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Companies that design furniture for elementary school classrooms produce a variety of sizes for kids of different ages. Suppose the heights of kindergarten children can be described by a Normal model with a mean of 38.2 inches and standard deviation of 1.8 inches. a) What fraction of kindergarten kids should the company expect to be less than 3 feet tall? b) In what height interval should the company expect to find the middle \(80 \%\) of kindergartners? c) At least how tall are the biggest \(10 \%\) of kindergartners?

Short Answer

Expert verified
a) About 11.12% are less than 3 feet. b) Between 35.9 and 40.5 inches. c) At least 40.5 inches tall.

Step by step solution

01

Convert 3 feet to inches

Since 1 foot is equal to 12 inches, convert 3 feet to inches by multiplying: \( 3 \times 12 = 36 \) inches. The first task requires us to find the fraction of kindergarten kids who are less than 36 inches tall.
02

Calculate Z-score for 36 inches

Use the formula for the Z-score: \( Z = \frac{X - \mu}{\sigma} \), where \( X = 36 \) inches, \( \mu = 38.2 \) inches, and \( \sigma = 1.8 \) inches. Calculate \( Z = \frac{36 - 38.2}{1.8} = -1.22 \).
03

Find the probability for Z-score

Look up the Z-score of -1.22 in the standard normal distribution table. The probability of a Z-score less than -1.22 is approximately 0.1112. Thus, about 11.12% of kindergarten kids are expected to be shorter than 36 inches.
04

Define middle 80% for height interval

To find the middle 80% of kindergartners, identify the 10th percentile (P10) and the 90th percentile (P90) in the normal distribution table.
05

Calculate Z-scores for 10th and 90th percentiles

For the 10th percentile, the Z-score is approximately -1.28, and for the 90th percentile, it is approximately 1.28.
06

Convert Z-scores to height values

Use the formula \( X = Z \sigma + \mu \). For P10: \( X = -1.28 \times 1.8 + 38.2 = 35.904 \) inches. For P90: \( X = 1.28 \times 1.8 + 38.2 = 40.496 \) inches. Thus, the middle 80% falls between approximately 35.9 inches and 40.5 inches.
07

Find the height for the top 10%

Use the 90th percentile Z-score, which we found in Step 5 is 1.28, and convert it to a height: \( X = 1.28 \times 1.8 + 38.2 = 40.496 \) inches. Hence, the tallest 10% of kindergartners are at least 40.5 inches tall (rounding to the nearest tenth).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-score
The Z-score is a way of standardizing individual data points within a distribution so that you can compare them to the entire group. It's like asking where a single piece fits into the whole puzzle. You calculate it using the formula:
  • \( Z = \frac{X - \mu}{\sigma} \)
where \(X\) is the value you're examining, \(\mu\) is the mean of the distribution, and \(\sigma\) is the standard deviation.
Imagine you're at a fair measuring heights. If a child's height is exactly average, they'd have a Z-score of zero. If they're taller than average, their Z-score is positive, and if shorter, it's negative.
In our problem, the kindergarteners' height of 36 inches results in a Z-score of -1.22. This tells us that 36 inches is below average in our data set, helping the furniture company determine how this height compares with the rest of the kids.
Percentile
Percentiles are like mile markers in a race, providing a clear measurement of how one score stacks up against others. If you're in the 90th percentile, you're ahead of 90% of everyone else in whatever attribute is being measured.
To find specific percentiles, such as the 10th and 90th in our exercise, you convert these percentiles to Z-scores and then use them to find corresponding actual heights.
  • For example, the Z-score for the 10th percentile is about -1.28, and for the 90th percentile, it's about 1.28.
  • These Z-scores are then translated back into real-world measurements, providing the height values that separate groups of students.
This approach ensures that the furniture company can plan for the middle 80% of kids, by focusing on heights between approximately 35.9 inches and 40.5 inches.
Standard Deviation
Standard deviation reflects variation within a group. It tells us how spread out the numbers are in a dataset. When you're at a concert, think about how spread out the people are around you. Are they all close together, or scattered all over the place?
The formula is:
  • \( \sigma = \sqrt{\frac{1}{N}\sum_{i=1}^{N}(X_i - \mu)^2} \)
In our kindergarten example, the standard deviation is 1.8 inches, which means most children's heights are within this range from the average height of 38.2 inches.
The smaller the standard deviation, the more compact the heights are around the mean. With larger values, heights would significantly vary, making the design of universally fitting furniture more challenging.
Probability
Probability helps us understand the likelihood of events. It's a cornerstone of the normal distribution, which in turn helps make educated guesses about populations based on sample data. Much like predicting tomorrow's weather using patterns.
In our exercise, knowing the probability of a child being less than 36 inches helps the company gauge demand for certain sizes of furniture.
  • The Z-score calculated for 36 inches corresponds to a probability of approximately 11.12%, meaning about 11.12% of the kindergarteners are expected to be shorter than 3 feet.
  • These probability calculations guide the company's production process, enabling them to design and produce furniture that targets the sizes needed by the majority of children.
Using statistical models based on probability, companies can make decisions grounded in data rather than guesswork.

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