/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 Some sequences do not have an or... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Some sequences do not have an order of convergence. Let \(p_{n}=\frac{2^{n}}{n !}\). (a) Show that \(\lim _{n \rightarrow \infty} p_{n}=0\). (b) Show that \(\lim _{n \rightarrow \infty} \frac{\left|p_{n+1}\right|}{\left|p_{n}\right|}=0\). (c) Show that \(\left\langle\frac{\left|p_{n+1}\right|}{\left|p_{n}\right|^{\alpha}}\right\rangle\) diverges for any \(\alpha>1\).

Short Answer

Expert verified
(a) \(\lim_{n \to \infty} p_n = 0\). (b) \(\lim_{n \to \infty} \frac{|p_{n+1}|}{|p_n|} = 0\). (c) Sequence diverges for \(\alpha > 1\).

Step by step solution

01

Prove \( \lim_{n \to \infty} p_n = 0 \)

Consider the sequence \( p_n = \frac{2^n}{n!} \). We need to show that this sequence approaches zero as \( n \to \infty \).Recall that \( n! = 1 \cdot 2 \cdot 3 \cdots n \). For \( n \geq 2 \), each factor in the factorial is greater than or equal to 2, hence \( n! \geq 2 \cdot 2 \cdot 2 \cdots \text{(n times)} = 2^{n-1} \). Therefore, \( \frac{2^n}{n!} \leq \frac{2^n}{2^{n-1}} = 2 \cdot \frac{1}{n} \).As \( n \to \infty \), the term \( \frac{1}{n} \to 0 \), and consequently, \( p_n \to 0 \). Thus, \( \lim_{n \to \infty} p_n = 0 \).
02

Prove \( \lim_{n \to \infty} \frac{|p_{n+1}|}{|p_n|} = 0 \)

We need to compute \( \frac{p_{n+1}}{p_n} = \frac{2^{n+1}/(n+1)!}{2^n/n!} \).Simplify the expression: \[\frac{p_{n+1}}{p_n} = \frac{2^{n+1}}{(n+1)!} \cdot \frac{n!}{2^n} = \frac{2 \cdot 2^n}{2^n \cdot (n+1)} = \frac{2}{n+1}.\]As \( n \to \infty \), \( \frac{2}{n+1} \to 0 \). Therefore, \( \lim_{n \to \infty} \frac{|p_{n+1}|}{|p_n|} = 0 \).
03

Prove \( \left\langle \frac{|p_{n+1}|}{|p_n|^\alpha} \right\rangle \) diverges for any \( \alpha > 1 \)

Consider \( \frac{|p_{n+1}|}{|p_n|^\alpha} = \left(\frac{2}{n+1}\right) \cdot \left(\frac{n!}{2^n}\right)^{\alpha - 1} \).Since we established in Step 2 that \( \frac{2}{n+1} \to 0 \) as \( n \to \infty \), our attention shifts to the second term: \( \left(\frac{n!}{2^n}\right)^{\alpha - 1} \).Because \( n! \) grows much faster than \( 2^n \) even at modest \( n \), for any \( \alpha > 1 \), this expression \ diverges towards infinity.Therefore, the sequence \( \left\langle \frac{|p_{n+1}|}{|p_n|^\alpha} \right\rangle \) diverges for any \( \alpha > 1 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limit of a sequence
A limit of a sequence refers to the value that the terms of a sequence approach as the index goes to infinity. Understanding this concept is pivotal in mathematics, especially in calculus and analysis.

To find the limit of a sequence, observe its behavior as the sequence progresses. Consider the sequence \( p_n = \frac{2^n}{n!} \). The expression \( n! \) or n factorial grows rapidly since it is a product of all positive integers up to \( n \). On the other hand, \( 2^n \) grows exponentially but at a slower pace compared to \( n! \). This means that \( \frac{2^n}{n!} \) becomes very small as \( n \) increases. Therefore, the limit of this sequence as \( n \to \infty \) is 0.

Practically, this tells us that no matter how large a term you consider in this sequence, it will eventually become negligible or very close to zero.
Factorials
Factorials are a mathematical function denoted by an exclamation mark (!), defined as the product of all positive integers up to a given number. For example, \( n! = n \times (n-1) \times (n-2) \times \ldots \times 1 \).

