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Who Takes the GMAT? In many settings, the "rules of probability" are just basic facts about percents. The Graduate Management Admission Test (GMAT) website provides the following information about the geographic region of citizenship of those who took the test in \(2015: 2.1 \%\) were from Africa; \(0.4 \%\) were from Australia and the Pacific Islands; \(2.5 \%\) were from Canada; \(12.9 \%\) were from Central and South Asia; \(32.0 \%\) were from East and Southeast Asja; 2.0\% were from Eastern Europe; \(3.2 \%\) were from Mexico, the Caribbean, and Latin America; \(3.0 \%\) were from the Middle East; \(34.2 \%\) were from the United States; and \(7.7 \%\) were from Western Europe.3 (a) What percent of those who took the test in 2015 were from North America (either Canada, the United States, Mexico, the Caribbean, or Latin America)? Which rule of probability did you use to find the answer? (b) What percent of those who took the test in 2015 were from some other region than the United States? Which rule of probability did you use to find the answer?

Short Answer

Expert verified
(a) 39.9% of test-takers were from North America using the additive rule. (b) 65.8% were from regions other than the U.S. using the complementary rule.

Step by step solution

01

Identifying North American Regions

North America comprises Canada, the United States, Mexico, the Caribbean, and Latin America. We need to add these percentages to find the answer.
02

Calculating Percent from North America

Add the percentages for Canada (2.5%), the United States (34.2%), and Mexico, the Caribbean, and Latin America (3.2%). \(2.5\% + 34.2\% + 3.2\% = 39.9\%\)
03

Identifying Regions Other Than the United States

To find the percentage from regions other than the United States, we need to add the percentages of all regions except the United States.
04

Calculating Percent from Other Regions

Find the sum of all other regions: \(2.1\% + 0.4\% + 2.5\% + 12.9\% + 32.0\% + 2.0\% + 3.2\% + 3.0\% + 7.7\%\)This equals \(65.8\%\).
05

Applying Probability Rule

For part (a), we used the additive rule of probability, where to find the probability of either of multiple events, we sum their individual probabilities. For part (b), we used the complementary rule, finding what was not in the United States (by subtracting the percentage for the United States from 100%).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Additive Rule of Probability
The Additive Rule of Probability is a simple yet powerful tool in probability theory. It is used to find the probability of any one of multiple events occurring. This rule is applicable to both mutually exclusive and non-mutually exclusive events.

When events are mutually exclusive (they cannot happen at the same time), the rule states that the probability of either event A or event B occurring is the sum of their individual probabilities:
  • \( P(A \cup B) = P(A) + P(B) \)
For non-mutually exclusive events, you must adjust for any overlap between events. The formula becomes:
  • \( P(A \cup B) = P(A) + P(B) - P(A \cap B) \)
In our exercise, since the regions in North America cannot overlap (you cannot be from two different countries at once), we simply added their probabilities (percentages). This real-world application of the additive rule helps you logically break down large datasets into understandable segments.
Complementary Rule of Probability
The Complementary Rule of Probability is essential when you want to find out the probability of an event not happening. It's based on the concept that the sum of the probabilities of all possible outcomes of a particular event is one (or 100%).

The formula is:
  • \( P( ext{{not A}}) = 1 - P(A) \)
This rule is particularly straightforward: if you know the probability of an event occurring, subtract it from one to get the probability of it not occurring.

In our GMAT exercise, we wanted to calculate the percentage of test takers from regions other than the United States. Here, the complementary rule was employed by subtracting the percentage of U.S. test-takers from 100% to get the percentage from other regions. Understanding this rule can save time by avoiding counting each possibility individually.
Geographic Data Analysis
Geographic Data Analysis in probability involves analyzing data that is grouped by geographic regions. This method provides insight into how different regions contribute to a dataset, like the population of GMAT test-takers by region.

Using geographic data helps identify patterns or trends. For instance, in our exercise, we could see a significant percentage of test-takers from East and Southeast Asia. Understanding these patterns is crucial for making informed decisions, whether in business, education, or public policy.

Analyzing geographic information often involves classifying data into discrete groups (such as continents or countries) and applying probability rules to derive meaningful insights. It's a way of contextualizing numbers by recognizing cultural, economic, and regional influences that might affect the data. Geographic data underscores the importance of both probability rules and data interpretation in presenting a holistic view of the analyzed dataset.

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Most popular questions from this chapter

Land in Canada. Canada's national statistics agency, Statistics Canada, says that the land area of Canada is \(9,094,000\) square kilometers. Of this land, \(4,176,000\) square kilometers are forested. Choose a square kilometer of land in Canada at random. (a) What is the probability that the area you chose is forested? (b) What is the probability that it is not forested?

Are They Disjoint? Which of the following pairs of events, \(A\) and \(B\), are disjoint? Explain your answers. (a) A person is selected at random. A is the event \({ }^{\alpha}\) sex of the person selected is male"; \(B\) is the event "sex of the person selected is female." (b) A person is selected at random. \(A\) is the event "the person selected earns more than \(\$ 100,000\) per year"; \(B\) is the event "the person selected earns more than \(\$ 250,000\) per year." (c) A pair of dice are tossed. \(A\) is the event "one of the dice is a \(3^{\prime \prime}, B\) is the event "the sum of the two dice is 3 ."

2 Sample space. In each of the following situations, describe a sample space for the random phenomenon. (a) A basketball player shoots four free throws. You record the sequence of hits and misses. (b) A basketball player shoots four free throws. You record the number of baskets she makes.

The Medical College Admission Test. The Normal distribution with mean \(\mu=499.6\) and standard deviation \(\sigma=10.4\) is a good description of the total score on the Medical College Admission Test (MCAT). \({ }^{9}\) This is a continuous probability model for the score of a randomly chosen student. Call the score of a randomly chosen srudent \(X\) for short. (a) Write the event "the student chosen has a score of 510 or higher" in terms of \(\boldsymbol{K}\). (b) Find the probability of this event.

Running a Mile. A study of 12,000 able-bodied male students at the University of Illinois found that their times for the mile run were approximately Normal with mean \(7.11\) minutes and standard deviation \(0.74\) minute. \({ }^{11}\) Choose a student at random from this group and call his time for the mile \(Y\). (a) Is \(Y\) a finite or continuous random variable? Explain your answer. (b) Say in words what the meaning of \(P(Y \geq 3.0)\) is. What is this probability? (c) Write the event "the student could run a mile in less than 6 minutes" in terms of values of the random variable \(Y\). What is the probability of this event?

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