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Consider the Angus weights model \(N(1152,84)\) one last time. a) What weight represents the 40th percentile? b) What weight represents the 99th percentile? c) What's the IQR of the weights of these Angus steers?

Short Answer

Expert verified
a) Approximately 1131 kg; b) Approximately 1349 kg; c) Approximately 113 kg for the IQR.

Step by step solution

01

Identify the distribution parameters

The problem describes the distribution of Angus weights as normally distributed with a mean of 1152 (denoted as \(\mu = 1152\)) and a standard deviation of 84 (denoted as \(\sigma = 84\)). We will use these parameters to find the requested percentiles.
02

Find the 40th percentile weight

To find the 40th percentile of a normal distribution, we need to find the corresponding Z-score from a standard normal distribution table or calculator that represents the 40th percentile. The Z-score for the 40th percentile is approximately -0.253. We use the formula:\[ X = \mu + Z\sigma \]Substitute \(\mu = 1152\), \(\sigma = 84\), and \(Z = -0.253\): \[ X = 1152 + (-0.253)(84) \approx 1130.76 \]Therefore, the weight representing the 40th percentile is approximately 1131 kg.
03

Find the 99th percentile weight

Next, we find the Z-score corresponding to the 99th percentile, which is approximately 2.33. We apply the same formula:\[ X = \mu + Z\sigma \]Substitute \(\mu = 1152\), \(\sigma = 84\), and \(Z = 2.33\): \[ X = 1152 + (2.33)(84) \approx 1348.72 \]Thus, the weight representing the 99th percentile is approximately 1349 kg.
04

Compute the Interquartile Range (IQR)

The IQR is the difference between the 75th percentile (Q3) and the 25th percentile (Q1). First, we find the Z-score for the 25th percentile, which is approximately -0.675, and the 75th percentile, which is approximately 0.675. Using the formula:For the 25th percentile:\[ X_{25} = 1152 + (-0.675)(84) \approx 1095.32 \]For the 75th percentile:\[ X_{75} = 1152 + (0.675)(84) \approx 1208.68 \]Calculate the IQR:\[ \text{IQR} = X_{75} - X_{25} = 1208.68 - 1095.32 = 113.36 \]The Interquartile Range of the weights is approximately 113 kg.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Percentile Calculation
When dealing with a normal distribution, calculating percentiles provides a way to understand the relative standing of a value within the data set. The percentile defines the value below which a given percentage of observations in a group of observations falls. For instance, the 40th percentile is the weight below which 40% of the Angus steer weights fall.
  • To find any percentile value, first determine the corresponding Z-score from a standard normal distribution table or a calculator. For example, the 40th percentile corresponds to a Z-score of approximately -0.253.
  • Utilize the formula for converting a Z-score to an actual score in your specific distribution:
\[ X = \mu + Z\sigma \] This formula requires the mean ( \( \mu \) ) and the standard deviation ( \( \sigma \) ) of the distribution. Calculating the 40th percentile weight for Angus involves substituting \( \mu = 1152 \) and \( \sigma = 84 \), resulting in a weight of approximately 1131 kg.
Z-score
A Z-score is a statistic that provides insight into how far and in what direction, a data point deviates from the mean of the standard distribution. It is expressed in terms of standard deviations. This makes it easier to compare data points from different normal distributions.
  • A Z-score tells you how many standard deviations away an element is from the mean.
  • Positive Z-scores indicate values above the mean, while negative Z-scores indicate values below the mean.

Using Z-scores for Percentile Calculation

For finding percentiles in a normal distribution, the Z-score is indispensable. Let's consider finding the 99th percentile, which gives a Z-score of about 2.33. Using the conversion formula \( X = \mu + Z\sigma \), you can determine the actual weight value corresponding to this percentile.
The mean of the distribution is 1152 kg and the standard deviation is 84 kg, so for the 99th percentile, the calculation results in approximately 1349 kg.
Interquartile Range (IQR)
The interquartile range (IQR) is a measure of statistical dispersion and provides a robust indicator of spread. It represents the range in the middle 50% of a data set, calculated as the difference between the 75th percentile (Q3) and the 25th percentile (Q1).

Calculating the IQR

To find the IQR in a normal distribution:
  • Determine the Z-scores corresponding to Q1 and Q3. For this example, Q1 corresponds to a Z-score of -0.675, and Q3 corresponds to a Z-score of 0.675.
  • Calculate the actual weights for Q1 and Q3 using the distribution parameters.
The weight for Q1 is approximately 1095 kg, while for Q3, it is around 1209 kg. Hence, the IQR is \( 1208 - 1095 = 113 \) kg. The IQR assesses variation without the influence of outliers, making it a valuable tool for understanding data spread.
Mean and Standard Deviation
In any symmetric distribution like the normal distribution, the mean and standard deviation are essential for describing the data set. The mean indicates the central point of the distribution, while the standard deviation specifies how dispersed the data points are around the mean.
  • The mean ( \( \mu \) ) is the average of all data points. In our case, it's given as 1152 kg.
  • The standard deviation ( \( \sigma \) ) measures the average distance of each data point from the mean. For this scenario, it is 84 kg.

The Role in Z-score Calculation

Both the mean and standard deviation play a pivotal role in translating Z-scores into real-world values. By employing the formula \( X = \mu + Z\sigma \), where \( X \) is the score, we evaluate how individual data points compare to the average using Z-scores.
This formula enables converting the abstract Z-score into a meaningful context through the specific distribution's lens, assisting in tasks like percentile calculations and more.

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Most popular questions from this chapter

A popular band on tour played a series of concerts in large venues. They always drew a large crowd, averaging 21,359 fans. While the band did not announce (and probably never calculated) the standard deviation, which of these values do you think is most likely to be correct: \(20,200,2000,\) or 20,000 fans? Explain your choice.

A high school senior uses the Internet to get information on February temperatures in the town where he'll be going to college. He finds a website with some statistics, but they are given in degrees Celsius. The conversion formula is \(^{\circ} \mathrm{F}=9 / 5^{\circ} \mathrm{C}+32 .\) Determine the Fahrenheit equivalents for the summary information below. Maximum temperature \(=11^{\circ} \mathrm{C}\) Range \(=33^{\circ}\) Mean \(=1^{\circ} \quad\) Standard deviation \(=7^{\circ}\) Median \(=2^{\circ} \quad\) IQR \(=16^{\circ}\)

Based on the model \(N(1152,84)\) describing Angus steer weights, what are the cutoff values for a) the highest \(10 \%\) of the weights? b) the lowest \(20 \%\) of the weights? c) the middle \(40 \%\) of the weights?

A town's January high temperatures average \(36^{\circ} \mathrm{F}\) with a standard deviation of \(10^{\circ},\) while in July the mean high temperature is \(74^{\circ}\) and the standard deviation is \(8^{\circ} .\) In which month is it more unusual to have a day with a high temperature of \(55^{\circ} ?\) Explain.

Using \(N(1152,84),\) the Normal model for weights of Angus steers in Exercise \(17,\) what percent of steers weigh a) over 1250 pounds? b) under 1200 pounds? c) between 1000 and 1100 pounds?

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