each production shift. The expectation is that the sensor will initially alarm if there is an object within 48 inches of the sensor. The sensors are put on a rack and an object is moved toward the sensors at a \(90^{\circ}\) angle until it alarms. The distance from the object to the sensor is recorded. The process mean should be \(\mu=48\) inches. Past experience indicates that the response varies with \(\sigma=0.8\) inch. The mean response distance is plotted on an \(\mathrm{x}^{-} \bar{x}\) control chart. The center line for this chart is (a) \(0.8\) inch. (b) 48 inches. (c) 4 inches.

The unique colors of the cashmere sweaters your firm makes result from heating undyed yarn in a kettle with a dye liquor. The pH (acidity) of the liquor is critical for regulating dye uptake and hence the final color. There are five kettles, all of which receive dye liquor from a common source. Twice each day, the pH of the liquor in each kettle is measured, giving samples of size 5 . The process has been operating in control with \(\mu=5.21\) and \(\sigma=0.147\). (a) Give the center line and control limits for the \(s\) chart. (b) Give the center line and control limits for the \(\mathrm{x}^{-} \bar{x}\) chart.

If the mesh tension of individual monitors follows a Normal distribution, we can describe capability by giving the percent of monitors that meet specifications. The old specifications for mesh tension are \(100-400 \mathrm{mV}\). The new specifications are \(150-350 \mathrm{mV}\). Because the process is in control, we can estimate that tension has mean \(275 \mathrm{mV}\) and standard deviation \(38.4 \mathrm{mV}\). (a) What percent of monitors meet the old specifications? (b) What percent meet the new specifications?

A pharmaceutical manufacturer forms tablets by compressing a granular material that contains the active ingredient and various fillers. The hardness of a sample from each lot of tablets is measured to control the compression process. The process has been operating in control with mean at the target value \(\mu=12.3\) kilograms \((\mathrm{kg}\) ) and estimated standard deviation \(\sigma=0.2\) kg. Table \(31.2\) gives three sets of data, each representing \(\mathrm{x}^{-} \bar{x}\) for 20 successive samples of \(n=4\) tablets. One set remains in control at the target value. In a second set, the process mean \(\mu\) shifts suddenly to a new value. In a third, the process mean drifts gradually. (a) What are the center line and control limits for an \(\mathrm{x}^{-} \bar{x}\) chart for this process? (b) Draw a separate \(x^{-} \bar{x}\) chart for each of the three data sets. Mark any points that are beyond the control limits. (c) Based on your work in part (b) and the appearance of the control charts, which set of data comes from a process that is in control? In which case does the process mean shift suddenly, and at about which sample do you think that the mean changed? Finally, in which case does the mean drift gradually?

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