Chapter 4: Problem 1
Let \(f(x)=e^{x}-\sin x .\) Complete the following table using the approximation formula $$ f^{\prime}\left(x_{0}\right) \approx \frac{-3 f\left(x_{0}\right)+4 f\left(x_{0}+h\right)-f\left(x_{0}+2 h\right)}{2 h} $$ \begin{tabular}{c|c|c} \(h\) & approximate \(f^{\prime}(2)\) & ahs. error \\ \hline .01 & & \\ .005 & & \\ -.005 & & \\ -.01 & & \\ & & \end{tabular} Is it OK to use negative values for \(h ?\)
Short Answer
Step by step solution
Apply the Approximation Formula for h = 0.01
Apply the Formula for h = 0.005
Apply the Formula for h = -0.005
Apply the Formula for h = -0.01
Evaluate Absolute Errors and Use of Negative h
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Approximation Formula
- \[ f^{\prime}(x_0) \approx \frac{-3f(x_0) + 4f(x_0 + h) - f(x_0 + 2h)}{2h} \]
Absolute Error
- Calculate the exact value: \(e^2 - \cos 2\).
- Compute the approximation using the formula for a specific \(h\).
- The absolute error is the absolute difference between the true value and the approximated value: \(|\text{True Value} - \text{Approximation}|\).
Backward Difference
- Our approximation formula becomes inverted over intervals behind \(x_0\).
- \[ f^{\prime}(x_0) \approx \frac{-3f(x_0) + 4f(x_0 - h) - f(x_0 - 2h)}{2(-h)} \]
Derivative Calculation
- Evaluate \(f\) at multiple points using the function provided \(f(x) = e^x - \sin x\).
- Substitute these values into our finite difference formula.
- Carry out the arithmetic to compute the rate of change at the desired point.