/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 Find the value of \(x.\) $$3: ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the value of \(x.\) $$3: x=x: 12$$

Short Answer

Expert verified
The value of x is 6 or -6, depending on the context. If x cannot be negative, the solution is x = 6.

Step by step solution

01

Understand the Proportion

The given equation is a proportion that states the ratio of 3 to x is equal to the ratio of x to 12. This can be expressed as the equation \(3/x = x/12\).
02

Cross-Multiply

To find the value of x, cross-multiply the terms of the proportion. This means multiplying the numerator of one ratio by the denominator of the other. The equation becomes \(3 \times 12 = x \times x\) which simplifies to \(36 = x^2\).
03

Solve for x

To solve for x, take the square root of both sides of the equation \(x^2 = 36\). Remember that taking the square root gives two possible solutions, a positive and a negative value. Therefore, \(x = \sqrt{36}\) which gives us \(x = \pm6\). However, if x represents a quantity that cannot be negative in the given context, such as length, the negative solution would be extraneous and we would take \(x = 6\) as the only meaningful solution.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cross-Multiplication
Cross-multiplication is a valuable technique used to solve proportions—equations that express one ratio equal to another, like the original problem \(3: x = x: 12\). The method simplifies the process of finding an unknown value within these ratios.

To cross-multiply, you take the numerator of one ratio and multiply it by the denominator of the other ratio and set it equal to the product of the remaining numerator and denominator. In the given exercise, cross-multiplication transformed the proportion \(3/x = x/12\) into the equation \(3 \times 12 = x \times x\), which simplifies to \(36 = x^2\). This direct approach easily turns a problem involving ratios into a more familiar form—a simple algebraic equation, in this case, a quadratic equation that can be solved for the value of \(x\).
Solving Quadratic Equations
Quadratic equations are polynomial equations of the second degree, typically in the form \(ax^2 + bx + c = 0\). Solving them involves finding the value(s) of \(x\) that make the equation true.

In the step-by-step solution for our proportion problem, after cross-multiplication, we obtained the quadratic equation \(x^2 = 36\). To solve this, we look for values of \(x\) which, when squared, give 36. Taking the square root of both sides of the equation gives us \(x = \pm6\), revealing that there are two potential solutions. It's important to consider the context of the problem when determining which solution is meaningful; if the variable represents a physical quantity that cannot be negative, we would discard the negative solution. When solving quadratic equations, other methods like factoring, completing the square, or using the quadratic formula might also be used, depending on the form of the equation.
Ratios
Ratios are comparative values expressing the relationship between quantities. They can be written in several ways: as fractions, with a colon, or with the word 'to'.

In the exercise, the ratio \(3:x\) compares the number 3 to \(x\), and similarly, \(x:12\) compares \(x\) to 12. Ratios are essential in various fields such as mathematics, science, engineering, and finance as they provide a way to compare quantities in a relative sense. Understanding ratios is fundamental to working on problems involving rates, scales, and proportions. When two ratios are set equal, they form a proportion, indicating that the two comparisons are equivalent. This equivalence is the basis of many problem-solving techniques, including the cross-multiplication method used in the given exercise.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Boyle's law states that for a confined gas at a constant temperature, the product of the pressure and the volume is a constant. Another way of stating this law is that the pressure is inversely proportional to the volume, or that the volume is inversely proportional to the pressure. Assume a constant temperature in the following problems. The air in a cylinder is at a pressure of \(14.7 \mathrm{lb} / \mathrm{in.}^{2}\) and occupies a volume of 175 in. \(^{3}\) Find the pressure when it is compressed to 25.0 in. \(^{3} .\)

The inverse square law states that for a surface illuminated by a light source, the intensity of illumination on the surface is inversely proportional to the square of the distance between the source and the surface. A certain light source produces an illumination of 800 lux (a lux is 1 lumen per square meter) on a surface. Find the illumination on that surface if the distance to the light source is doubled.

The inverse square law states that for a surface illuminated by a light source, the intensity of illumination on the surface is inversely proportional to the square of the distance between the source and the surface. A light source located \(2.75 \mathrm{m}\) from a surface produces an illumination of \(528 \mathrm{lux}\) on that surface. Find the illumination if the distance is changed to \(1.55 \mathrm{m}\).

If the base and the altitude of a triangle are both halved, by what factor will the area change?

When an electric current flows through a wire, the resistance to the flow varies directly as the length and inversely as the cross-sectional area of the wire. If the length and the diameter are both tripled, by what factor will the resistance change?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.