/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 To study whether higher predicti... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

To study whether higher predictions are rated as more accurate than lower predictions, 161 college students were presented a prediction by a basketball expert about the winner of an upcoming basketball game between teams A and B. All participants learned that the expert had carefully examined the two teams' history, players, and other information. Eighty students were randomly assigned to a group in which the expert claimed the chance that A would win was \(70 \%\). The other 81 students were assigned to a group in which the expert claimed that the chance B would win was \(30 \%\). All students rated the expert on his accuracy using a scale ranging from 0 to 20 , with higher scores indicating greater accuracy. Are the conditions for two-sample \(t\) inference satisfied? (a) Maybe: the SRS condition is OK but we need to look at the data to check Normality. (b) No: scores in a range between 0 and 20 can't be Normal. (c) Yes: the SRS condition is OK and large sample sizes make the Normality condition unnecessary.

Short Answer

Expert verified
Option (c) is correct: the SRS condition is satisfied, and large sample sizes make the Normality condition unnecessary.

Step by step solution

01

Understand the Problem

We are presented with a problem that involves checking the conditions for two-sample t inference based on a survey given to two groups of students who rated a basketball expert's prediction accuracy. The focus is on understanding whether conditions for this statistical test are met.
02

Check SRS Condition

The problem statement indicates that each group of students was randomly assigned, implying a simple random sample (SRS) condition is satisfied for both groups. This is one of the requirements for two-sample t inference.
03

Consider Normality and Sample Size

While checking Normality usually involves looking at data distributions, in practice, the use of larger sample sizes (e.g., total sample of 161 with 80 in one group and 81 in another) allows the Central Limit Theorem to apply. This theorem states that for large sample sizes, the sampling distribution of the sample mean is approximately normal regardless of the data's distribution.
04

Evaluate the Options

Given that the SRS condition is satisfied, and the sample sizes are sufficiently large, the most appropriate choice is that the large sample sizes make the Normality condition unnecessary. Option (c) directly addresses this by stating: 'Yes: the SRS condition is OK and large sample sizes make the Normality condition unnecessary.'

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Simple Random Sample (SRS)
A Simple Random Sample (SRS) is a foundational concept in statistics that ensures each member of a population has an equal chance of being selected. This is crucial because it reduces bias, allowing conclusions drawn from the sample to be more representative of the entire population. In the given exercise, students were randomly assigned to two different groups. This random assignment is indicative of an SRS, thereby fulfilling one of the key requirements for performing two-sample t inference.
The importance of SRS lies in its ability to provide:
  • Unbiased results that are generalizable to the broader population.
  • A sound basis for statistical inference because every member has an equal chance of selection.
  • The ability to control for confounding variables through random assignment.
Without meeting the SRS condition, any further statistical analysis might be questionable, as bias could influence the results. Therefore, having SRS ensures that the analysis proceeds credibly for both groups.
Normality condition
The Normality condition is another important aspect of statistical inference. This condition requires that the data should, ideally, follow a normal distribution in order for certain statistical tests, like the t-test, to be valid. Practically, it is often evaluated by checking the shape of the data's distribution or by considering the sample size.
In the context of the exercise, while individual scores range between 0 and 20, the larger sample sizes significantly ease concerns about this condition. Here, instead of visually checking distribution for normality, statistical principles provide reassurance.
  • If the sample size is large enough—typically over 30—deviations from normality are less alarming.
  • The distribution of the sample mean will tend towards a normal distribution as sample size increases, as per Central Limit Theorem.
Thus, in large samples like the one with 161 students, the requirement for strictly normal data is relaxed, making the study's conclusions more robust and reliable.
Central Limit Theorem
The Central Limit Theorem (CLT) is a powerful tool in statistics providing insight into how distributions behave when sampling from a population. It states that the distribution of the sample mean will approach a normal distribution as the sample size increases, regardless of the initial distribution of the population. This theorem is particularly useful in situations where normality is an initial concern.
In our scenario, even though the individual accuracy ratings might not normally distribute, the CLT suggests that with 80 students in one group and 81 in the other, both are sufficiently large to assume a normal distribution of the sample mean.
  • The CLT helps justify using t-tests without strict normality by focusing on the sample mean.
  • It provides confidence, through large samples, that normal approximation of the sampling distribution is valid.
By applying the CLT, researchers can confidently perform t-tests and make accurate inferences about population parameters based on sample data, even when the original data does not follow a normal distribution.

