Chapter 4: Problem 3
( \(L^{1}\)-Bounded Martingales Need Not Be Uniformly Integrable). Consider \(X_{t}=\exp \left(B_{t}-t / 2\right)\) and show that \(X_{t}\) is a continuous martingale with \(E\left(\left|X_{t}\right|\right)=1\) for all \(t \geq 0\). Next, show that \(X_{t}\) converges with probability one to \(X=0\). Explain why this implies that \(X_{t}\) does not converge in \(L^{i}\) to \(X\) and explain why \(X_{t}\) is not uniformly integrable, despite being \(L^{1}\)-bounded.
Short Answer
Step by step solution
Show Continuity of the Martingale
Verify Martingale Property
Compute Expected Value
Show Convergence to Zero
Discuss Non-Convergence in L1
Explain Lack of Uniform Integrability
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Stochastic Processes
Common types of stochastic processes include:
- Discrete-time processes, where the index set is a countable set of time points.
- Continuous-time processes, where the index set is an interval on the real line.
- Markov processes, where the future state depends only on the current state and not on the history.
Brownian Motion
- The process starts at zero: \( B_0 = 0 \).
- For any time increment \( t \), the change \( B_t - B_s \) is normally distributed with mean zero and variance \( t - s \).
- Brownian motion is continuous at every point with probability one.
Uniform Integrability
- \( \sup_t E[ |X_t| ] < \infty \).
- For any \( \epsilon > 0 \), there exists \( \ a \) such that \( \ \sup_t E[ |X_t| 1_{|X_t| > a} ] < \epsilon \), where \( \ 1_{|X_t| > a} \) is the indicator function.