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False positives in testing for HIV. A rapid test for the presence in the blood of antibodies to HIV, the virus that causes AIDS, gives a positive result with probability about \(0.004\) when a person who is free of HIV antibodies is tested. A clinic tests 1000 people who are all free of HIV antibodies. (a) What is the distribution of the number of positive tests? (b) What is the mean number of positive tests? (c) You cannot safely use the Normal approximation for this distribution. Explain why.

Short Answer

Expert verified
(a) Binomial distribution \((n=1000, p=0.004)\). (b) Mean is 4. (c) \(np < 10\), condition failed.

Step by step solution

01

Determine the Distribution

The number of positive tests out of 1000 tests each with a probability of positive result given a false positive is a classic setting for a binomial distribution. Therefore, the distribution of the number of positive tests is a binomial distribution with parameters: number of trials \(n = 1000\) and probability of success (a positive test given no antibodies) \(p = 0.004\).
02

Calculate the Mean of the Distribution

For a binomial distribution \(B(n, p)\), the mean is calculated using the formula \(\mu = np\). Substituting the given values, we have \(\mu = 1000 \times 0.004 = 4\). Therefore, the mean number of positive tests is 4.
03

Check Conditions for Normal Approximation

For a binomial distribution to be approximated by a normal distribution, the conditions \(np \geq 10\) and \(n(1-p) \geq 10\) must hold. Here, \(np = 4\) and \(n(1-p) = 996\). Since \(np < 10\), the normal approximation isn't sufficient in this case.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

False Positives
In a medical testing scenario, a false positive occurs when a test indicates the presence of a condition, such as HIV antibodies, even though it is not actually present in the person being tested. This can happen due to the inherent error rate in the testing method.
In the exercise example, the rapid HIV test has a false positive rate of 0.4%, which means that there is a 0.004 probability for a person without HIV antibodies to receive a positive test result.
Considering a scenario where 1000 people who are free of HIV antibodies are tested, these false positives can collectively become significant, leading us to investigate how many false positive results can be expected.
Mean Calculation
In probability distributions, the mean, denoted by \( \mu \), gives the expected average or the central value of a random variable. For a binomial distribution, which applies here due to the testing scenario, the mean can be easily calculated using the formula:

\[ \mu = np \]

where \( n \) is the number of trials and \( p \) is the probability of success for each trial. In this case, a 'success' is defined as a false positive test result. The number of trials \( n = 1000 \), and the probability of a false positive result is \( p = 0.004 \). By substituting these values into the formula, we get:

\[ \mu = 1000 \times 0.004 = 4 \]

Thus, the expected number of false positive test results is 4.
Normal Approximation
The normal approximation to a binomial distribution is a technique used to simplify calculations. It allows us to use the normal distribution to approximate the binomial distribution under certain conditions. However, not all scenarios are suitable for this approximation.
The criteria for using a normal approximation include:
  • The product \( np \) (mean of the distribution) should be at least 10.
  • The product \( n(1-p) \) (mean of the complements) should also be at least 10.
In the exercise's context, we calculated the expected number of false positives, \( np \), as 4 - which is less than the required 10. This makes the binomial distribution not well-suited for normal approximation, as it would not accurately reflect the distribution of false positives in this scenario.

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