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Most popular questions from this chapter

Credit card companies earn a percent of the amount charged on their credit cards, paid by the stores that accept the card. A credit card company compares two proposals for increasing the amount that its customers charge on their credit cards. Proposal 1 offers to eliminate the annual fee for customers who charge \(\$ 1800\) or more during the year on their card. Proposal 2 offers a small percent of the total amount charged as a cash reward at the end of the year. The credit card company offers each proposal to an SRS of 100 of its existing customers. At the end of the year, the total amount charged by each customer is recorded. Here are the summary statistics. $$ \begin{array}{lccc} \hline \text { Group } & n & x^{-} \bar{x} & s \\ \hline \text { Proposal 1 } & 100 & \$ 1319 & \$ 261 \\ \hline \text { Proposal 2 } & 100 & \$ 1372 & \$ 274 \\ \hline \end{array} $$ (a) Do the data show a significant difference between the mean amounts charged by customers offered the two proposed plans? Give the null and alternative hypotheses, and calculate the two-sample \(t\) statistic. Obtain the \(P\)-value, using Option 2. State your practical conclusions. (b) The distributions of the amounts charged on credit cards are skewed to the right. However, outliers are prevented by the limits that the credit card companies impose on credit balances. Do you think that skewness threatens the validity of the text that you used in part (a)? Explain your answer.

Choose a random sample of 100 married couples. Ask each member of the couple how much time they spend looking at their smartphone while at home. Compare the mean times for the two members of couples.

In a study of the effects of mood on evaluation of nutritious food, 208 subjects were randomly assigned to read either a happy story (to induce a positive mood) or a control (no story, neutral mood) group. Subjects were then asked to evaluate their attitude toward a certain indulgent food on a nine- point scale, with higher numbers indicating a more positive attitude toward the food. The following table summarizes data on the attitude rating: \({ }^{14}\) $$ \begin{array}{lccc} \hline \text { Group } & n & \mathrm{x}^{-} \bar{x} & \mathrm{~s} \\ \hline \text { Positive mood } & 104 & 4.30 & 2.05 \\ \hline \text { Neutral mood } & 104 & 5.50 & 1.74 \\ \hline \end{array} $$ (a) What are the standard errors of the sample means of the two groups? (b) What degrees of freedom does the conservative Option 2 use for twosample \(t\) procedures for these data? (c) Test the null hypothesis of no difference between the two group means against the two-sided alternative. Use the degrees of freedom from part (b).

In the autumn, contests for the largest pumpkin are held in several counties in Ohio. Winners can weigh more that 1500 pounds. Two new varieties of pumpkin are to be compared to see which produces the largest pumpkins. To do this, 10 plots of land located in different regions of the state will be used. Half of each plot will be planted with one pumpkin variety and half with the other variety. You compare the weights of both varieties and use (a) the two-sample \(t\) test. (b) the matched pairs \(t\) test. (c) the one-sample \(t\) test.

A research firm supplies manufacturers with estimates of the sales of their products from samples of stores. Marketing managers often look at the sales estimates and ignore sampling error. An SRS of 50 stores this month shows mean sales of 41 units of a particular appliance with standard deviation of 11 units. During the same month last year, an SRS of 52 stores gave mean sales of 38 units of the same appliance with a standard deviation of 13 units. An increase from 38 to 41 is a rise of \(7.9 \%\). The marketing manager is happy because sales are up \(7.9 \%\). (a) Give a 95\% confidence interval for the difference in mean number of units of the appliance sold at all retail stores. (b) Explain in language that the manager can understand why he cannot be confident that sales rose by \(7.9 \%\) and, in fact, may have dropped.

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