Factorials grow extremely fast. For instance, 5! equals 120, while 10! equals 3,628,800. This rapid growth makes factorials a significant factor in certain sequence behaviors, especially when compared to exponential functions like \( 2^n \).

This characteristic is crucial when evaluating sequences such as \( \frac{2^n}{n!} \). The denominator's growth outpaces the numerator significantly, leading the terms of the sequence to decrease rapidly towards zero.
Divergence of sequences
Divergence of sequences refers to when the terms of a sequence do not settle at a finite limit as the sequence progresses. Instead, the terms might increase indefinitely, decrease indefinitely, or oscillate without approaching a specific value.

In our given sequence, when exploring the expression \( \left\langle\frac{|p_{n+1}|}{|p_{n}|^\alpha}\right\rangle \) for any \( \alpha > 1 \), it shows divergent behavior. This happens because the growth rate of \( n! \) relative to \( 2^n \) is so significant that adding a power \( \alpha \) further accentuates the disparity.

Consequently, the terms do not converge to a single value and are considered divergent. Recognizing divergence can be as important as identifying convergence, especially when evaluating limits in calculus.
Mathematical proof techniques
Mathematical proof techniques are methods used to establish the validity of a statement or theorem. Proofs are essential in math to demonstrate the truth of propositions beyond doubt.

Several techniques can be used, such as:
  • Direct Proof: Prove directly from definitions and given information.
  • Contradiction: Assume the contrary of what you intend to prove and show that it leads to an inconsistency.
  • Induction: Prove a base case, and then prove a general case based on the assumption that it holds for a particular instance.
  • Comparison: Compare with sequences or series that have known behavior.
In the steps provided, the proofs utilize a direct analysis of the sequence terms and their limits. Recognizing how to process and simplify complex expressions is a valuable skill in crafting proofs. By leveraging growth rates and inequality transformations, these techniques lead to proving whether a sequence converges or diverges.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find \(\xi(x)\) as guaranteed by Taylor's theorem in the following situation. (a) \(f(x)=\cos (x), x_{0}=0, n=3, x=\pi\). (b) \(f(x)=e^{x}, x_{0}=0, n=3, x=\ln 4\). (c) \(f(x)-\ln (x), x_{0}-1, n-4, x-2\).

Find the fourth Taylor Polynomial for \(\ln x\) expanded about \(x_{0}=1\)

All of these equations are mathematically true. Nonetheless, floating point error causes some of them to be false according to Octave. Which ones? HINT: Use the boolean operator wo to check. For example, to check if \(\sin (0)=0,\) type \(\sin (0)==0\) into Octave. ans=1 means true (the two sides are equal according to Octave - no round-off error) and ans=0 means false (the two sides are not equal according to Octave round-off error). (a) \((2)(12)=9^{2}-4(9)-21\) (b) \(e^{3 \ln (2)}=8\) (c) \(\ln (10)=\ln (5)+\ln (2)\) (d) \(g\left(\frac{1+\sqrt{5}}{2}\right)=\frac{1+\sqrt{5}}{2}\) where \(g(x)=\sqrt[3]{x^{2}+x}\) (e) \(\lfloor 153465 / 3\rfloor=153465 / 3\) (f) \(3 \pi^{3}+7 \pi^{2}-2 \pi+8=((3 \pi+7) \pi-2) \pi+8\)

The Tower of Hanoi, part 1. The Tower of Hanoi is a game played with a number of different sized disks stacked on a pole in decreasing size, the largest on the bottom and the smallest on top. There are two other poles, initially with no disks on them. The goal is to move the entire stack of disks to one of the initially empty poles following two rules. You are allowed to move only one disk at a time from one pole to another. You may never place a disk upon a smaller one. [3] (a) Starting with a stack of three disks, what is the minimum number of moves it takes to complete the game? Answer this question with a number. (b) Starting with a stack of four disks, what is the minimum number of moves it takes to complete the game? i. Answer this question recursively. ii. Answer this question with a number based on your recursive answer.

Compute the absolute error and relative error in approximations of \(p\) by \(\bar{p}\). (a) \(p=\sqrt{2}, \bar{p}=1.414\) (b) \(p=10^{\pi}, \tilde{p}=1400\) (c) \(p=9 !, \tilde{p}=\sqrt{18 \pi}(9 / e)^{9}\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.