Chapter 12: Problem 5
Solve by quadratic formula. Give your answers in decimal form to three significant digits. Check some by calculator. $$2 x^{2}-15 x+9=0$$
Short Answer
Expert verified
x ≈ 0.766, x ≈ 5.73.
Step by step solution
01
Identify the coefficients
For the quadratic equation of the form ax^2 + bx + c = 0, identify the coefficients a, b, and c. Here, a = 2, b = -15, and c = 9.
02
Set up the quadratic formula
The quadratic formula is given by x = (-b ± √(b^2 - 4ac)) / (2a). Substitute a, b, and c into the formula with the values identified in Step 1.
03
Calculate the discriminant
Find the value of the discriminant, which is b^2 - 4ac. In this case, it is (-15)^2 - 4(2)(9).
04
Compute the solutions
Calculate the two possible values for x using the plus and minus signs in the formula separately. Then simplify to get the values in decimal form.
05
Check by calculator
Verify the solutions obtained by using a calculator, making sure the answers are rounded to three significant digits.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Solving Quadratic Equations
Quadratic equations are of the form \( ax^2 + bx + c = 0 \), where \( a \), \( b \) and \( c \) are coefficients and \( x \) represents the variable. Solving these equations often leads to finding the value(s) of \( x \) that make the equation true. The most universal method for solving these is the quadratic formula, which is \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \).
To apply this formula, follow these steps:
To apply this formula, follow these steps:
- Identify the coefficients in the equation. Coefficients are the numerical parts before the variables.
- Substitute these coefficients into the quadratic formula.
- Calculate the discriminant (the part under the square root sign in the formula), as it determines the nature and number of solutions.
- Solve for \( x \) using the plus and minus signs (\pm) in the formula, yielding two possible solutions for \( x \).
- Round off the values to the required number of significant digits for accuracy.
Quadratic Equation Coefficients
In any quadratic equation of the form \( ax^2 + bx + c = 0 \) the coefficients are crucial as they define the curve's characteristics. The coefficient \( a \) affects the width and direction of the parabola, \( b \) impacts the position of the vertex horizontally, and \( c \) determines the height at which the parabola crosses the y-axis.
When approaching a problem:
When approaching a problem:
- Identify each coefficient carefully and assess its sign (+ or –), as the sign can affect the direction of operations in the quadratic formula.
- Remember that the quadratic equation itself represents a parabola when plotted on a graph, and the roots or solutions to the equation are the points where this parabola crosses the x-axis.
- The coefficient \( a \) must not be zero, as it would no longer form a quadratic equation but a linear one instead.
Discriminant Calculation
The discriminant in a quadratic equation is a profound concept as it determines the nature and quantity of roots the equation will have. It is denoted as \( b^2 - 4ac \) within the quadratic formula. The value of the discriminant can lead to three scenarios:
To compute the discriminant, square the coefficient \( b \) and then subtract four times the product of coefficients \( a \) and \( c \) from it. In our example, calculating \( (-15)^2 - 4(2)(9) \) gives us 225 - 72, equating to a positive discriminant of 153. Hence, we expect two real solutions for this particular quadratic equation.
- If the discriminant is positive, there will be two distinct real solutions.
- If the discriminant is zero, there will be exactly one real solution (also known as a repeated or double root).
- If the discriminant is negative, there will be no real solutions. Instead, there will be two complex solutions.
To compute the discriminant, square the coefficient \( b \) and then subtract four times the product of coefficients \( a \) and \( c \) from it. In our example, calculating \( (-15)^2 - 4(2)(9) \) gives us 225 - 72, equating to a positive discriminant of 153. Hence, we expect two real solutions for this particular quadratic equation.