/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 Is this coin balanced? While he ... [FREE SOLUTION] | 91Ó°ÊÓ

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Is this coin balanced? While he was a prisoner of war during World War II, 14.36 John Kerrich tossed a coin 10,000 times. He got 5067 heads. If the coin is perfectly balanced, the probability of a head is \(0.5\). Is there reason to think that Kerrich's coin was not balanced? To answer this question, find the probability that tossing a balanced coin 10,000 times would give a count of heads at least this far from 5000 (that is, at least 5067 heads or no more than 4933 heads).

Short Answer

Expert verified
No, Kerrich's coin is not unbalanced with a significance level of 0.05.

Step by step solution

01

Define the problem

We want to determine whether a coin that is tossed 10,000 times could result in 5067 heads under the assumption that the coin is balanced. This will involve checking for a significant deviation from 5000 heads.
02

Calculate the expected value and standard deviation

For a balanced coin, the probability of getting a head on any single toss is \( p = 0.5 \). If the coin is tossed \( n = 10,000 \) times, the expected number of heads, \( \mu \), is \( n \cdot p = 10,000 \times 0.5 = 5000 \). The standard deviation, \( \sigma \), is given by \( \sqrt{n \cdot p \cdot (1 - p)} = \sqrt{10,000 \times 0.5 \times 0.5} = \sqrt{2500} = 50 \).
03

Calculate the z-score for 5067 heads

The z-score will help measure how far the observed value deviates from the expected value in terms of standard deviations. The z-score is calculated as \( z = \frac{(X - \mu)}{\sigma} \), where \( X = 5067 \). So, \( z = \frac{(5067 - 5000)}{50} = \frac{67}{50} = 1.34 \).
04

Calculate the probability using z-score

Using standard normal distribution tables, we find the probability corresponding to a z-score of 1.34. This gives the probability of getting at most 5067 heads. Use \( P(Z \leq 1.34) \) which roughly equals 0.9099. Hence, \( P(Z \geq 5067) = 1 - 0.9099 = 0.0901 \). This is the area in one tail of the distribution.
05

Consider both tails of distribution

Since we are interested in deviations in both directions (at least 5067 heads or no more than 4933 heads), double the tail probability: \( 2 \times 0.0901 = 0.1802 \). This represents the probability that a balanced coin would show a result this extreme.
06

Conclusion

Because 0.1802 is greater than a common significance level (such as 0.05), there is insufficient evidence to conclude that the coin is unbalanced based on Kerrich’s experiment results.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability theory is a branch of mathematics that deals with the likelihood of events occurring. It helps in understanding and quantifying uncertain occurrences, such as the outcome of tossing a coin. When dealing with probabilities, values range from 0 to 1. A probability of 0 means that an event will not happen, while a probability of 1 signifies certainty.
For a balanced coin, the probability of getting heads in a single toss is 0.5, meaning there is an equal chance for it to land on heads or tails. **In this context:**
  • The probability of getting heads or tails is called a 'simple probability.'
  • The event of getting heads 5,067 times out of 10,000 in Kerrich’s experiment involves 'binomial probability,' dealing with the repeated independent events of coin tosses.
Understanding these concepts allows us to evaluate if such a result deviates significantly from what's expected.
Standard Deviation
Standard deviation is a measure that tells us how much variation or dispersion there is from the average (or mean). In simpler terms, it indicates how spread out the outcomes are in a set of data. The smaller the standard deviation, the closer the data points are to the mean, and vice versa.
When we calculate standard deviation in the context of coin tosses, we use the formula for binomial distribution: \[ \sigma = \sqrt{n \cdot p \cdot (1 - p)} \]where:\[ n \] is the number of trials, \[ p \] is the probability of success per trial, and \[ (1 - p) \] is the probability of failure per trial. In Kerrich’s case, using 10,000 tosses, we found a standard deviation of 50. This helps us understand how much the number of heads can vary around the expected 5,000.
  • A larger standard deviation indicates the results will have more potential to vary widely from the mean.
  • A smaller standard deviation indicates that the results are likely clustered near the mean.
This concept is key in understanding how typical or atypical our observed result is.
Normal Distribution
The normal distribution, often referred to as a "bell curve," is a probability distribution that is symmetric around the mean. In many natural phenomena, it is observed that data values tend to cluster around a central point with decreasing frequencies as they move away from this center.
In our coin toss scenario, given enough trials (like Kerrich's 10,000 tosses), the distribution of heads should theoretically form a normal distribution. This helps because:
  • The mean (\[ \mu = 5000 \]) is at the center of the curve.
  • The standard deviation indicates how spread out the values are across the distribution.
  • Z-scores can be used to find how far an observed number (like 5,067 heads) lies from the mean in terms of standard deviations.
We discovered this by calculating a z-score of 1.34, which is used to understand where the outcome sits in the normal distribution. If we use normal distribution tables or software, we can identify the likelihood of observing 5,067 heads if the coin is truly balanced. This helps in making statistical conclusions about our hypothesis around balance.

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