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How many American teens must be interviewed to estimate the proportion who own an MP3 players within \(\pm 0.02\) with \(99 \%\) confidence using the large- sample confidence interval? Use \(0.5\) as the conservative guess for \(p\). (a) \(n=1692\) (b) \(n=2401\) (c) \(n=4148\)

Short Answer

Expert verified
The required sample size is 4148, so the answer is (c) 4148.

Step by step solution

01

Determine the Confidence Interval Formula

We need to estimate the sample size using the formula for the sample size of a population proportion with a given confidence level: \[ n = \left( \frac{z^2 \cdot p \cdot (1-p)}{E^2} \right) \]where \( n \) is the sample size, \( z \) is the z-score corresponding to the desired confidence level, \( p \) is the estimated proportion of the population, and \( E \) is the margin of error.
02

Identify the Given Values

The confidence level is 99%, which corresponds to a z-score of approximately 2.576. The margin of error, \( E \), is 0.02, and the estimated proportion, \( p \), is 0.5.
03

Plug in the Values into the Formula

Substitute the known values into the formula:\[ n = \left( \frac{2.576^2 \cdot 0.5 \cdot (1-0.5)}{0.02^2} \right) \]
04

Calculation

Calculate the expression step-by-step:1. Calculate \( z^2 \): \( 2.576^2 = 6.635776 \)2. Calculate \( p(1-p) \): \( 0.5(1-0.5) = 0.25 \)3. Calculate the denominator: \( 0.02^2 = 0.0004 \)4. Put it all together: \[ n = \left( \frac{6.635776 \cdot 0.25}{0.0004} \right) = \frac{1.658944}{0.0004} = 4147.36 \]Since the sample size must be a whole number, round up to 4148.
05

Choose the Correct Answer From Options

After rounding, the required sample size is 4148. Therefore, the correct answer from the given options is (c) \( n = 4148 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
When we talk about confidence intervals, we are exploring how confident we are, in terms of probability, about where the true population parameter will place itself based on our sample data. Imagine it like this: if you were to measure the heights of a group of people and averaged it, you'd like to have an interval that gives you a probable range of what the true average height of the whole population might be. The key here is the percentage of confidence we apply, such as 99%. This high percentage indicates that if we were to take numerous samples and compute intervals, 99% of those intervals would contain the real population parameter.

In the context of the sample size calculation for the proportion of teens owning MP3 players, a 99% confidence level is chosen. This high level implies a wider confidence interval because we want to be more certain about capturing the true proportion. However, achieving such a high confidence comes with the necessity of larger sample sizes, which we will explore further.
Population Proportion
The population proportion is a key concept in statistics that refers to the ratio or fraction of individuals in the total population who have a particular characteristic. In simpler terms, it's like saying, out of everyone, how many share the trait we're interested in? In our exercise, the characteristic of interest is owning an MP3 player.

For calculations involving sample sizes, often an estimated proportion is used when actual data is not available. Here, the number 0.5 is used as a conservative estimate. Why 0.5? Because it represents the point of maximum uncertainty or variability. If we're unsure about the exact population proportion, 0.5 ensures the sample size calculation accounts for the worst-case scenario, hence ensuring robustness in the results.
Margin of Error
The margin of error quantifies the uncertainty or variability of a sample estimate. It provides a buffer zone around the sample estimate to indicate the range within which the true population parameter is likely to fall. Think of it like saying, "I'm pretty sure the exact figure isn't just my estimate—it'll probably be a little higher or lower, within this margin."

In the exercise, we have a margin of error of 0.02 (or 2%). This means we're looking for an estimate that is within 2 percentage points of the true proportion of all American teens who own MP3 players. Smaller margins of error demand larger sample sizes, as they require more precise estimates, which increases the reliability of the data.
Z-Score
Z-scores are statistical figures that tell us how many standard deviations away from the mean a data point is. It helps gauge where a particular point stands relative to other data. In sampling and confidence intervals, z-scores correspond to confidence levels, aiding in determining how broad an interval is.

For our exercise, the z-score is 2.576, correlating with a 99% confidence level. This essentially means, for normally distributed data, the area under the curve that corresponds to this z-score ensures that our sample estimate has a 99% probability of encompassing the true population value. As the z-score increases (implying higher confidence), the interval around our estimate widens, directly impacting the sample size calculation, pushing for larger samples to maintain accuracy.

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